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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+
+// Ex9_8
+
+clc;
+
+// Given:
+a1=0.015;
+a2=0.04;
+
+// Solution: Defining the seperation factor f as approximately equal to (a2/a1) where a1, a2 are the relative abundances of the isotope of interest in the initial and final fractions, we have
+
+f=(a2/a1);
+
+printf("The single stage seperation factor is = %f",f)
+