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+// Problem 11.3,Page no.274
+
+clc;clear;
+close;
+
+A=300 //cm**2 //Area of column
+e=5 //cm //eccentricity
+
+//Calculations
+
+//sigma_d=P*A**-1  //Direct compressive stress
+//M=P*e //Bending Moment
+Z=((20**4-10**4)*(6*20)**-1) //cm**3 //Section modulus
+
+//sigma_b=M*Z**-1=P*250**-1 
+
+//Now sigma_d+sigma_b=60*10**2
+
+//P*300**-1+P*250**-1=6000
+
+//After simplifying we get
+P_1=6000*300*250*550**-1 //N //Load
+
+//sigma_b-sigma_d=300 
+
+P_2=300*300*250*50**-1 //N //Load 
+
+//Result
+printf("The maximum load column can carry %.2f",P_2);printf(" N")