From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 181/CH4/EX4.9/example4_9.sce | 38 ++++++++++++++++++++++++++++++++++++++
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+// Calculating BJT parameters assuming Vbe
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 4-9 in page 211
+
+clear; clc; close;
+
+// Given Data
+Ve=1; // Emitter Voltage of BJT in V
+Vbe=0.7; // Base-Emitter Voltage of BJT in V
+Rb=20*10^3; // Base Resistance of Circuit in K-ohms
+Rc=5*10^3; // Collector Resistance of Circuit in K-ohms
+Re=5*10^3; // Emitter Resistance of Circuit in K-ohms
+Vcc=5; // DC voltage across Collector in V
+Vee=-5; // DC voltage across Emitter in V
+
+// Calculations
+Vb=Ve-Vbe;
+Ib=Vb/Rb; 
+Ie=(Vcc-1)/Re; 
+Ic=Ie-Ib;
+Vc=(Rc*Ic)-Vcc;
+beta_bjt=Ic/Ib;
+alpha=Ic/Ie; 
+
+printf("Circuit Parameters:\n(a)Base Voltage = %0.3f V\n(b)Base Current = %0.3e A\n(c)Emitter Current = %0.3e A\n(d)Collector Current = %0.3e A\n(e)Collector Voltage = %0.3f V\n(f)beta gain = %0.3f\n(g)alpha gain = %0.3f\n",Vb,Ib,Ie,Ic,Vc,beta_bjt,alpha);
+
+// Results
+// For the BJT Circuit,
+// (a) Base Voltage = 0.3 V
+// (b) Base Current = 0.015 mA
+// (c) Emitter Current = 0.8 mA
+// (d) Collector Current = 0.785 mA
+// (e) Collector Voltage = -1.075 volt
+// (f) Beta gain = 52.3
+// (g) Alpha gain = 0.98
\ No newline at end of file
-- 
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