From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 2642/CH4/EX4.8/Ex4_8.sce | 33 +++++++++++++++++++++++++++++++++
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 create mode 100755 2642/CH4/EX4.8/Ex4_8.sce

(limited to '2642/CH4/EX4.8')

diff --git a/2642/CH4/EX4.8/Ex4_8.sce b/2642/CH4/EX4.8/Ex4_8.sce
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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 4 : DIRECT CURRENT GENERATORS
+// Example : 4.8
+
+
+clc;clear; // clears the console and command history 
+
+// Given data
+V_t = 220   // shunt generator voltage in V
+I_L = 146   // generator delivering current in A
+R_sh = 50   // shunt field resistance in ohm
+R_a = 0.012 // armature resistance in ohm
+R_s = 0.02  // series field resistance in ohm
+R_d = 0.03  // diverter field resistance in ohm
+
+// caclulations 
+I_sh = V_t/R_sh             // shunt field current in A
+I_a = I_L+I_sh              // armature current in A
+R_com = R_s*R_d/(R_s+R_d)   // combined resistance in ohm
+E_g = V_t+(I_a*(R_a+R_com)) // generated voltage in V
+P_lsd = I_a^2*R_com         // power loss in series and diverter in W
+P_la = I_a^2*R_com         // power loss in the armature circuit resistance in W
+P_lsh =  V_t*I_sh          // power loss in shunt field resistance in W
+P_dl = I_L*V_t             // power delivered in W
+
+// display the result 
+disp("Example 4.8 solution");
+printf(" \n Generated voltage \n E_g = %.1f V \n", E_g);
+printf(" \n Power distribution \n P_dl = %.0f W \n", P_dl);
-- 
cgit