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+//Chapter 1
+//Example 1.2
+//Page 23
+
+clear;
+clc;
+
+p=2.1*10^3;
+
+//Calculation of pressure in pascals
+
+printf("As we know that 10^2 cm= 1m and 10^5 dyne=1 Newton \n Thus the value of pressure is %.f Pascals",(p*10000)/(100000));