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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /181/CH4/EX4.9/example4_9.sce | |
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diff --git a/181/CH4/EX4.9/example4_9.sce b/181/CH4/EX4.9/example4_9.sce new file mode 100755 index 000000000..32d2b36ea --- /dev/null +++ b/181/CH4/EX4.9/example4_9.sce @@ -0,0 +1,38 @@ +// Calculating BJT parameters assuming Vbe
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 4-9 in page 211
+
+clear; clc; close;
+
+// Given Data
+Ve=1; // Emitter Voltage of BJT in V
+Vbe=0.7; // Base-Emitter Voltage of BJT in V
+Rb=20*10^3; // Base Resistance of Circuit in K-ohms
+Rc=5*10^3; // Collector Resistance of Circuit in K-ohms
+Re=5*10^3; // Emitter Resistance of Circuit in K-ohms
+Vcc=5; // DC voltage across Collector in V
+Vee=-5; // DC voltage across Emitter in V
+
+// Calculations
+Vb=Ve-Vbe;
+Ib=Vb/Rb;
+Ie=(Vcc-1)/Re;
+Ic=Ie-Ib;
+Vc=(Rc*Ic)-Vcc;
+beta_bjt=Ic/Ib;
+alpha=Ic/Ie;
+
+printf("Circuit Parameters:\n(a)Base Voltage = %0.3f V\n(b)Base Current = %0.3e A\n(c)Emitter Current = %0.3e A\n(d)Collector Current = %0.3e A\n(e)Collector Voltage = %0.3f V\n(f)beta gain = %0.3f\n(g)alpha gain = %0.3f\n",Vb,Ib,Ie,Ic,Vc,beta_bjt,alpha);
+
+// Results
+// For the BJT Circuit,
+// (a) Base Voltage = 0.3 V
+// (b) Base Current = 0.015 mA
+// (c) Emitter Current = 0.8 mA
+// (d) Collector Current = 0.785 mA
+// (e) Collector Voltage = -1.075 volt
+// (f) Beta gain = 52.3
+// (g) Alpha gain = 0.98
\ No newline at end of file |