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+//Fluid Systems - By - Shiv Kumar
+//Chapter 11- Centrifugal Pumps
+//Example 11.13
+//To Find         (i)The Discharge of the Pump          (ii)The Pressure at Suction and Delivery side of the Pump.
+
+       clc
+        clear
+
+//Given Data:-
+         h_st=35;      //Static Head, m
+         h_s=4;       //Suction Head, m         
+         D=150;         //Diameter of Pipes, mm
+         Ds=D;        //Diameter of Suction Pipe, mm
+         Dd=D;        //Diameter of Delivery Pipe, mm
+         h_fs=1.6;      //Head loss in Suction pipe,  m
+         h_fd=6.5;     //Head loss in Delivery Pipe,  m
+         Do=380;      //Diameter of Impeller at Outlet, mm
+         bo=25;        //Width of Impeller at Outlet, mm
+         N=1200;        //Speed, rpm
+         beta_o=35;         //Ezxit Blade Angle, degrees
+         eta_man=80/100;       //Manometric Efficiency        
+
+
+//Data Used:-
+         g=9.81;        //Acceleration due to gravity, m/s^2
+
+//Computations:-
+          Do=Do/1000;        //m
+          D=D/1000;         //m
+          Ds=Ds/1000;       //m
+          Dd=Dd/1000;      //m
+          bo=bo/1000;     //m
+
+         Hm=h_st+h_fs+h_fd;      // Manometric Head, m
+          uo=%pi*Do*N/60;      // Tangential velocity of Impeller at Outlet, m/s
+          Vwo=g*Hm/(uo*eta_man);       //m/s
+          Vfo=(uo-Vwo)*tand(beta_o);        //m/s
+
+     //(i)The Discharge of the Pump, Q
+          Q=%pi*Do*bo*Vfo*1000;       //litres/s
+
+    // (ii)The Pressure at Suction and Delivery side of the Pump
+   
+         A=(%pi/4)*D^2;        //m^2
+         Vd=Q*10^-3/A;       //m/s
+         Vs=Vd;        //m/s
+         Hs=h_s+h_fs+Vs^2/(2*g);        //Pressure on Suction Side, m of water
+         h_d=h_st-h_s;      //m
+         Hd=h_d+h_fd+Vd^2/(2*g);        //Pressure on Delivery Side, m of water
+         
+
+//Result:-
+      printf(" (i)The Discharge of the Pump, Q =%.2f litres/s\n",Q)  //The answer vary due to round off error 
+      printf(" (ii) Pressure on Suction Side, Hs =-%.3f m of water \n",Hs)  //The answer vary due to round off error
+     printf("      Pressure on Delivery Side, Hd =%.2f m of water \n",Hd)  //The answer vary due to round off error
+