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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+Nd=6*10^16
+disp("Nd = "+string(Nd)+" cm^-3") //initializing the value of donor concentration.
+Na=10^17
+disp("Na = "+string(Na)+" cm^-3")//initializing the value of acceptor concentration.
+no=1.5*10^10
+disp("no = "+string(no)+" cm^-3")//initializing the value of electron and hole per cm^3.
+p=((Na-Nd)+sqrt((Na-Nd)^2+4*no))/2
+disp("Hole concentration,n=(-(Na-Nd)+sqrt((Na-Nd)^2+4*no))/2)= "+string(p)+"cm^-3")//calculation
+n=(no^2/p)
+disp("Electron concentration,n=(no^2/p))= "+string(n))//calculation
+
+
+//this is solved problem 2.15 of chapter 2.
+//the value of Na,Nd in the solution is different than provided in the question
+//I have used the value used in the solution(i.e Na=10^17,Nd=6*10^16)