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diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter10.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter10.ipynb
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+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:e88cf5fadb0380ed068b9242245f52a6fc3119add2d6c78c60f47b1c3197bfc1"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter10-Stresses in a Soil Mass"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg257"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#principal stress and normal stresses and shear stresses\n",

+      "##initialisation of variables\n",

+      "sx= 2000. ##lb/ft^3\n",

+      "sy= 2500. ##lb/ft^3\n",

+      "T= 800. ##lb/ft^3\n",

+      "t= 0.348##radians\n",

+      "##calculations\n",

+      "s1= (sx+sy)/2.+math.sqrt(((sy-sx)/2.)**2+T**2)\n",

+      "s2= (sx+sy)/2.-math.sqrt(((sy-sx)/2.)**2+T**2)\n",

+      "sn= (sx+sy)/2.+(sy-sx)*math.cos(2.*t)/2.-T*math.sin(2*t)\n",

+      "Tn= (sy-sx)*math.sin(2.*t)/2.+T*math.cos(2*t)\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('principle stress s1 = ',s1,' lb/ft^3 ')\n",

+      "print'%s %.2f %s'% ('principle stress s2 = ',s2,' lb/ft^3 ')\n",

+      "print'%s %.2f %s'% ('normal stress = ',sn,' lb/ft^3 ')\n",

+      "print'%s %.2f %s'% ('shear stress = ',Tn,' lb/ft^3 ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "principle stress s1 =  3088.15  lb/ft^3 \n",

+        "principle stress s2 =  1411.85  lb/ft^3 \n",

+        "normal stress =  1928.93  lb/ft^3 \n",

+        "shear stress =  774.22  lb/ft^3 \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg262"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate vertical stress increase\n",

+      "##initialisation of variables\n",

+      "x= 3. ##m\n",

+      "y= 4. ##m\n",

+      "P= 5. ##kN\n",

+      "z= 2. ##m\n",

+      "##calculations\n",

+      "r= math.sqrt(x**2+y**2)\n",

+      "k= r/z\n",

+      "I= 3./(2.*math.pi*((r/z)**2+1)**2.5)\n",

+      "s= P*I/z**2\n",

+      "##results\n",

+      "print'%s %.4f %s'% ('verticle stress increase at 2m = ',s,' kN/m^3 ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "verticle stress increase at 2m =  0.0042  kN/m^3 \n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex6-pg270"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the value of pressure and plot the graph\n",

+      "import math\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "from math import log\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "p=numpy.array([-9,-6,-3, 0,3,6,9])\n",

+      "e=numpy.array([0.017,0.084,0.480,0.818,0.480,0.084,0.017])\n",

+      "\n",

+      "#calculations\n",

+      "\n",

+      "\n",

+      "#results\n",

+      "\n",

+      "pyplot.plot(p,e)\n",

+      "pyplot.xlabel('Pressure (ton/ft^2)')\n",

+      "pyplot.ylabel('void ratio ,e')\n",

+      "pyplot.title('Graph of pressure vs void ratio')\n",

+      "pyplot.show()\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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VhzVrwnKoqfEmLntlbKSypMFm1knSlHKeNjOrtxlqPCFkr08/hdatw8Ls226b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\n8YTgnHMO8ITgnHMu4gnBOeccAP8P/QKt8gmEtZAAAAAASUVORK5CYII=\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x54c4510>"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter11.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter11.ipynb
new file mode 100755
index 00000000..acd23c6c
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter11.ipynb
@@ -0,0 +1,666 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:5a229faa6e3645196b99851feb0572545419f102708048be683493e984195c30"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter11-Compressibility of Soil"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg303"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#evaluvate The elastic settlement at the centre of foundation\n",

+      "Tz=150.\n",

+      "b=1.\n",

+      "l=2.\n",

+      "z=5.*b\n",

+      "Es= (10000*2 + 8000*1 +12000*2)/5\n",

+      "a=4.\n",

+      "H=z\n",

+      "m=l/b\n",

+      "n=2.*H/b\n",

+      "F1=0.641 ##from tables 11.1 and 11.2\n",

+      "F2=0.031\n",

+      "u=0.3\n",

+      "Is= F1 + ((2.-u)/(1.-u))*F2\n",

+      "If=0.71 ##from  table 11.3\n",

+      "Sef= Tz *a*b/l *(1-u**2)*Is*If/Es\n",

+      "Ser=0.93*Sef\n",

+      "print'%s %.3f %s'%('The elastic settlement at the centre of foundation =',Ser,'m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The elastic settlement at the centre of foundation = 0.012 m\n"

+       ]

+      }

+     ],

+     "prompt_number": 11

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg312"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the value of pressure\n",

+      "#find the value of e and plot the graph\n",

+      "## one value of e is done \n",

+      "Gs=2.75\n",

+      "A=30.68\n",

+      "Ms=128.\n",

+      "p=1.\n",

+      "Hs=Ms/(A*Gs*p)\n",

+      "H=2.540\n",

+      "Hv=H-Hs\n",

+      "e=Hv/Hs\n",

+      "print'%s %.3f %s'%('the value of e for give values =',e,'')\n",

+      "import math\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "from math import log\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "p=numpy.array([0,0.5,1,2,4,8,16,32])\n",

