2 files changed, 18 insertions, 0 deletions
diff --git a/1574/CH8/EX8.4/Result_of_Chapter_8_Ex8_4.JPG b/1574/CH8/EX8.4/Result_of_Chapter_8_Ex8_4.JPG
new file mode 100755
index 000000000..df8873a62
--- /dev/null
+++ b/1574/CH8/EX8.4/Result_of_Chapter_8_Ex8_4.JPG
diff --git a/1574/CH8/EX8.4/TL_Ex_8_4.sce b/1574/CH8/EX8.4/TL_Ex_8_4.sce
new file mode 100755
index 000000000..c2c702932
--- /dev/null
+++ b/1574/CH8/EX8.4/TL_Ex_8_4.sce
@@ -0,0 +1,18 @@
+clc
+//Chapter8
+//Example8.4, page no 316
+//Given
+d=0.7// distance between two insertions
+Ld_m= (80e-3)*(10/7)//Loading coil inductance
+//disp(Ld_m)
+Rd_m=100/7//Loading coil resistance
+//disp(Rd_m)
+R=20+Rd_m//Line resistance 
+L=Ld_m// Line inductance
+C=0.05e-6// Line Capacitance
+alfa=0.5*R*sqrt(C/L)//Attenuation Constant
+//
+fc=(%pi*d*sqrt(L*C))^-1//cut off freq
+mprintf('The atenuation constant is %f nepers/mile\nThe Cut-off Freq is %d KHz',alfa,fc*1e-3)
+
+// Note :  There are some calculation errors in the solution presented in the book