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+// FUNDAMENTALS OF ELECTICAL MACHINES 

+// M.A.SALAM 

+// NAROSA PUBLISHING HOUSE 

+// SECOND EDITION

+

+// Chapter 4 : DIRECT CURRENT GENERATORS

+// Example : 4.8

+

+

+clc;clear; // clears the console and command history 

+

+// Given data

+V_t = 220   // shunt generator voltage in V

+I_L = 146   // generator delivering current in A

+R_sh = 50   // shunt field resistance in ohm

+R_a = 0.012 // armature resistance in ohm

+R_s = 0.02  // series field resistance in ohm

+R_d = 0.03  // diverter field resistance in ohm

+

+// caclulations 

+I_sh = V_t/R_sh             // shunt field current in A

+I_a = I_L+I_sh              // armature current in A

+R_com = R_s*R_d/(R_s+R_d)   // combined resistance in ohm

+E_g = V_t+(I_a*(R_a+R_com)) // generated voltage in V

+P_lsd = I_a^2*R_com         // power loss in series and diverter in W

+P_la = I_a^2*R_com         // power loss in the armature circuit resistance in W

+P_lsh =  V_t*I_sh          // power loss in shunt field resistance in W

+P_dl = I_L*V_t             // power delivered in W

+

+// display the result 

+disp("Example 4.8 solution");

+printf(" \n Generated voltage \n E_g = %.1f V \n", E_g);

+printf(" \n Power distribution \n P_dl = %.0f W \n", P_dl);