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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3751/CH6/EX6.6 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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| -rw-r--r-- | 3751/CH6/EX6.6/Ex6_6.sce | 40 |
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diff --git a/3751/CH6/EX6.6/Ex6_6.sce b/3751/CH6/EX6.6/Ex6_6.sce new file mode 100644 index 000000000..b89471bc5 --- /dev/null +++ b/3751/CH6/EX6.6/Ex6_6.sce @@ -0,0 +1,40 @@ +//Fluid System By Shiv Kumar
+//Chapter 6 - Kaplan and Propeller Turbines
+//Example 6.6
+//To Find (a)Diameter of Runner (b)Speed of Turbine (c)Specific Speed of the turbine
+
+ clc
+ clear
+
+//Given:
+ P=9100; //Shaft Power, KW
+ H=5.6; //Net Available Head, m
+ Ku=2.09; //Speed Ratio
+ Kf=0.68; //Flow Ratio
+ eta_0=86/100; //Overall Efficiency
+ dbyD=1/3; //Ratio of Diameters of Hub and Runner
+
+//Data Required:
+ rho=1000; //Density of Water, Kg/m^3
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+//Computations
+
+ Q=P*10^3/(rho*g*H*eta_0); //Discharge, m^3/s
+
+
+ d=sqrt(Q/((%pi/4)*Kf*sqrt(2*g*H)*(dbyD^-2-1))); // Diameter of Hub ,m
+ //(i) Diameter of Runner ,D
+ D=d/dbyD; //m
+
+ //(ii) Speed of Turbine,N
+ N=Ku*60*sqrt(2*g*H)/(%pi*D); // rpm
+//(iii) Specific Speed of Turbine, Ns
+ Ns=N*(P)^(1/2)/(H^(5/4)); // SI Units
+
+
+//Results
+ printf("(i)Diameter of Runner , D=%.2f m\n",D)
+ printf("(ii)Speed of Turbine, N =%.2f rpm\n",N) //The answer vary due to round off error
+ printf("(iii) Specific Speed of Turbine, Ns =%.2f (SI Units)\n",Ns) //The answer provided in the textbook is wrong(Due to error in N)
+
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