diff options
Diffstat (limited to '2459/CH5/EX5.5')
| -rw-r--r-- | 2459/CH5/EX5.5/Ex5_5.PNG | bin | 0 -> 6094 bytes | |||
| -rw-r--r-- | 2459/CH5/EX5.5/Ex5_5.sce | 21 | ||||
| -rw-r--r-- | 2459/CH5/EX5.5/Figure5_5.JPG | bin | 0 -> 21276 bytes |
3 files changed, 21 insertions, 0 deletions
diff --git a/2459/CH5/EX5.5/Ex5_5.PNG b/2459/CH5/EX5.5/Ex5_5.PNG Binary files differnew file mode 100644 index 000000000..bdd4596fe --- /dev/null +++ b/2459/CH5/EX5.5/Ex5_5.PNG diff --git a/2459/CH5/EX5.5/Ex5_5.sce b/2459/CH5/EX5.5/Ex5_5.sce new file mode 100644 index 000000000..dcc87b75f --- /dev/null +++ b/2459/CH5/EX5.5/Ex5_5.sce @@ -0,0 +1,21 @@ +//chapter5
+//example5.5
+//page95
+
+rp=1000 // ohm
+Rl=10 // ohm
+Eg=8 // V
+mu=20
+
+// the diagram in book is for understanding only. Also we do not have a block of "triode" in scilab xcos. The figure is not required to solve the problem.
+// however, the equivalent circuit has been drawn in xcos for reference.
+
+// since rp=n^2*Rl for maximum power transfer so
+n=(rp/Rl)^0.5
+
+// P_max=Ip^2*RE where Ip=mu*Eg/(rp+RE) and RE=rp
+// thus
+P_max=((mu*Eg)^2)/(4*rp)
+
+printf("transformation ratio n= %.2f \n",n)
+printf("power supplied to speaker when signal is 8V rms is = %.3f W",P_max)
diff --git a/2459/CH5/EX5.5/Figure5_5.JPG b/2459/CH5/EX5.5/Figure5_5.JPG Binary files differnew file mode 100644 index 000000000..172a31849 --- /dev/null +++ b/2459/CH5/EX5.5/Figure5_5.JPG |
