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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Scilab code Ex7.11: Pg:307 (2008)
+clc;clear;
+P = 3.2e+07/1.6e-013; // Power developed by the reactor, MeV
+E = 200; // Energy released by the reactor per fission, MeV
+n = P/E; // Number of fissions occuring in the reactor per second, per sec
+N = n*1000*3600; // Number of atoms or nuclei of Uranium 235 consumed in 1000 hours
+// Since the number of atoms in 235 g of Uranium is 6e+023
+M = N/6e+023*235/1000; // Mass of Uranium 235 consumed in 1000 hours, kg
+printf("\nThe number of atoms of Uranium 235 undergoing fission per second = %4.1e ", N);
+printf("\nThe mass of Uranium 235 consumed in 1000 hours = %4.2f kg ", M);
+
+// Result
+// The number of atoms of Uranium 235 undergoing fission per second = 3.6e+024
+// The mass of Uranium 235 consumed in 1000 hours = 1.41 kg \ No newline at end of file