diff options
| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /2459/CH5 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '2459/CH5')
| -rw-r--r-- | 2459/CH5/EX5.1/Ex5_1.PNG | bin | 0 -> 4352 bytes | |||
| -rw-r--r-- | 2459/CH5/EX5.1/Ex5_1.sce | 11 | ||||
| -rw-r--r-- | 2459/CH5/EX5.2/Ex5_2.PNG | bin | 0 -> 5952 bytes | |||
| -rw-r--r-- | 2459/CH5/EX5.2/Ex5_2.sce | 20 | ||||
| -rw-r--r-- | 2459/CH5/EX5.3/Ex5_3.PNG | bin | 0 -> 5380 bytes | |||
| -rw-r--r-- | 2459/CH5/EX5.3/Ex5_3.sce | 27 | ||||
| -rw-r--r-- | 2459/CH5/EX5.4/Ex5_4.PNG | bin | 0 -> 4489 bytes | |||
| -rw-r--r-- | 2459/CH5/EX5.4/Ex5_4.sce | 13 | ||||
| -rw-r--r-- | 2459/CH5/EX5.5/Ex5_5.PNG | bin | 0 -> 6094 bytes | |||
| -rw-r--r-- | 2459/CH5/EX5.5/Ex5_5.sce | 21 | ||||
| -rw-r--r-- | 2459/CH5/EX5.5/Figure5_5.JPG | bin | 0 -> 21276 bytes |
11 files changed, 92 insertions, 0 deletions
diff --git a/2459/CH5/EX5.1/Ex5_1.PNG b/2459/CH5/EX5.1/Ex5_1.PNG Binary files differnew file mode 100644 index 000000000..aa47c618f --- /dev/null +++ b/2459/CH5/EX5.1/Ex5_1.PNG diff --git a/2459/CH5/EX5.1/Ex5_1.sce b/2459/CH5/EX5.1/Ex5_1.sce new file mode 100644 index 000000000..d04943f60 --- /dev/null +++ b/2459/CH5/EX5.1/Ex5_1.sce @@ -0,0 +1,11 @@ +//chspter5
+//example5.1
+//page85
+
+mu=20
+rp=10 // kilo ohm
+Rl=15 // kilo ohm
+
+Av=mu*Rl/(rp+Rl)
+
+printf("voltage gain = %.3f",Av)
diff --git a/2459/CH5/EX5.2/Ex5_2.PNG b/2459/CH5/EX5.2/Ex5_2.PNG Binary files differnew file mode 100644 index 000000000..e54b1397e --- /dev/null +++ b/2459/CH5/EX5.2/Ex5_2.PNG diff --git a/2459/CH5/EX5.2/Ex5_2.sce b/2459/CH5/EX5.2/Ex5_2.sce new file mode 100644 index 000000000..0323e4bec --- /dev/null +++ b/2459/CH5/EX5.2/Ex5_2.sce @@ -0,0 +1,20 @@ +//chspter5
+//example5.2
+//page85
+
+mu=20
+rp=10 // kilo ohm
+Rl=15 // kilo ohm
+Eg=3 // V
+
+// the diagram in book is for understanding only. Also we do not have a block of "triode" in scilab xcos. The figure is not required to solve the problem.
+
+Av=mu*Rl/(rp+Rl)
+Ip=(mu*Eg/2^0.5)/(rp+Rl)
+V_out=Ip*Rl
+
+printf("voltage gain = %.3f \n",Av)
+printf("load current = %.3f mA \n",Ip)
+printf("output voltage = %.3f V",V_out)
+
+// the accurate answer for output voltage is 25.456V but in book it is given as 25.35V
diff --git a/2459/CH5/EX5.3/Ex5_3.PNG b/2459/CH5/EX5.3/Ex5_3.PNG Binary files differnew file mode 100644 index 000000000..50d3a688d --- /dev/null +++ b/2459/CH5/EX5.3/Ex5_3.PNG diff --git a/2459/CH5/EX5.3/Ex5_3.sce b/2459/CH5/EX5.3/Ex5_3.sce new file mode 100644 index 000000000..7ca406c06 --- /dev/null +++ b/2459/CH5/EX5.3/Ex5_3.sce @@ -0,0 +1,27 @@ +//chapter5
+//example5.3
+//page85
+
+// for Rl=50, Av=30
+//for Rl=85, Av=34
+
+// Av=mu*Rl/(rp+Rl)
+// thus
+// Av*rp-mu*Rl=-Av*rl
+// substituting for Rl=50 and Rl=85 we get the following linaer equations
+
+// 30*rp-50*mu=-1500 and
+// 34*rp-85*mu=-2890
+// solving by matrix
+
+a=[30 34 ; -50 -85]
+b=[-1500 -2890]
+solution=b/a
+mu=solution(1,2)
+rp=solution(1,1) // in kilo ohms since RL was in kilo ohm in the equations
+
+gm_kilo_mho=mu/rp
+gm=gm_kilo_mho/1000
+printf("mu = %.3f \n",mu)
+printf("rp = %.3f kilo ohm \n",rp)
+printf("gm = %.4f mho \n",gm)
diff --git a/2459/CH5/EX5.4/Ex5_4.PNG b/2459/CH5/EX5.4/Ex5_4.PNG Binary files differnew file mode 100644 index 000000000..e45865e09 --- /dev/null +++ b/2459/CH5/EX5.4/Ex5_4.PNG diff --git a/2459/CH5/EX5.4/Ex5_4.sce b/2459/CH5/EX5.4/Ex5_4.sce new file mode 100644 index 000000000..eb940987c --- /dev/null +++ b/2459/CH5/EX5.4/Ex5_4.sce @@ -0,0 +1,13 @@ +//chapter5
+//example5.4
+//page86
+
+mu=6
+Eg=9 // V
+rp=2400 // ohm
+Rl=3000 // ohm
+
+Ip=mu*Eg/(rp+Rl) // A
+power=Ip^2*Rl // W
+
+printf("ac power in load = %.3f W",power)
diff --git a/2459/CH5/EX5.5/Ex5_5.PNG b/2459/CH5/EX5.5/Ex5_5.PNG Binary files differnew file mode 100644 index 000000000..bdd4596fe --- /dev/null +++ b/2459/CH5/EX5.5/Ex5_5.PNG diff --git a/2459/CH5/EX5.5/Ex5_5.sce b/2459/CH5/EX5.5/Ex5_5.sce new file mode 100644 index 000000000..dcc87b75f --- /dev/null +++ b/2459/CH5/EX5.5/Ex5_5.sce @@ -0,0 +1,21 @@ +//chapter5
+//example5.5
+//page95
+
+rp=1000 // ohm
+Rl=10 // ohm
+Eg=8 // V
+mu=20
+
+// the diagram in book is for understanding only. Also we do not have a block of "triode" in scilab xcos. The figure is not required to solve the problem.
+// however, the equivalent circuit has been drawn in xcos for reference.
+
+// since rp=n^2*Rl for maximum power transfer so
+n=(rp/Rl)^0.5
+
+// P_max=Ip^2*RE where Ip=mu*Eg/(rp+RE) and RE=rp
+// thus
+P_max=((mu*Eg)^2)/(4*rp)
+
+printf("transformation ratio n= %.2f \n",n)
+printf("power supplied to speaker when signal is 8V rms is = %.3f W",P_max)
diff --git a/2459/CH5/EX5.5/Figure5_5.JPG b/2459/CH5/EX5.5/Figure5_5.JPG Binary files differnew file mode 100644 index 000000000..172a31849 --- /dev/null +++ b/2459/CH5/EX5.5/Figure5_5.JPG |