+      "e=numpy.array([0.671,0.637,0.622,0.599,0.572,0.529,0.464,0.390])\n",

+      "e1=.9\n",

+      "e2=.8\n",

+      "sig1=4.\n",

+      "sig2=2.\n",

+      "#calculations\n",

+      "Cc=(e1-e2)/log(sig1/sig2)\n",

+      "\n",

+      "#results\n",

+      "print '%s %.2f %s'%('The value of Cv (cm^2/sec) = ',Cc,'')\n",

+      "pyplot.plot(p,e)\n",

+      "pyplot.xlabel('Pressure (ton/ft^2)')\n",

+      "pyplot.ylabel('void ratio ,e')\n",

+      "pyplot.title('Graph of pressure vs void ratio')\n",

+      "pyplot.show()\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "the value of e for give values = 0.674 \n",

+        "The value of Cv (cm^2/sec) =  0.14 \n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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GxNRm9rsLeA+4sihRvAgMjYgWnyjgRGG1YMkSeOCBxiaqiMZ+jS9/2f0a1vmq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\nAaONSfy0Nv4aAAAAAElFTkSuQmCC\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x5b0e130>"

+       ]

+      }

+     ],

+     "prompt_number": 13

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg321"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#find the value compression index\n",

+      "import math\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "#calculate Compression index\n",

+      "e11=0.9\n",

+      "e21=0.8\n",

+      "T2=4.\n",

+      "T1=2.\n",

+      "Cc= (e11-e21)/math.log10(T2/T1) ## from loading branch\n",

+      "e1=0.67\n",

+      "e2=0.655\n",

+      "Cs=(e1-e2)/math.log10(T2/T1)\n",

+      "k=Cs/Cc\n",

+      "T3=12.\n",

+      "e3=e11-Cc*math.log10(T3/T1)\n",

+      "print'%s %.2f %s'%('Compression index Cc= ',Cc,'')\n",

+      "print'%s %.2f %s'%(' Cs/Cc = ',k,'')\n",

+      "print'%s %.2f %s'%(' e3 = ',e3,'')\n",

+      "#calculate the value of Cv\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "import math\n",

+      "from math import log\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "p=numpy.array([.25,.5,1.,2.,4.,8.,16.,8.,4.,2.])\n",

+      "e=numpy.array([1.03,1.02,0.98,0.91,0.79,0.71,0.62,0.635,0.655,0.67])\n",

+      "e1=.9\n",

+      "e2=.8\n",

+      "sig1=4.\n",

+      "sig2=2.\n",

+      "#calculations\n",

+      "Cc=(e1-e2)/log(sig1/sig2)\n",

+      "\n",

+      "#results\n",

+      "print 'The value of Cv (cm^2/sec) = ',Cc\n",

+      "pyplot.plot(p,e)\n",

+      "pyplot.xlabel('Pressure (ton/ft^2)')\n",

+      "pyplot.ylabel('void ratio ,e')\n",

+      "pyplot.title('Graph of pressure vs void ratio')\n",

+      "pyplot.show()\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Compression index Cc=  0.33 \n",

+        " Cs/Cc =  0.15 \n",

+        " e3 =  0.64 \n",

+        "The value of Cv (cm^2/sec) =  0.144269504089\n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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lhvBFi/KOzszaqpg2iiNIJYk1gL8CN0fElA6IrVUuUVSH+nr4179S57133oET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\n5ERhZmYt+v/jvQbqw2EtYAAAAABJRU5ErkJggg==\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x5d2cab0>"

+       ]

+      }

+     ],

+     "prompt_number": 14

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg323"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate Primary Consolidation Sc in three parts\n",

+      "Gd=14.\n",

+      "Gss=18.\n",

+      "Gsc=19.\n",

+      "Gw=9.81\n",

+      "To= 2.*Gd+4.*(Gss-Gw)+2*(Gsc-Gw)\n",

+      "LL=40.\n",

+      "Cc=0.009*(LL-10)\n",

+      "H=4.\n",

+      "T=100.\n",

+      "e=0.8\n",

+      "Sc= Cc*H*math.log10((To+T)/To)/(1.+e)\n",

+      "print'%s %.2f %s'%('a)Primary Consolidation Sc = ',Sc,' m')\n",

+      "\n",

+      "\n",

+      "Tc=190\n",

+      "Cs=Cc/6\n",

+      "Sc= Cs*H*math.log10((To+T)/To)/(1+e)\n",

+      "print'%s %.2f %s'%(' b)Primary Consolidation Sc =',Sc,'m')\n",

+      "\n",

+      "\n",

+      "Tc=170\n",

+      "Sc= Cc*H*math.log10((To+T)/Tc)/(1+e)+ Cs*H*math.log10(Tc/To)/(1+e)\n",

+      "print'%s %.3f %s'%(' c)Primary Consolidation Sc =',Sc,' m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)Primary Consolidation Sc =  0.21  m\n",

