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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1574/CH8/EX8.4 | |
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diff --git a/1574/CH8/EX8.4/Result_of_Chapter_8_Ex8_4.JPG b/1574/CH8/EX8.4/Result_of_Chapter_8_Ex8_4.JPG Binary files differnew file mode 100755 index 000000000..df8873a62 --- /dev/null +++ b/1574/CH8/EX8.4/Result_of_Chapter_8_Ex8_4.JPG diff --git a/1574/CH8/EX8.4/TL_Ex_8_4.sce b/1574/CH8/EX8.4/TL_Ex_8_4.sce new file mode 100755 index 000000000..c2c702932 --- /dev/null +++ b/1574/CH8/EX8.4/TL_Ex_8_4.sce @@ -0,0 +1,18 @@ +clc
+//Chapter8
+//Example8.4, page no 316
+//Given
+d=0.7// distance between two insertions
+Ld_m= (80e-3)*(10/7)//Loading coil inductance
+//disp(Ld_m)
+Rd_m=100/7//Loading coil resistance
+//disp(Rd_m)
+R=20+Rd_m//Line resistance
+L=Ld_m// Line inductance
+C=0.05e-6// Line Capacitance
+alfa=0.5*R*sqrt(C/L)//Attenuation Constant
+//
+fc=(%pi*d*sqrt(L*C))^-1//cut off freq
+mprintf('The atenuation constant is %f nepers/mile\nThe Cut-off Freq is %d KHz',alfa,fc*1e-3)
+
+// Note : There are some calculation errors in the solution presented in the book
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