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+//Example No. 3.10

+clc;

+clear;

+close;

+format('v',6);

+

+//Given Data : 

+MotorSpeed=1440;//rpm

+Jmotor=0.4;//Kg-m^2

+Jdc_load=0.6;//Kg-m^2(Inertia directly coupled load)

+w_tl=100;//kg(weight of transratioonal load)

+F_res=1.2;//N/Kg(Friction resistance for translational load)

+v=10;//m/s

+T_RotLoad=1.5;//N-m

+g=9.81;//gravity constant

+

+//Solution : 

+MotorSpeed=MotorSpeed*2*%pi/60;//rad/sec

+F_horz=w_tl*F_res;//N(horizontal force of translational load)

+mass=w_tl*g;//N

+J=Jmotor+Jdc_load+mass*(v/MotorSpeed)^2;//Kg-m^2

+disp(J,"Moment of Inertia at motor shaft in Kg-m^2 :  ");

+T=T_RotLoad+F_horz*v/MotorSpeed;//N-m

+disp(T,"Torque at motor shaft in N-m : ");