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//Fluid Systems - By - Shiv Kumar
//Chapter 11 - Centrifugal Pumps
//Example 11.25
//To Find the Discharge and Head of the Pump at Condition '2' and '3' and Compare the Power Consumed in all the cases.
clc
clear
//Given Data:-
//At Condition '1'
N1=750; //Speed, rpm
Q1=60; //Discharge, l/s
H1=20; //Head, m
//At Condition '2'
N2=1200; //Speed, rpm
//At Condition '3'
N3=4200; //Speed, rpm
//Computations:-
Q2=Q1*(N2/N1); // l/s
H2=H1*(N2/N1)^2; //m
Q3=Q1*(N3/N1); // l/s
H3=H1*(N3/N1)^2; //m
//Results:-
printf("At Condition -2 Discharge, Q2=%.f l/s and Head, H2=%.1f m\n",Q2,H2)
printf(" At Condition -3 Discharge, Q3=%.f l/s and Head, H3=%.1f m\n",Q3,H3)
printf(" P1: P2 : P3 = 1 : %.2f : %.2f ",Q2*H2/(Q1*H1),Q3*H3/(Q1*H1)) //The answer vary due to round off error
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