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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3751/CH11/EX11.25/Ex11_25.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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| -rw-r--r-- | 3751/CH11/EX11.25/Ex11_25.sce | 32 |
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diff --git a/3751/CH11/EX11.25/Ex11_25.sce b/3751/CH11/EX11.25/Ex11_25.sce new file mode 100644 index 000000000..cf6b0ffeb --- /dev/null +++ b/3751/CH11/EX11.25/Ex11_25.sce @@ -0,0 +1,32 @@ +//Fluid Systems - By - Shiv Kumar +//Chapter 11 - Centrifugal Pumps +//Example 11.25 +//To Find the Discharge and Head of the Pump at Condition '2' and '3' and Compare the Power Consumed in all the cases. + + clc + clear + +//Given Data:- + //At Condition '1' + N1=750; //Speed, rpm + Q1=60; //Discharge, l/s + H1=20; //Head, m + + //At Condition '2' + N2=1200; //Speed, rpm + + //At Condition '3' + N3=4200; //Speed, rpm + +//Computations:- + Q2=Q1*(N2/N1); // l/s + H2=H1*(N2/N1)^2; //m + Q3=Q1*(N3/N1); // l/s + H3=H1*(N3/N1)^2; //m + +//Results:- + printf("At Condition -2 Discharge, Q2=%.f l/s and Head, H2=%.1f m\n",Q2,H2) + printf(" At Condition -3 Discharge, Q3=%.f l/s and Head, H3=%.1f m\n",Q3,H3) + printf(" P1: P2 : P3 = 1 : %.2f : %.2f ",Q2*H2/(Q1*H1),Q3*H3/(Q1*H1)) //The answer vary due to round off error + + |