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+//Example No. 3.10
+clc;
+clear;
+close;
+format('v',6);
+
+//Given Data : 
+MotorSpeed=1440;//rpm
+Jmotor=0.4;//Kg-m^2
+Jdc_load=0.6;//Kg-m^2(Inertia directly coupled load)
+w_tl=100;//kg(weight of transratioonal load)
+F_res=1.2;//N/Kg(Friction resistance for translational load)
+v=10;//m/s
+T_RotLoad=1.5;//N-m
+g=9.81;//gravity constant
+
+//Solution : 
+MotorSpeed=MotorSpeed*2*%pi/60;//rad/sec
+F_horz=w_tl*F_res;//N(horizontal force of translational load)
+mass=w_tl*g;//N
+J=Jmotor+Jdc_load+mass*(v/MotorSpeed)^2;//Kg-m^2
+disp(J,"Moment of Inertia at motor shaft in Kg-m^2 :  ");
+T=T_RotLoad+F_horz*v/MotorSpeed;//N-m
+disp(T,"Torque at motor shaft in N-m : ");