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// Problem 11.3,Page no.274
clc;clear;
close;
A=300 //cm**2 //Area of column
e=5 //cm //eccentricity
//Calculations
//sigma_d=P*A**-1 //Direct compressive stress
//M=P*e //Bending Moment
Z=((20**4-10**4)*(6*20)**-1) //cm**3 //Section modulus
//sigma_b=M*Z**-1=P*250**-1
//Now sigma_d+sigma_b=60*10**2
//P*300**-1+P*250**-1=6000
//After simplifying we get
P_1=6000*300*250*550**-1 //N //Load
//sigma_b-sigma_d=300
P_2=300*300*250*50**-1 //N //Load
//Result
printf("The maximum load column can carry %.2f",P_2);printf(" N")
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