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authorpriyanka2015-06-24 15:03:17 +0530
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+ // Example 4.3
+
+ // From the diagram 4.5
+ // Using super position theorem
+ // 4-A current source is active
+
+i=4/{1+(2+3)}; // Current
+R=3; // Rsistance of 3 Ohms
+V4=i*R; // Voltage across 3 Ohms resistance in Case-1
+
+ // 5-A current source is active
+i5=5; // 5-A current source
+V5=(-i5)*{1/[1+(2+3)]*3}; // Voltage across 3 Ohms resistance in Case-2
+
+ // 6-V voltage source is active
+i6=6; // 6-A current source
+V6=i6*{3/[1+(2+3)]}; // Voltage across 3 Ohms resistance in Case-3
+
+V=V4+V5+V6; // Voltage across 3 Ohms resistance
+disp(' Voltage across 3 Ohms resistance is = '+string(V)+' Volt');
+
+
+
+
+ // p 106 4.3 \ No newline at end of file