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+//chapter5
+//example5.5
+//page95
+
+rp=1000 // ohm
+Rl=10 // ohm
+Eg=8 // V
+mu=20
+
+// the diagram in book is for understanding only. Also we do not have a block of "triode" in scilab xcos. The figure is not required to solve the problem.
+// however, the equivalent circuit has been drawn in xcos for reference.
+
+// since rp=n^2*Rl for maximum power transfer so
+n=(rp/Rl)^0.5
+
+// P_max=Ip^2*RE where Ip=mu*Eg/(rp+RE) and RE=rp
+// thus
+P_max=((mu*Eg)^2)/(4*rp)
+
+printf("transformation ratio n= %.2f \n",n)
+printf("power supplied to speaker when signal is 8V rms is = %.3f W",P_max)