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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1316/CH1/EX1.2/example1_2.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '1316/CH1/EX1.2/example1_2.sce')
| -rw-r--r-- | 1316/CH1/EX1.2/example1_2.sce | 12 |
1 files changed, 12 insertions, 0 deletions
diff --git a/1316/CH1/EX1.2/example1_2.sce b/1316/CH1/EX1.2/example1_2.sce new file mode 100644 index 000000000..17860f9e9 --- /dev/null +++ b/1316/CH1/EX1.2/example1_2.sce @@ -0,0 +1,12 @@ +//Chapter 1
+//Example 1.2
+//Page 23
+
+clear;
+clc;
+
+p=2.1*10^3;
+
+//Calculation of pressure in pascals
+
+printf("As we know that 10^2 cm= 1m and 10^5 dyne=1 Newton \n Thus the value of pressure is %.f Pascals",(p*10000)/(100000));
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