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+//Fluid System By Shiv Kumar
+//Chapter 6 - Kaplan and Propeller Turbines
+//Example 6.6
+//To Find (a)Diameter of Runner  (b)Speed of Turbine (c)Specific Speed of the turbine
+
+      clc
+      clear
+
+//Given:
+   P=9100;   //Shaft Power, KW
+   H=5.6;   //Net Available Head, m
+   Ku=2.09;       //Speed Ratio
+   Kf=0.68;     //Flow Ratio
+   eta_0=86/100;  //Overall Efficiency
+   dbyD=1/3;   //Ratio of Diameters of Hub and Runner
+   
+//Data Required:
+   rho=1000;   //Density of Water, Kg/m^3
+   g=9.81;     //Acceleration due to gravity, m/s^2
+
+//Computations
+
+     Q=P*10^3/(rho*g*H*eta_0);   //Discharge, m^3/s
+
+
+      d=sqrt(Q/((%pi/4)*Kf*sqrt(2*g*H)*(dbyD^-2-1)));   // Diameter of Hub ,m
+  //(i) Diameter of Runner ,D
+      D=d/dbyD;  //m
+  
+  //(ii) Speed of Turbine,N
+     N=Ku*60*sqrt(2*g*H)/(%pi*D);  // rpm
+//(iii) Specific Speed of Turbine, Ns
+     Ns=N*(P)^(1/2)/(H^(5/4));   // SI Units
+
+
+//Results 
+    printf("(i)Diameter of Runner , D=%.2f m\n",D)
+    printf("(ii)Speed of Turbine, N =%.2f rpm\n",N)    //The answer vary due to round off error
+    printf("(iii) Specific Speed of Turbine, Ns =%.2f (SI Units)\n",Ns)    //The answer provided in the textbook is wrong(Due to error in N)
+