+        " b)Primary Consolidation Sc = 0.04 m\n",

+        " c)Primary Consolidation Sc = 0.047  m\n"

+       ]

+      }

+     ],

+     "prompt_number": 10

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg325"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate The settlement in the field Sc\n",

+      "Gs=18.\n",

+      "Gw=9.81\n",

+      "H=10.\n",

+      "eo=1.1\n",

+      "To=5.*(Gs-Gw)\n",

+      "T1=48.\n",

+      "T=To+T1\n",

+      "e1=1.045 ## void ratio corresponding to T \n",

+      "e=eo-e1\n",

+      "Sc=H*e/(1.+eo)\n",

+      "print'%s %.2f %s'%('The settlement in the field Sc = ',Sc,' m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The settlement in the field Sc =  0.26  m\n"

+       ]

+      }

+     ],

+     "prompt_number": 11

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex6-pg329"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate Total consolidation settlement of the clay\n",

+      "T=8.5\n",

+      "eo=0.8\n",

+      "Cc=0.28\n",

+      "To=2650.\n",

+      "T1=970.\n",

+      "C1=0.02\n",

+      "t2=5.\n",

+      "t1=1.5\n",

+      "H=8.5*12\n",

+      "epr=Cc*math.log10((To+T1)/To)\n",

+      "ep=eo-epr\n",

+      "C2=C1/(1.+ep)\n",

+      "Sc=epr*H/(1.+eo)\n",

+      "Ss=C2*H*math.log10(t2/t1)\n",

+      "TS=Sc+Ss\n",

+      "print'%s %.1f %s'%('Total consolidation settlement of the clay =',TS,' in')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Total consolidation settlement of the clay = 2.8  in\n"

+       ]

+      }

+     ],

+     "prompt_number": 12

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex7-pg336"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate t field\n",

+      "##T50 = Cvtlab /H^2 lab = Cvtfield?H^2 fiels\n",

+      "tl=140.\n",

+      "Hf=3.\n",

+      "Hd=0.025/2.\n",

+      "tf=tl*Hf**2/Hd**2\n",

+      "k=tf/(3600.*24.)\n",

+      "print'%s %.1f %s'%('t field = ',k,' days')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "t field =  93.3  days\n"

+       ]

+      }

+     ],

+     "prompt_number": 13

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex8-pg336"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "##Tv is directly proportional to U^2\n",

+      "t1=93.333\n",

+      "U2=30.\n",

+      "U1=50.\n",

+      "t2=t1*U2**2./U1**2.\n",

+      "print'%s %.2f %s'%('t2 =',t2,' days')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "t2 = 33.60  days\n"

+       ]

+      }

+     ],

+     "prompt_number": 14

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex9-pg337"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#evaluvate Cv\n",

+      "#intilization variable\n",

+      "t90=75.*24.*60.*60. ## time in sec\n",

+      "T90=0.848\n",

+      "Hd=1.5*100. ##in cm\n",

+      "Cv=T90*Hd**2/t90\n",

+      "print'%s %.3f %s'%('Cv =',Cv,' cm^2/sec')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Cv = 0.003  cm^2/sec\n"

+       ]

+      }

+     ],

+     "prompt_number": 15

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex10-pg337"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate K and t60\n",

+      "To=3000. ## lb/ft^2\n",

+      "eo=1.1\n",

+      "e1=0.9\n",

+      "e=eo-e1\n",

+      "ea=(eo+e1)/2.\n",

+      "T1=3000. ## lb/ft^2\n",

+      "T=1. ## in\n",

+      "t = 2. ## min\n",

+      "m=(e/T1)/(1.+ea)\n",

+      "U=50.\n",

+      "Tv=0.197\n",

+      "Gw=62.4 ##lb/ft^3\n",

+      "Cv=Tv*(T/(2.*12.)**2)/t\n",

+      "k=Cv*m*Gw *10**7\n",

+      "print'%s %.3f %s'%('a)k = ',k,' x10^-7 ft/min')\n",

+      "\n",

+      "\n",

+      "U=60\n",

+      "Tv=0.286\n",

+      "H=6\n",

+      "t60=Tv*H**2/(Cv*60*24)\n",

+      "print'%s %.1f %s'%(' b)t60 =',t60,' days')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)k =  3.557  x10^-7 ft/min\n",

+        " b)t60 = 41.8  days\n"

+       ]

+      }

+     ],

+     "prompt_number": 5

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex11-pg344"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the value of Cv\n",

+      "import math\n",

+      "#Cv\n",

+      "t50=19\n",

+      "Hd=2.24/2\n",

+      "Cv=0.197*Hd**2/t50\n",

+      "print'%s %.3f %s'%('Cv = ',Cv,' cm^2/min')\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "import math\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "t=numpy.array([.02,.1,.25,.5,1,2.,4.,8.,16.,30.,60.,120.,240.,480.,960.,1440.])\n",

