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authorprashantsinalkar2018-02-03 10:59:42 +0530
committerprashantsinalkar2018-02-03 10:59:42 +0530
commitd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (patch)
tree612077a22c8142c0ae754ec11882a4e7d5dc25a4 /2465/CH18/EX18.4/Ex18_4.sce
parentf35ea80659b6a49d1bb2ce1d7d002583f3f40947 (diff)
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Modified the code
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diff --git a/2465/CH18/EX18.4/Ex18_4.sce b/2465/CH18/EX18.4/Ex18_4.sce
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@@ -1,17 +0,0 @@
-//Chapter-18,Example 4,Page 406
-clc();
-close();
-
-V1= 25 //volume of H2SO4
-
-V2 =15 //volumeof NaOH
-
-v= V1*0.1-V2*0.1 //volume of H2SO4 consumed
-
-//100 cc H2SO4 ==17 g NH3 == 14 g N
-//1 cc H2SO4 = 14/1000 g N =0.014 g N
-//0.014 g N is present in 1 g coal
-
-N= 0.014*100
-
-printf("the percentage of nitrogen is %.2f ",N)