From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 2594/CH2/EX2.27/Ex2_27.sce | 16 ++++++++++++++++
 1 file changed, 16 insertions(+)
 create mode 100755 2594/CH2/EX2.27/Ex2_27.sce

(limited to '2594/CH2/EX2.27')

diff --git a/2594/CH2/EX2.27/Ex2_27.sce b/2594/CH2/EX2.27/Ex2_27.sce
new file mode 100755
index 000000000..2a12e9ec2
--- /dev/null
+++ b/2594/CH2/EX2.27/Ex2_27.sce
@@ -0,0 +1,16 @@
+clc
+Nd=6*10^16
+disp("Nd = "+string(Nd)+" cm^-3") //initializing the value of donor concentration.
+Na=10^17
+disp("Na = "+string(Na)+" cm^-3")//initializing the value of acceptor concentration.
+no=1.5*10^10
+disp("no = "+string(no)+" cm^-3")//initializing the value of electron and hole per cm^3.
+p=((Na-Nd)+sqrt((Na-Nd)^2+4*no))/2
+disp("Hole concentration,n=(-(Na-Nd)+sqrt((Na-Nd)^2+4*no))/2)= "+string(p)+"cm^-3")//calculation
+n=(no^2/p)
+disp("Electron concentration,n=(no^2/p))= "+string(n))//calculation
+
+
+//this is solved problem 2.15 of chapter 2.
+//the value of Na,Nd in the solution is different than provided in the question 
+//I have used the value used in the solution(i.e Na=10^17,Nd=6*10^16) 
-- 
cgit