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diff --git a/3472/CH46/EX46.1/Example46_1.sce b/3472/CH46/EX46.1/Example46_1.sce
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+// A Texbook on POWER SYSTEM ENGINEERING

+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar

+// DHANPAT RAI & Co.

+// SECOND EDITION 

+

+// PART IV : UTILIZATION AND TRACTION

+// CHAPTER 8: BRAKING

+

+// EXAMPLE : 8.1 :

+// Page number 806

+clear ; clc ; close ; // Clear the work space and console

+

+// Given data

+V = 525.0    // Voltage of motor(V)

+I_1 = 50.0   // Current(A)

+T_1 = 216.0  // Torque(N-m)

+I_2 = 70.0   // Current(A)

+T_2 = 344.0  // Torque(N-m)

+I_3 = 80.0   // Current(A)

+T_3 = 422.0  // Torque(N-m)

+I_4 = 90.0   // Current(A)

+T_4 = 500.0  // Torque(N-m)

+V_m = 26.0   // Speed(kmph)

+R_b = 5.5    // Resistance of braking rheostat(ohm)

+R_m = 0.5    // Resistance of motor(ohm)

+

+// Calculations

+I = 75.0                // Current drawn at 26 kmph(A)

+back_emf = V-I*R_m      // Back emf of the motor(V)

+R_t = R_b+R_m           // Total resistance(ohm)

+I_del = back_emf/R_t    // Current delivered(A)

+T_b = T_3*I_del/I_3     // Braking torque(N-m)

+

+// Results

+disp("PART IV - EXAMPLE : 8.1 : SOLUTION :-")

+printf("\nBraking torque = %.f N-m", T_b)

diff --git a/3472/CH46/EX46.2/Example46_2.sce b/3472/CH46/EX46.2/Example46_2.sce
new file mode 100644
index 000000000..e7b2523b3
--- /dev/null
+++ b/3472/CH46/EX46.2/Example46_2.sce
@@ -0,0 +1,35 @@
+// A Texbook on POWER SYSTEM ENGINEERING

+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar

+// DHANPAT RAI & Co.

+// SECOND EDITION 

+

+// PART IV : UTILIZATION AND TRACTION

+// CHAPTER 8: BRAKING

+

+// EXAMPLE : 8.2 :

+// Page number 806

+clear ; clc ; close ; // Clear the work space and console

+

+// Given data

+V = 525.0      // Voltage of motor(V)

+I_1 = 50.0     // Current(A)

+N_1 = 1200.0   // Speed(rpm)

+I_2 = 100.0    // Current(A)

+N_2 = 950.0    // Speed(rpm)

+I_3 = 150.0    // Current(A)

+N_3 = 840.0    // Speed(rpm)

+I_4 = 200.0    // Current(A)

+N_4 = 745.0    // Speed(rpm)

+N = 1000.0     // Speed opearting(rpm)

+R = 3.0        // Resistance(ohm)

+R_m = 0.5      // Resistance of motor(ohm)

+

+// Calculations

+I = 85.0                // Current drawn at 1000 rpm(A)

+back_emf = V-I*R_m      // Back emf of the motor(V)

+R_t = R+R_m             // Total resistance(ohm)

+I_del = back_emf/R_t    // Current delivered(A)

+

+// Results

+disp("PART IV - EXAMPLE : 8.2 : SOLUTION :-")

+printf("\nCurrent delivered when motor works as generator = %.f A", I_del)

diff --git a/3472/CH46/EX46.3/Example46_3.sce b/3472/CH46/EX46.3/Example46_3.sce
new file mode 100644
index 000000000..9e8f5b048
--- /dev/null
+++ b/3472/CH46/EX46.3/Example46_3.sce
@@ -0,0 +1,35 @@
+// A Texbook on POWER SYSTEM ENGINEERING

+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar

+// DHANPAT RAI & Co.