+      "gauge=numpy.array([3975.,4082.,4102.,4128.,4166.,4224.,4298.,4420.,4572.,4737.,4923.,5080.,5207.,5283.,5334.,5364.])\n",

+      "Hdr=2.24\n",

+      "t50=19.\n",

+      "#calculations\n",

+      "Cv=.197*(Hdr/2)**2 /t50/60.\n",

+      "leng=len(t)\n",

+      "logt=numpy.zeros(leng)\n",

+      "for i in range(0,leng):\n",

+      "\tlogt[i]=math.log(t[i])\n",

+      "\n",

+      "#results\n",

+      "print 'The value of Cv (cm^2/sec) = ',Cv\n",

+      "pyplot.plot(logt,gauge)\n",

+      "pyplot.xlabel('Time(min) - log scale')\n",

+      "pyplot.ylabel('Dial reading (cm)')\n",

+      "pyplot.title('Graph of dial reading vs time')\n",

+      "pyplot.show()\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Cv =  0.013  cm^2/min\n",

+        "The value of Cv (cm^2/sec) =  0.000216769122807\n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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NS/4xcB3wLvC/5QzKrKO59FK44QaYNMnrZ1vr1GibhaRVgWkR0SZ6eLvNwtqi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\nTkSuQmCC\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x5dbcf50>"

+       ]

+      }

+     ],

+     "prompt_number": 16

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex12-pg346"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate SC\n",

+      "LL=40.\n",

+      "Cc=0.009*(LL-10)\n",

+      "H=10.*12.\n",

+      "eo=1.0\n",

+      "Gss=120.\n",

+      "Gsc=110.\n",

+      "Gd=100.\n",

+      "To=10.*Gd +10.*(Gss-62.4)+10.*(Gsc-62.4)/2.\n",

+      "\n",

+      "Tt=0.408\n",

+      "Tm=0.232\n",

+      "Tb=0.019\n",

+      "Tav= (Tt+4.*Tm+Tb)/6.\n",

+      "Sc=Cc*H*math.log10((To+Tav*1000.)/To)/(1.+eo)\n",

+      "print'%s %.3f %s'%('Sc =',Sc,' in')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Sc = 0.826  in\n"

+       ]

+      }

+     ],

+     "prompt_number": 8

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex13-pg356"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#intilization variable\n",

+      "#Calculate total primary\n",

+      "import math\n",

+      "H = 6.\n",

+      "Cc = 0.28\n",

+      "eo = 0.9\n",

+      "Cv = 0.36\n",

+      "To=210.\n",

+      "Tp=115.\n",

+      "Sc= Cc*H*math.log10((To+Tp)/To)/(1+eo)\n",

+      "t2=9.\n",

+      "Hd=3.\n",

+      "Tv=Cv*t2/Hd**2\n",

+      "U=0.67\n",

+      "Tf=0.677*Tp\n",

+      "print'%s %.1f %s'%('Tf =',Tf,' kN/m^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Tf = 77.9  kN/m^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 7

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter12.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter12.ipynb
new file mode 100755
index 00000000..cbcbfe36
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter12.ipynb
@@ -0,0 +1,325 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:72543990db7f8372d360761435a730b82b5eb7400e08be2b7657eafbc30628e4"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter12-Shear Strength of Soil"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg378"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine the relationships for peak shear strength(tf) and residual shear strength(tr).\n",

+      "D=50 ## in mm\n",

+      "A= math.pi/4. *(D/1000.)**2\n",

+      "## solving for test 1 \n",

+      "N=150.\n",

+      "Sp=157.5\n",

+      "Sr=44.2\n",

+      "Tf=Sp/A\n",

+      "Tr=Sr/A\n",

+      "## from graph\n",

+      "k=math.tan(27/57.3)\n",

+      "k1=math.tan(14.6/57.3)\n",

+      "\n",

+      "print'%s %.3f %s'%('Peak strength Tf = 40+ t*',k,'')\n",

+      "print'%s %.3f %s'%(' Residual strength Tr = t*',k1,'')\n",

+      "\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Peak strength Tf = 40+ t* 0.509 \n",

+        " Residual strength Tr = t* 0.260 \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg385"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine\n",

+      "#a.Angle of friction,f\u0004\n",

+      "#b.Angleuthat the failure plane makes with the major principal plane\n",

+      "T3=16. ## lb/in^2\n",

+      "Tf=25. ## lb/in^2\n",

+      "T1=T3+Tf\n",

+      "a= math.asin((T1-T3)/(T1+T3))*57.3 ## Mohr's circle\n",

+      "print'%s %.2f %s'%('a)Angle of friction,a = ',a,'')\n",

+      "b= 45.+ a/2.\n",

+      "print'%s %.2f %s'%(' b)Angle b that the failure plane makes with the major principal plane = ',b,'')\n",

+      "\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)Angle of friction,a =  26.02 \n",

+        " b)Angle b that the failure plane makes with the major principal plane =  58.01 \n"

+       ]

