From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 2459/CH5/EX5.1/Ex5_1.PNG     | Bin 0 -> 4352 bytes
 2459/CH5/EX5.1/Ex5_1.sce     |  11 +++++++++++
 2459/CH5/EX5.2/Ex5_2.PNG     | Bin 0 -> 5952 bytes
 2459/CH5/EX5.2/Ex5_2.sce     |  20 ++++++++++++++++++++
 2459/CH5/EX5.3/Ex5_3.PNG     | Bin 0 -> 5380 bytes
 2459/CH5/EX5.3/Ex5_3.sce     |  27 +++++++++++++++++++++++++++
 2459/CH5/EX5.4/Ex5_4.PNG     | Bin 0 -> 4489 bytes
 2459/CH5/EX5.4/Ex5_4.sce     |  13 +++++++++++++
 2459/CH5/EX5.5/Ex5_5.PNG     | Bin 0 -> 6094 bytes
 2459/CH5/EX5.5/Ex5_5.sce     |  21 +++++++++++++++++++++
 2459/CH5/EX5.5/Figure5_5.JPG | Bin 0 -> 21276 bytes
 11 files changed, 92 insertions(+)
 create mode 100644 2459/CH5/EX5.1/Ex5_1.PNG
 create mode 100644 2459/CH5/EX5.1/Ex5_1.sce
 create mode 100644 2459/CH5/EX5.2/Ex5_2.PNG
 create mode 100644 2459/CH5/EX5.2/Ex5_2.sce
 create mode 100644 2459/CH5/EX5.3/Ex5_3.PNG
 create mode 100644 2459/CH5/EX5.3/Ex5_3.sce
 create mode 100644 2459/CH5/EX5.4/Ex5_4.PNG
 create mode 100644 2459/CH5/EX5.4/Ex5_4.sce
 create mode 100644 2459/CH5/EX5.5/Ex5_5.PNG
 create mode 100644 2459/CH5/EX5.5/Ex5_5.sce
 create mode 100644 2459/CH5/EX5.5/Figure5_5.JPG

(limited to '2459/CH5')

diff --git a/2459/CH5/EX5.1/Ex5_1.PNG b/2459/CH5/EX5.1/Ex5_1.PNG
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diff --git a/2459/CH5/EX5.1/Ex5_1.sce b/2459/CH5/EX5.1/Ex5_1.sce
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index 000000000..d04943f60
--- /dev/null
+++ b/2459/CH5/EX5.1/Ex5_1.sce
@@ -0,0 +1,11 @@
+//chspter5
+//example5.1
+//page85
+
+mu=20 
+rp=10 // kilo ohm
+Rl=15 // kilo ohm
+
+Av=mu*Rl/(rp+Rl)
+
+printf("voltage gain = %.3f",Av)
diff --git a/2459/CH5/EX5.2/Ex5_2.PNG b/2459/CH5/EX5.2/Ex5_2.PNG
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index 000000000..e54b1397e
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diff --git a/2459/CH5/EX5.2/Ex5_2.sce b/2459/CH5/EX5.2/Ex5_2.sce
new file mode 100644
index 000000000..0323e4bec
--- /dev/null
+++ b/2459/CH5/EX5.2/Ex5_2.sce
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+//chspter5
+//example5.2
+//page85
+
+mu=20
+rp=10 // kilo ohm
+Rl=15 // kilo ohm
+Eg=3 // V
+
+// the diagram in book is for understanding only. Also we do not have a block of "triode" in scilab xcos. The figure is not required to solve the problem.
+
+Av=mu*Rl/(rp+Rl)
+Ip=(mu*Eg/2^0.5)/(rp+Rl)
+V_out=Ip*Rl
+
+printf("voltage gain = %.3f \n",Av)
+printf("load current = %.3f mA \n",Ip)
+printf("output voltage = %.3f V",V_out)
+
+// the accurate answer for output voltage is 25.456V but in book it is given as 25.35V
diff --git a/2459/CH5/EX5.3/Ex5_3.PNG b/2459/CH5/EX5.3/Ex5_3.PNG
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index 000000000..50d3a688d
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diff --git a/2459/CH5/EX5.3/Ex5_3.sce b/2459/CH5/EX5.3/Ex5_3.sce
new file mode 100644
index 000000000..7ca406c06
--- /dev/null
+++ b/2459/CH5/EX5.3/Ex5_3.sce
@@ -0,0 +1,27 @@
+//chapter5
+//example5.3
+//page85
+
+// for Rl=50, Av=30
+//for Rl=85, Av=34
+
+// Av=mu*Rl/(rp+Rl)
+// thus
+// Av*rp-mu*Rl=-Av*rl
+// substituting for Rl=50 and Rl=85 we get the following linaer equations
+
+// 30*rp-50*mu=-1500 and 
+// 34*rp-85*mu=-2890
+// solving by matrix
+
+a=[30 34 ; -50 -85]
+b=[-1500 -2890]
+solution=b/a
+mu=solution(1,2)
+rp=solution(1,1) // in kilo ohms since RL was in kilo ohm in the equations
+
+gm_kilo_mho=mu/rp
+gm=gm_kilo_mho/1000
+printf("mu = %.3f \n",mu)
+printf("rp = %.3f kilo ohm \n",rp)
+printf("gm = %.4f mho \n",gm)
diff --git a/2459/CH5/EX5.4/Ex5_4.PNG b/2459/CH5/EX5.4/Ex5_4.PNG
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diff --git a/2459/CH5/EX5.4/Ex5_4.sce b/2459/CH5/EX5.4/Ex5_4.sce
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index 000000000..eb940987c
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@@ -0,0 +1,13 @@
+//chapter5
+//example5.4
+//page86
+
+mu=6
+Eg=9 // V
+rp=2400 // ohm
+Rl=3000 // ohm
+
+Ip=mu*Eg/(rp+Rl) // A
+power=Ip^2*Rl // W
+
+printf("ac power in load = %.3f W",power)
diff --git a/2459/CH5/EX5.5/Ex5_5.PNG b/2459/CH5/EX5.5/Ex5_5.PNG
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index 000000000..bdd4596fe
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diff --git a/2459/CH5/EX5.5/Ex5_5.sce b/2459/CH5/EX5.5/Ex5_5.sce
new file mode 100644
index 000000000..dcc87b75f
--- /dev/null
+++ b/2459/CH5/EX5.5/Ex5_5.sce
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+//chapter5
+//example5.5
+//page95
+
+rp=1000 // ohm
+Rl=10 // ohm
+Eg=8 // V
+mu=20
+
+// the diagram in book is for understanding only. Also we do not have a block of "triode" in scilab xcos. The figure is not required to solve the problem.
+// however, the equivalent circuit has been drawn in xcos for reference.
+
+// since rp=n^2*Rl for maximum power transfer so
+n=(rp/Rl)^0.5
+
+// P_max=Ip^2*RE where Ip=mu*Eg/(rp+RE) and RE=rp
+// thus
+P_max=((mu*Eg)^2)/(4*rp)
+
+printf("transformation ratio n= %.2f \n",n)
+printf("power supplied to speaker when signal is 8V rms is = %.3f W",P_max)
diff --git a/2459/CH5/EX5.5/Figure5_5.JPG b/2459/CH5/EX5.5/Figure5_5.JPG
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-- 
cgit