+// SECOND EDITION 

+

+// PART IV : UTILIZATION AND TRACTION

+// CHAPTER 8: BRAKING

+

+// EXAMPLE : 8.3 :

+// Page number 810

+clear ; clc ; close ; // Clear the work space and console

+

+// Given data

+W = 400.0       // Weight of train(tonne)

+G = 100.0/70    // Gradient(%)

+t = 120.0       // Time(sec)

+V_1 = 80.0      // Speed(km/hr)

+V_2 = 50.0      // Speed(km/hr)

+r_kg = 5.0      // Tractive resistance(kg/tonne)

+I = 7.5         // Rotational inertia(%)

+n = 0.75        // Overall efficiency

+

+// Calculations

+W_e = W*(100+I)/100                                      // Accelerating weight of train(tonne)

+r = r_kg*9.81                                            // Tractive resistance(N-m/tonne)

+energy_recuperation = 0.01072*W_e*(V_1**2-V_2**2)/1000   // Energy available for recuperation(kWh)

+F_t = W*(r-98.1*G)                                       // Tractive effort during retardation(N)

+distance = (V_1+V_2)*1000*t/(2*3600)                     // Distance travelled by train during retardation period(m)

+energy_train = abs(F_t)*distance/(3600*1000)             // Energy available during train movement(kWh)

+net_energy = n*(energy_recuperation+energy_train)        // Net energy returned to supply system(kWh)

+

+// Results

+disp("PART IV - EXAMPLE : 8.3 : SOLUTION :-")

+printf("\nEnergy returned to lines = %.2f kWh\n", net_energy)

+printf("\nNOTE: ERROR: Calculation mistakes & more approximation in textbook solution")

diff --git a/3472/CH46/EX46.4/Example46_4.sce b/3472/CH46/EX46.4/Example46_4.sce
new file mode 100644
index 000000000..550c2a55c
--- /dev/null
+++ b/3472/CH46/EX46.4/Example46_4.sce
@@ -0,0 +1,32 @@
+// A Texbook on POWER SYSTEM ENGINEERING

+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar

+// DHANPAT RAI & Co.

+// SECOND EDITION 

+

+// PART IV : UTILIZATION AND TRACTION

+// CHAPTER 8: BRAKING

+

+// EXAMPLE : 8.4 :

+// Page number 810

+clear ; clc ; close ; // Clear the work space and console

+

+// Given data

+W = 355.0        // Weight of train(tonne)

+V_1 = 80.5       // Speed(km/hr)

+V_2 = 48.3       // Speed(km/hr)

+D = 1.525        // Distance(km)

+G = 100.0/90     // Gradient(%)

+I = 10.0         // Rotational inertia(%)

+r = 53.0         // Tractive resistance(N/tonne)

+n = 0.8          // Overall efficiency

+

+// Calculations

+beta = (V_1**2-V_2**2)/(2*D*3600)   // Braking retardation(km phps)

+W_e = W*(100+I)/100                 // Accelerating weight of train(tonne)

+F_t = 277.8*W_e*beta+98.1*W*G-W*r   // Tractive effort(N)

+work_done = F_t*D*1000              // Work done by this effort(N-m)

+energy = work_done*n/(1000*3600)    // Energy returned to line(kWh)

+

+// Results

+disp("PART IV - EXAMPLE : 8.4 : SOLUTION :-")

+printf("\nEnergy returned to the line = %.1f kWh", energy)

diff --git a/3472/CH46/EX46.5/Example46_5.sce b/3472/CH46/EX46.5/Example46_5.sce
new file mode 100644
index 000000000..fecc3fbf5
--- /dev/null
+++ b/3472/CH46/EX46.5/Example46_5.sce
@@ -0,0 +1,29 @@
+// A Texbook on POWER SYSTEM ENGINEERING

+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar

+// DHANPAT RAI & Co.

+// SECOND EDITION 

+

+// PART IV : UTILIZATION AND TRACTION

+// CHAPTER 8: BRAKING

+

+// EXAMPLE : 8.5 :

+// Page number 811-812

+clear ; clc ; close ; // Clear the work space and console

+funcprot(0)

+

+// Given data

+area = 16.13       // Area of brakes(sq.cm/pole face)

+phi = 2.5*10**-3   // Flux(Wb)

+u = 0.2            // Co-efficient of friction

+W = 10.0           // Weight of car(tonnes)

+

+// Calculations

+a = area*10**-4                   // Area of brakes(sq.m/pole face)

+F = phi**2/(2*%pi*10**-7*a)       // Force(N)

+force = F*u                       // Braking effect considering flux and coefficient of friction(N)

+beta = u*F/(W*1000)*100           // Rate of retardation produced by braking effect(cm/sec^2)

+

+// Results

+disp("PART IV - EXAMPLE : 8.5 : SOLUTION :-")

+printf("\nBraking effect, F = %.f N", force)

+printf("\nRate of retardation produced by this braking effect, β = %.2f cm/sec^2", beta)