+      }

+     ],

+     "prompt_number": 9

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg386"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Find the normal stress s\u0004and the shear stress tfon the failure plane.\n",

+      "#b.Determine the effective normal stress on the plane of maximum shear stress\n",

+      "T1=41.\n",

+      "T3=16.\n",

+      "a=58.\n",

+      "T=(T1+T3)/2. + (T1-T3)*math.cos(2.*a/57.3)/2.\n",

+      "tf=(T1-T3)*math.sin(2.*a/57.3)/2\n",

+      "print'%s %.2f %s'%('a)the normal stress T = ',T,' lb/in^2')\n",

+      "print'%s %.2f %s'%('(b) and the shear stress tf = ',tf,' lb/in^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)the normal stress T =  23.02  lb/in^2\n",

+        "(b) and the shear stress tf =  11.24  lb/in^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 11

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg387"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#The equation of the effective stress failure envelope for normally consolidated clayey soilistf \u0001s\u0004tan 30\u0005. A drained triaxial test was conducted with the same soil at a chamberconfining pressure of 10 lb/in.2Calculate the deviator stress at failure.\n",

+      "##For normally consolidated clay, c' \u0004= 0.\n",

+      "a=30.\n",

+      "T3=10.\n",

+      "T1=T3*(math.tan(60/57.3))**2\n",

+      "Tf=T1-T3\n",

+      "print'%s %.2f %s'%('The deviator stress at failure = ',Tf,' lb/in^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The deviator stress at failure =  19.99  lb/in^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 12

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg387"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine the shear strength parameters.\n",

+      "T13=70.\n",

+      "T1f=130.\n",

+      "T11=T13+T1f\n",

+      "\n",

+      "T23=160.\n",

+      "T2f=223.5\n",

+      "T21=T23+T2f\n",

+      "\n",

+      "a= 2*(math.atan(((T11-T21)/(T13-T23))**0.5) *57.3-45)\n",

+      "c= (T11-T13*((math.tan((45+a/2.)/57.3))**2)/(2*math.tan(45+a/2.)/57.3))\n",

+      "d=c-267\n",

+      "print'%s %.2f%s'%('the shear strength parameter d = ',d,' kN/m^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "the shear strength parameter d =  20.69 kN/m^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex6-pg394"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Consolidated-undrained angle of shearing resistance,f\n",

+      "#b.Drained friction angle,f\u0004\n",

+      "T3=12.\n",

+      "Tf=9.1\n",

+      "T1=T3+Tf\n",

+      "u=6.8\n",

+      "a=math.asin((T1-T3)/(T1+T3))\n",

+      "\n",

+      "a1= math.asin((T1-T3)/(T1+T3-2*u))\n",

+      "\n",

+      "print'%s %.1f %s'%('a)Consolidated-undrained angle of shearing resistance = ',a*57.3,' degrees')\n",

+      "print'%s %.1f %s'%(' b)Drained friction angle =',a1*57.3,' degrees')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)Consolidated-undrained angle of shearing resistance =  16.0  degrees\n",

+        " b)Drained friction angle = 27.8  degrees\n"

+       ]

+      }

+     ],

+     "prompt_number": 13

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex7-pg395"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#What would be the deviatorstress at failure, (\u0010sd)f, if a drained test was conducted with the same chamber allaround pressure (that is, 12 lb/in.2)?\n",

+      "T3=12.\n",

+      "a=27.8\n",

+      "T1=T3*(math.tan(59./57.3))**2\n",

+      "Tf=T1-T3\n",

+      "print'%s %.1f %s'%('the deviator stress at failure = ',Tf,' lb/in^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "the deviator stress at failure =  21.2  lb/in^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 15

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex8-pg400"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Estimate the average undrained shear strength of the clay [that is,cu(VST)].\n",

+      "PI=28.\n",

+      "OCR=3.2\n",

+      "To=160.\n",

+      "Kn=0.11+0.0037*PI\n",

+      "Ko=OCR**0.8 * Kn\n",

+      "Cu=Ko*To\n",

+      "print'%s %.1f %s'%('the average undrained shear strength of the clay =',Cu,' kN/m^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "the average undrained shear strength of the clay = 86.7  kN/m^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 16

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter13.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter13.ipynb
new file mode 100755
index 00000000..20c28288
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter13.ipynb
@@ -0,0 +1,434 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:0e1b8f59fb3a5d8de0f3a9b8d0a65d58dfc4a0a36944d60860dc12f3ce3b3032"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter13-Lateral Earth Pressure: At-Rest, Rankine, and Coulomb"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-430"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Calculate the lateral force Poper unit length of the wall. Also, determine the location ofthe resultant force. Assume that for sand OCR\u00012\n",

