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//Chapter-9,Example 9,Page 221
clc();
close();
strength =0.05 //strength of CH3COOH
Ka=1.8*10^-5
// CH3COOH <---> CH3COO- + H+
//intially = 0.05 0 0
//dissolution a
//at equilibrium= 0.05(1-a) 0.05*a 0.05*a
//Ka =(0.05*a*0.05*a)/(0.05(1-a))
//Ka=0.05*a^2 a=negligible 1-a=1
a=sqrt(Ka/strength)
printf('the degree of dissolution is %.4f ',a)
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