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+//Calculate the value of Change in Gibbs Energy (delG) for melting of ice at 0 degree celcious, 10 degree celcious and minus 10 degree celcious
+
+//Example 6.2
+
+clc;
+
+clear;
+
+delH=6.01;  //Change in Enthalpy in kJ mol^-1
+
+T1=273;  //Temperature of ice in K
+
+delS=22.0;  //Change in Entropy in J K^-1
+
+delG1=delH-(T1*delS/1000);  //Change in Gibbs Energy in kJ
+
+printf("(a)Change in Gibbs Energy at Zero degree celcious = %.0f ",delG1);
+
+T2=283;  //Temperature of ice in K
+
+delG2=delH-(T2*delS/1000);  //Change in Gibbs Energy in kJ
+
+printf("\n(b)Change in Gibbs Energy at Ten degree celcious = %.2f kJ",delG2);
+
+T3=263;  //Temperature of ice in K
+
+delG3=delH-(T3*delS/1000);  //Change in Gibbs Energy in kJ
+
+printf("\n(c)Change in Gibbs Energy at minus Ten degree celcious= %.2f kJ",delG3);