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//Calculate the value of Change in Gibbs Energy (delG) for melting of ice at 0 degree celcious, 10 degree celcious and minus 10 degree celcious
//Example 6.2
clc;
clear;
delH=6.01; //Change in Enthalpy in kJ mol^-1
T1=273; //Temperature of ice in K
delS=22.0; //Change in Entropy in J K^-1
delG1=delH-(T1*delS/1000); //Change in Gibbs Energy in kJ
printf("(a)Change in Gibbs Energy at Zero degree celcious = %.0f ",delG1);
T2=283; //Temperature of ice in K
delG2=delH-(T2*delS/1000); //Change in Gibbs Energy in kJ
printf("\n(b)Change in Gibbs Energy at Ten degree celcious = %.2f kJ",delG2);
T3=263; //Temperature of ice in K
delG3=delH-(T3*delS/1000); //Change in Gibbs Energy in kJ
printf("\n(c)Change in Gibbs Energy at minus Ten degree celcious= %.2f kJ",delG3);
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