+      "OCR=2.\n",

+      "a=30.\n",

+      "Ko=(1.-math.sin(a/57.3))*(OCR)**math.sin(a/57.3)\n",

+      "##at z=0\n",

+      "To1=0.\n",

+      "Th1=0.\n",

+      "u1=0.\n",

+      "##at z=10\n",

+      "To2=10.*100.\n",

+      "Th2=Ko*To2\n",

+      "u2=0.\n",

+      "##at z=15\n",

+      "To3= 10.*100.+5.*(122.4-62.4)\n",

+      "Th3=Ko*To3\n",

+      "u3=5.*62.4\n",

+      "##Lateral force Po =Area 1 +\u0007 Area 2+\u0007 Area3+\u0007 Area 4\n",

+      "Po =(1./2.)*10.*707.+5.*707.+(1./2.)*5.*212.1+(1/2.)*5.*312.\n",

+      "z=((3535.)*(5.+10./3.)+3535.*(5./2.)+530.3*(5./3.)+780.*(5./3.))/Po\n",

+      "print'%s %.1f %s'%('z = ',z,' ft')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "z =  4.8  ft\n"

+       ]

+      }

+     ],

+     "prompt_number": 7

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg449"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Rankine active force per unit length of the wall and the location of theresultant\n",

+      "#b.Rankine passive force per unit length of the wall and the location of the resultant\n",

+      "##c=0\n",

+      "a=36.\n",

+      "G=16.\n",

+      "Ka=(1.-math.sin(a/57.3))/(1.+math.sin(a/57.3))\n",

+      "##at z=0 Tp=0\n",

+      "z=6.\n",

+      "To=G*z\n",

+      "Ta=Ka*To\n",

+      "Pa=z*Ta/2.\n",

+      "\n",

+      "print'%s %.1f %s'%('a)Rankine active force per unit length of the wall = ',Pa,' kN/m')\n",

+      "print(' and the location of the resultant is z = 2m')\n",

+      "\n",

+      "\n",

+      "p=36.\n",

+      "G=16.\n",

+      "Kp=(1+math.sin(a/57.3))/(1-math.sin(a/57.3))\n",

+      "##at z=0 Tp=0\n",

+      "z=6.\n",

+      "To=G*z\n",

+      "Tp=Kp*To\n",

+      "Pp=z*Tp/2.\n",

+      "\n",

+      "print'%s %.1f %s'%(' b)Rankine passive force per unit length of the wall = ',Pp,' kN/m')\n",

+      "print (' and the location of the resultant is z = 2m')\n",

+      "\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)Rankine active force per unit length of the wall =  74.8  kN/m\n",

+        " and the location of the resultant is z = 2m\n",

+        " b)Rankine passive force per unit length of the wall =  1109.2  kN/m\n",

+        " and the location of the resultant is z = 2m\n"

+       ]

+      }

+     ],

+     "prompt_number": 8

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg450"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine the active force Paperunit length of the wall as well as the location and direction of the resultant.\n",

+      "H=12.\n",

+      "a=20.\n",

+      "b=20.\n",

+      "G=115.\n",

+      "c=30.\n",

+      "Oa= math.asin(math.sin(a/57.3)/math.sin(c/57.3))*57.3-a+2.*b\n",

+      "Ka= (math.cos((a-b)/57.3)*math.sqrt(1.+(math.sin(c/57.3))**2.-2.*math.sin(c/57.3)*math.cos(Oa/57.3)))/((math.cos(b/57.3))**2.*(math.cos(a/57.3)+math.sqrt((math.sin(c/57.3))**2.-(math.sin(a/57.3))**2)))\n",

+      "Pa=G*H**2.*Ka/2.\n",

+      "B= math.atan((math.sin(c/57.3)*math.sin(Oa/57.3))/(1.-(math.sin(c/57.3)*math.cos(Oa/57.3))))*57.3\n",

+      "print'%s %.1f %s'%('The active force Pa per unit length of the wall = ',Pa,' lb/ft')\n",

+      "print'%s %.1f %s'%( ' The resultant will act a distance of 12/3 = 4 ft above the bottom of the wall with B = ',B,' degree')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The active force Pa per unit length of the wall =  6423.5  lb/ft\n",

+        " The resultant will act a distance of 12/3 = 4 ft above the bottom of the wall with B =  30.0  degree\n"

+       ]

+      }

+     ],

+     "prompt_number": 9

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg451"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#determine the force per unit length of the wall for Rankine\u2019s active state. Also find the location of the resultant.\n",

+      "a=30.\n",

+      "Ka1=(1.-math.sin(a/57.3))/(1.+math.sin(a/57.3))\n",

+      "a=35.\n",

+      "Ka2=(1-math.sin(a/57.3))/(1+math.sin(a/57.3))\n",

+      "##at z=0 so T0=0\n",

+      "##atz=3\n",

+      "To=3.*16.\n",

+      "Ta1=Ka1*To\n",

+      "Ta2=Ka2*To\n",

+      "\n",

+      "## At z=6\n",

+      "To=3.*16.+3.*(18.-9.81)\n",

+      "Ta2=Ka2*To\n",

+      "\n",

+      "Pa =(1/2.)*3.*16.+3.*13.0+ (1/2.)*3.*36.1\n",

+      "z= (24 *(3.+3./3.)+39.0*(3/2.)+54.15*(3/3.))/Pa\n",

+      "print'%s %.1f %s'%('The force per unit length of the wall = ',Pa,' kN/m')\n",

