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+// Problem 8.15,Page no.216
+
+clc;clear;
+close;
+
+alpha=30 //degree //helix angle
+dell=2.3*10**-2 //m //Vertical displacement
+W=40 //N //Axial Load
+d=6*10**-3 //steel rod diameter
+E=200*10**9 //Pa 
+G=80*10**9 //Pa 
+
+//Calculations
+
+//from equation of deflection of the spring under the Load we get
+//R**3*n=8.49*10**-4 
+
+//Let R**3*n=X
+X=8.49*10**-4  //Equation 1
+
+//from equation of angular rotation
+//R**2*n=8.1*10**-3
+
+//Let R**2*n=Y
+Y=8.1*10**-3   //Equation 2
+
+//After dividing equation 1 by equation 2 we get R 
+//Let Z=R
+
+Z=X*Y**-1
+R=Z*10**2 //cm //Mean Radius
+
+//Result
+printf("Mean Radius of Open coiled spring of helix angle is %.2f",R);printf(" cm")