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-rw-r--r--3681/CH6/EX6.1/Ans6_1.PNGbin0 -> 7358 bytes
-rw-r--r--3681/CH6/EX6.1/Ex6_1.sce22
-rw-r--r--3681/CH6/EX6.5/Ans6_5.PNGbin0 -> 4931 bytes
-rw-r--r--3681/CH6/EX6.5/Ex6_5.sce13
-rw-r--r--3681/CH6/EX6.6/Ans6_6.PNGbin0 -> 5660 bytes
-rw-r--r--3681/CH6/EX6.6/Ex6_6.sce11
-rw-r--r--3681/CH6/EX6.8/Ans6_8.PNGbin0 -> 8519 bytes
-rw-r--r--3681/CH6/EX6.8/Ex6_8.sce23
-rw-r--r--3681/CH6/EX6.9/Ans6_9.PNGbin0 -> 5255 bytes
-rw-r--r--3681/CH6/EX6.9/Ex6_9.sce21
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diff --git a/3681/CH6/EX6.1/Ans6_1.PNG b/3681/CH6/EX6.1/Ans6_1.PNG
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diff --git a/3681/CH6/EX6.1/Ex6_1.sce b/3681/CH6/EX6.1/Ex6_1.sce
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+// Calculating the specific electric and specific magnetic loading
+clc;
+disp('Example 6.1, Page No. = 6.10')
+// Given Data
+P = 350;// Power rating (in kW)
+E = 500;// Voltage (in V)
+rpm = 450;
+p = 6;// Number of poles
+a = 6;// Since a=p for lap winding
+Z = 660;// Number of conductors
+L = 0.32;// Core length (in meter)
+D = 0.87;// Armature diameter (in meter)
+// Calculation of the specific electric loading
+Ia = P*1000/E;// Armature current (in A)
+Iz = Ia/a;// Current in each conductor (in A)
+ac = Iz*Z/(%pi*D);// Specific electric loading
+disp(ac,'Specific electric loading (ampere conductors per meter)=');
+// Calculation of the specific magnetic loading
+F = E*a/(Z*rpm/60*p);// Flux per pole (in Wb)
+Bac = p*F/(%pi*D*L);// specific magnetic loading
+disp(Bac,'Specific magnetic loading (Wb per meter square)=');
+//in book answers are 28200 (ampere conductors per meter) and 0.693 (Wb per meter square) respectively. The answers vary due to round off error
diff --git a/3681/CH6/EX6.5/Ans6_5.PNG b/3681/CH6/EX6.5/Ans6_5.PNG
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diff --git a/3681/CH6/EX6.5/Ex6_5.sce b/3681/CH6/EX6.5/Ex6_5.sce
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+// Calculating the power developed by the armature of motor
+clc;
+disp('Example 6.5, Page No. = 6.12')
+// Given Data
+P = 125;// Power rating (in W)
+E = 230;// Voltage (in V)
+rpm = 5000;
+// Calculation of the power developed by the armature
+Losses_total = P;// Total losses (in W)
+Losses_constant = P/3;// Constant losses (in W). Since the sum of iron, friction and windage losses is approximately 1/3 of total losses
+Pa = Losses_total+Losses_constant;// Power developed by the armature (in W)
+disp(Pa,'Power developed by the armature (W)=');
+//in book answer is 167 (W). The answers vary due to round off error
diff --git a/3681/CH6/EX6.6/Ans6_6.PNG b/3681/CH6/EX6.6/Ans6_6.PNG
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diff --git a/3681/CH6/EX6.6/Ex6_6.sce b/3681/CH6/EX6.6/Ex6_6.sce
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+// Calculating the limiting value of specific magnetic loading
+clc;
+disp('Example 6.6, Page No. = 6.12')
+// Given Data
+Bt = 2.0;// Maximum flux density in the armature (in Wb per meter square)
+R = 0.7;// Ratio of pole arc to pole pitch
+Wt_ys = 0.4;// Ratio of minimum width of tooth to slot pitch
+// Calculation of the limiting value of specific magnetic loading
