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+//Chapter-9,Example 9,Page 221
+clc();
+close();
+
+strength =0.05 //strength of CH3COOH
+
+Ka=1.8*10^-5
+
+// CH3COOH <---> CH3COO- + H+
+//intially = 0.05 0 0
+//dissolution a
+//at equilibrium= 0.05(1-a) 0.05*a 0.05*a
+//Ka =(0.05*a*0.05*a)/(0.05(1-a))
+//Ka=0.05*a^2 a=negligible 1-a=1
+
+a=sqrt(Ka/strength)
+
+printf('the degree of dissolution is %.4f ',a)