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+//Tested on Windows 7 Ultimate 32-bit
+//Chapter 6 Single Staje BJT Amplifiers Pg no. 184 and 185
+clear;
+clc;
+
+//Given Data
+//Figure 6.7
+
+VCC=20;//collector supply voltage in volts
+RC=1.5D3;//collector resistance in ohms
+RE=1.8D3;//emitter resistance in ohms
+R1=8.2D3;//divider network resistance R1 in ohms
+R2=3.9D3;//divider network resistance R2 in ohms
+VBE=0.7;//forward voltage drop of emitter diode in volts
+
+//Solution
+
+//For DC load line
+VCEd=0:VCC;//as for load line maximum VCE is at IC=0 mA ie. VCE=VCC
+ICd=(VCC-VCEd)/(RC+RE)*1000;//equation for DC load line
+VB=VCC*R2/(R1+R2);//base to ground voltage in volts
+VE=VB-VBE;//emitter to ground voltage in volts
+IE=VE/RE;//emitter current in milli-amperes
+IC=IE;//collector current is approximately equal to emitter current
+VCE=VCC-IC*(RC+RE);//collector to emitter voltage in volts
+
+//For AC load line
+m=-1/RC;//slope of AC load line i.e. ΔIC/ΔVCE
+c=IC-m*VCE;//load line passes through Q point
+ICa=(m*VCEd+c)*1000;//AC load line equation
+
+plot2d(VCEd,[ICd' ICa'],[1,2],leg="DC LOAD LINE@AC LOAD LINE",rect=[0,0,21,7]);
+plot2d(VCE,IC*1000,-1);
+xlabel("VCE (in Volts)");
+ylabel("IC (in mA)");
+xstring(VCE+.1,IC*1000+.1,"Q point");
+xstring(VCC,.1,"R");
+xstring(.1,VCC/(RC+RE)*1000,"P");
+title("LOAD LINES FOR EXAMPLE 6.1")