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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /317/CH15/EX15.1 | |
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initial commit / add all books
Diffstat (limited to '317/CH15/EX15.1')
-rwxr-xr-x | 317/CH15/EX15.1/example1.sce | 23 | ||||
-rwxr-xr-x | 317/CH15/EX15.1/example1.txt | 1 |
2 files changed, 24 insertions, 0 deletions
diff --git a/317/CH15/EX15.1/example1.sce b/317/CH15/EX15.1/example1.sce new file mode 100755 index 000000000..6370430fe --- /dev/null +++ b/317/CH15/EX15.1/example1.sce @@ -0,0 +1,23 @@ +// find diode current
+// Electronic Principles
+// By Albert Malvino , David Bates
+// Seventh Edition
+// The McGraw-Hill Companies
+// Example 15-1, page 524
+
+clear; clc; close;
+
+// Given data
+Vb=10;// breakover voltage of the diode
+V=15;// input voltage in volts
+Ih=4*10^-3;// holding current in amperes
+Vd=0.7 ;// voltage across diode in volts
+R=100;// resistance in ohms
+
+// Calculations
+// as V>Vb ,the diode breaks over .Taking into consideration the voltage across the diode
+I=(V-Vd)/R;// diode current in amperes
+disp("Amperes",I,"diode current=")
+
+// Result
+// Diode current is 143 mAmperes
\ No newline at end of file diff --git a/317/CH15/EX15.1/example1.txt b/317/CH15/EX15.1/example1.txt new file mode 100755 index 000000000..c3ccc00be --- /dev/null +++ b/317/CH15/EX15.1/example1.txt @@ -0,0 +1 @@ +Diode current is 143 mAmperes
\ No newline at end of file |