+Bav = R*Wt_ys*Bt;// Limiting value of specific magnetic loading (in W per meter square)
+disp(Bav,'Limiting value of specific magnetic loading (W per meter square)=');
+//in book answer is 0.56 (W per meter square). The answers vary due to round off error
diff --git a/3681/CH6/EX6.8/Ans6_8.PNG b/3681/CH6/EX6.8/Ans6_8.PNG
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diff --git a/3681/CH6/EX6.8/Ex6_8.sce b/3681/CH6/EX6.8/Ex6_8.sce
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+// Calculating the maximum permissible specific electric loading
+clc;
+disp('Example 6.8, Page No. = 6.13')
+// Given Data
+p_20 = 1.734*10^(-8);// Resistivity of copper at 20 degree celsius (in ohm*meter)
+alpha = 0.00393;// Resistance temperature co-efficient of copper at 20 degree celsius (in per degree celsius)
+s = 3.5;// Current density (in A per mm square)
+c = 0.03;// Cooling co-efficient
+Tm_ambient = 40;// Maximum ambient temperature (in degree celsius)
+Tm_rise_A = 50;// Maximum temperature rise for Class A insulation (in degree celsius)
+Tm_rise_E = 65;// Maximum temperature rise for Class E insulation (in degree celsius)
+// Calculation of the maximum permissible specific electric loading
+//for Class A insulation
+T_A = Tm_ambient+Tm_rise_A;// Operating temperature of copper conductors (in degree celsius)
+p = p_20*(1+alpha*(T_A-20));// Resistivity at operating temperature (in ohm*meter)
+ac = Tm_rise_A/(p*s*10^(6)*c);// Maximum permissible specific electric loading
+disp(ac,'Maximum allowable specific electric loading (ampere conductors per meter)=');
+T_E = Tm_ambient+Tm_rise_E;// Operating temperature of copper conductors (in degree celsius)
+//for Class E insulation
+p = p_20*(1+alpha*(T_E-20));// Resistivity at operating temperature (in ohm*meter)
+ac = Tm_rise_E/(p*s*10^(6)*c);// Maximum permissible specific electric loading
+disp(ac,'Maximum allowable specific electric loading (ampere conductors per meter)=');
+//in book answers are 21600 (ampere conductors per meter) and 26700 (ampere conductors per meter) respectively. The answers vary due to round off error
diff --git a/3681/CH6/EX6.9/Ans6_9.PNG b/3681/CH6/EX6.9/Ans6_9.PNG
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diff --git a/3681/CH6/EX6.9/Ex6_9.sce b/3681/CH6/EX6.9/Ex6_9.sce
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+// Calculating the specific electric loading
+clc;
+disp('Example 6.9, Page No. = 6.13')
+// Given Data
+Pc = 1000;// Core loss (in W)
+R = 0.025;// Armature resistance (in ohm)
+l = 230;// Specific loss dissipation (in W per degree celsius per meter square)
+a = 2;// Since a=z for lap winding
+Z = 270;// Number of conductors
+L = 0.25;// Core length (in meter)
+D = 0.25;// Armature diameter (in meter)
+T = 40;// Temperature rise (degree celsius)
+// Calculation of the specific electric loading
+c = 1/l;// Cooling co-efficient
+S = %pi*D*L;// Dissipation surface (in meter square)
+Q = S*T/c;// Maximum allowable pwer dissipation from armature surface
+Ia = ((Q-Pc)/R)^(1/2);// Armature current (in Ampere)
+Iz = Ia/a;// Current in each conductor (in A)
+ac = Iz*Z/(%pi*D);// Specific electric loading
+disp(ac,'Specific electric loading (ampere conductors per meter)=');
+//in book answer is 31000 (ampere conductors per meter). The answers vary due to round off error