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// Problem 8.15,Page no.216
clc;clear;
close;
alpha=30 //degree //helix angle
dell=2.3*10**-2 //m //Vertical displacement
W=40 //N //Axial Load
d=6*10**-3 //steel rod diameter
E=200*10**9 //Pa
G=80*10**9 //Pa
//Calculations
//from equation of deflection of the spring under the Load we get
//R**3*n=8.49*10**-4
//Let R**3*n=X
X=8.49*10**-4 //Equation 1
//from equation of angular rotation
//R**2*n=8.1*10**-3
//Let R**2*n=Y
Y=8.1*10**-3 //Equation 2
//After dividing equation 1 by equation 2 we get R
//Let Z=R
Z=X*Y**-1
R=Z*10**2 //cm //Mean Radius
//Result
printf("Mean Radius of Open coiled spring of helix angle is %.2f",R);printf(" cm")
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