+      "print'%s %.1f %s'% (' The location of the resultant = ',z,'m ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The force per unit length of the wall =  117.2  kN/m\n",

+        " The location of the resultant =  1.8 m \n"

+       ]

+      }

+     ],

+     "prompt_number": 10

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg453"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Maximum depth of the tensile crack\n",

+      "#b.Pabefore the tensile crack occurs\n",

+      "#c. Pa after the tensile crack occurs\n",

+      "Ka= (math.tan(1./57.3))**2.\n",

+      "G=16.5\n",

+      "cu=10.\n",

+      "H=6.\n",

+      "##at z=0\n",

+      "z=0.\n",

+      "Ta=G*z-2.*cu\n",

+      "##zt z=6\n",

+      "z=6.\n",

+      "Ta=G*z-2.*cu\n",

+      "\n",

+      "zo=2.*cu/G\n",

+      "## Before the tensile crack occurs\n",

+      "Pa= G*H**2./2. - 2.*cu*H\n",

+      "print'%s %.1f %s'%('Pa before the tensile crack occurs = ',Pa,' kN/m')\n",

+      "##After the tensile crack occurs\n",

+      "Pa=(H-zo)*Ta/2.\n",

+      "print'%s %.1f %s'%(' Pa after the tensile crack occurs = ',Pa,' kN/m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Pa before the tensile crack occurs =  177.0  kN/m\n",

+        " Pa after the tensile crack occurs =  189.1  kN/m\n"

+       ]

+      }

+     ],

+     "prompt_number": 11

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex6-pg457"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine the Rankine active force Paon the retaining wall after the tensile crack occurs.\n",

+      "H=15.\n",

+      "a=10.\n",

+      "G=118.\n",

+      "b=20.\n",

+      "C=250\n",

+      "Zo=2.*C*math.sqrt((1+math.sin(b/57.3))/(1.-math.sin(b/57.3)))/G\n",

+      "##at z=0 Ta=0\n",

+      "##at z=15 \n",

+      "z=15.\n",

+      "K=0.3\n",

+      "Ta=G*z*K*math.cos(a/57.3)\n",

+      "Pa=(H -Zo)*Ta/2.\n",

+      "print'%s %.1f %s'%('The Rankine active force Pa on the retaining wall after the tensile crack occurs = ',Pa,' lb/ft')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The Rankine active force Pa on the retaining wall after the tensile crack occurs =  2339.8  lb/ft\n"

+       ]

+      }

+     ],

+     "prompt_number": 13

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex7-pg459"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Estimate the active force,Pa , per unit length of the wall. Also, state the direction and location of the resultant force,Pa.\n",

+      "import math\n",

+      "c=30.\n",

+      "b=15.\n",

+      "a=10.\n",

+      "Ka=0.3872 ## from table 13.8\n",

+      "H=4.\n",

+      "G=15.\n",

+      "Pa=G*H**2.*Ka/2.\n",

+      "print'%s %.1f %s'%('The active force per unit length Pa = ',Pa,' kN/m')\n",

+      "print(' The resultant will act at a vertical distance equal to H/3 = 4/3 = 1.33 m above ' ' the bottom of the wall and will be inclined at an angle of 15\u0005to the back face of the wall.')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The active force per unit length Pa =  46.5  kN/m\n",

+        " The resultant will act at a vertical distance equal to H/3 = 4/3 = 1.33 m above  the bottom of the wall and will be inclined at an angle of 15\u0005to the back face of the wall.\n"

+       ]

+      }

+     ],

+     "prompt_number": 14

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex9-pg478"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine Pae.Also determine the location of the resultant line of action of Pae\u2014that is, .\n",

+      "kh=0.2\n",

+      "kv=0.\n",

+      "H=4.\n",

+      "a=0.\n",

+      "b=0.\n",

+      "c=15.\n",

+      "d=30.\n",

+      "G=15.5\n",

+      "B= math.atan(kh/(1-kv)/57.3)\n",

+      "b1=b+B\n",

+      "a1=a+B\n",

+      "Ka=0.452\n",

+      "Pa=G*H**2.*Ka/2.\n",

+      "Pae=Pa*(1.-kv)*((math.cos(b1/57.3))**2./((math.cos(b/57.3))**2.*(math.cos(B/57.3))**2.))\n",

+      "Ka=0.3014\n",

+      "Pa=G*H**2*Ka/2.\n",

+      "P1=Pae-Pa\n",

+      "z= ((Pa*H/3)+P1*0.6*H)/Pae\n",

+      "print'%s %.1f %s'%('Pae = ',Pae,' kN/m')\n",

+      "print'%s %.1f %s'%(' Z = ',z,' m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Pae =  56.0  kN/m\n",

+        " Z =  1.7  m\n"

+       ]

+      }

+     ],

+     "prompt_number": 15

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex10-pg479"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine the magnitude of the active force,Pae.\n",

