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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /2459/CH27/EX27.2 | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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diff --git a/2459/CH27/EX27.2/Ex27_2.JPG b/2459/CH27/EX27.2/Ex27_2.JPG Binary files differnew file mode 100644 index 000000000..ab24faffe --- /dev/null +++ b/2459/CH27/EX27.2/Ex27_2.JPG diff --git a/2459/CH27/EX27.2/Ex27_2.sce b/2459/CH27/EX27.2/Ex27_2.sce new file mode 100644 index 000000000..1fa39220f --- /dev/null +++ b/2459/CH27/EX27.2/Ex27_2.sce @@ -0,0 +1,30 @@ +//chapter27
+//example27.2
+//page575
+
+R1=4 // ohm
+R2=4 // ohm
+R3=4 // ohm
+
+// for h11 and h21, imagine that output terminals are shorted hence it is clear that input impedence is equal to R1+R2*R3/(R2+R3)
+ // this is h11 by definition so
+ h11=R1+R2*R3/(R2+R3)
+
+ // now current will divide equally at junction of 4 ohm resistors so output_current/input_current = -0.5
+ // but this ratio is h21 by definition. Thus
+ h21=-0.5
+
+// for h12 and h22 imagine a voltage source on output terminals
+ // this voltage will be divided by a factor 2
+ // hence input_voltage/output_voltage = 0.5
+ // but this ratio is h12 by definition. Thus
+ h12=0.5
+
+ // here output impedence looking into output terminals with input terminals open is 8 ohm.
+ // its reciprocal is h22 by definition. Thus
+ h22=1/8
+
+printf("h11 = %.3f ohm \n",h11)
+printf("h21 = %.3f \n",h21)
+printf("h12 = %.3f \n",h12)
+printf("h22 = %.3f ohm \n",h22)
diff --git a/2459/CH27/EX27.2/Figure27_2.jpg b/2459/CH27/EX27.2/Figure27_2.jpg Binary files differnew file mode 100644 index 000000000..cdf80584e --- /dev/null +++ b/2459/CH27/EX27.2/Figure27_2.jpg |