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//Chapter 1
//Example 1.2
//Page 23
clear;
clc;
p=2.1*10^3;
//Calculation of pressure in pascals
printf("As we know that 10^2 cm= 1m and 10^5 dyne=1 Newton \n Thus the value of pressure is %.f Pascals",(p*10000)/(100000));
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