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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Exa 4.20
+format('v',5)
+clc;
+clear;
+close;
+// Given data
+alpha_dc = 0.98;
+I_CBO = 12;// in µA
+I_CBO = I_CBO * 10^-6;// in A
+I_B = 120;// in µA
+I_B = I_B * 10^-6;// in A
+beta_dc = alpha_dc/(1-alpha_dc);
+// The emitter current,
+I_E = ((1 + beta_dc) * I_B) + ((1 + beta_dc) * I_CBO);//in A
+I_E = I_E * 10^3;// in mA
+disp(I_E,"The value of I_E in mA is");