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diff --git a/2465/CH9/EX9.9/Example_9.sce b/2465/CH9/EX9.9/Example_9.sce
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+//Chapter-9,Example 9,Page 221
+clc();
+close();
+
+strength =0.05   //strength of CH3COOH
+
+Ka=1.8*10^-5
+
+//              CH3COOH <---> CH3COO- +  H+
+//intially  =     0.05          0        0
+//dissolution                   a 
+//at equilibrium= 0.05(1-a)   0.05*a   0.05*a
+//Ka =(0.05*a*0.05*a)/(0.05(1-a))
+//Ka=0.05*a^2      a=negligible   1-a=1
+
+a=sqrt(Ka/strength)
+
+printf('the degree of dissolution is %.4f ',a)