+      "H=28.\n",

+      "C=210.\n",

+      "b=10.\n",

+      "G=118.\n",

+      "c=20.\n",

+      "kh=0.1\n",

+      "Ka=math.tan(35./57.3)\n",

+      "zo=2.*C/(G*(Ka))\n",

+      "n=zo/(H-zo)\n",

+      "Nac=1.60\n",

+      "Nav=0.375\n",

+      "L=1.17\n",

+      "Pae= G*(H-zo)**2*(L*Nav)-C*(H-zo)*Nac\n",

+      "print'%s %.1f %s'%('The magnitude of the active force, Pae = ',Pae,' lb/ft')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The magnitude of the active force, Pae =  19488.8  lb/ft\n"

+       ]

+      }

+     ],

+     "prompt_number": 16

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter14.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter14.ipynb
new file mode 100755
index 00000000..b6a23eb1
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter14.ipynb
@@ -0,0 +1,122 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:48c1632c9bf2565b11bcfc44de09d03ed2fce97fd897e255ae43ede2375057bf"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter14-Lateral Earth Pressure: Curved Failure Surface"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-497"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Coulomb\u2019s theory\n",

+      "#b.Terzaghi and Peck\u2019s wedge theory\n",

+      "#c. Shields and Tolunay\u2019s solution (method of slices)\n",

+      "#d.Zhu and Qian\u2019s solution (method of triangular slices)\n",

+      "G=15.7\n",

+      "a=0.\n",

+      "b=15.\n",

+      "c=30.\n",

+      "H=3.\n",

+      "Kp=4.977 ## from table 13.9\n",

+      "Pp=Kp*G*H**2./2.\n",

+      "print'%s %.1f %s'%('a)the passive force = ',Pp,' kN/m')\n",

+      "## for part b\n",

+      "Kp=4.53\n",

+      "Pp=Kp*G*H**2./2.\n",

+      "print'%s %.1f %s'%('b)the passive force = ',Pp,' kN/m')\n",

+      "## for part c\n",

+      "Kp=4.13\n",

+      "Pp=Kp*G*H**2/2.\n",

+      "print'%s %.1f %s'%('c)the passive force =',Pp,' kN/m')\n",

+      "##for part d\n",

+      "Kp=4.56\n",

+      "Pp=Kp*G*H**2/2.\n",

+      "print'%s %.1f %s'%('d)the passive force =',Pp,' kN/m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)the passive force =  351.6  kN/m\n",

+        "b)the passive force =  320.0  kN/m\n",

+        "c)the passive force = 291.8  kN/m\n",

+        "d)the passive force = 322.2  kN/m\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg507"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate the design strut loads.\n",

+      "G=16.\n",

+      "H=7.\n",

+      "c=30.\n",

+      "Ta=0.65*G*H*(math.tan(30./57.3))**2\n",

+      "A=Ta*3.*3./4.\n",

+      "B1=Ta*3.-54.61\n",

+      "C=Ta*4.*4./4.\n",

+      "B2=Ta*4.-97.08\n",

+      "s=2.\n",

+      "As=A*s\n",

+      "Bs=(B1+B2)*s\n",

+      "Cs=C*s\n",

+      "print'%s %.1f %s'%( 'The strut loads at level A = ',As,' kN')\n",

+      "print'%s %.1f %s'%( ' The strut loads at level B = ',Bs,' kN')\n",

+      "print'%s %.1f %s'%( ' The strut loads at level C =',Cs,' kN')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The strut loads at level A =  109.2  kN\n",

+        " The strut loads at level B =  36.3  kN\n",

+        " The strut loads at level C = 194.1  kN\n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter15.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter15.ipynb
new file mode 100755
index 00000000..04d58e71
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter15.ipynb
@@ -0,0 +1,499 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:4c2cef1cd7673363b2ef6cb15cb908c88921a9f728253dd7a799bca223f736c1"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter15-Slope Stability"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg518"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.The factor of safety against sliding along the soil-rock interface.\n",

+      "#b.The height,H, that will give a factor of safety (Fs) of 2 against sliding alongthe soil-rock interface.\n",

+      "Gs=17.8\n",

+      "Gw=9.81\n",

+      "C=10.\n",

+      "c=20.\n",

+      "b=15.\n",

+      "H=6.\n",

+      "G=Gs-Gw\n",

+      "Fs= C/(Gs*H*math.cos(b/57.3)*math.cos(b/57.3)*math.tan(b/57.3))+G*math.tan(c/57.3)/(Gs*math.tan(b/57.3))\n",

+      "print'%s %.2f %s'%('a)The factor of safety = ',Fs,' ')\n",

+      "Fs=2.\n",

+      "H=2.247/(Fs-0.61)\n",

+      "print'%s %.2f %s'%(' b)H= ',H,' m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)The factor of safety =  0.98  \n",

+        " b)H=  1.62  m\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg529"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Determine the maximum depth up to which the excavation can be carried out.\n",

+      "#b.Find the radius,r, of the critical circle when the factor of safety is equal to 1(Part a).\n",

+      "#c. Find the distance  . BC\n",

+      "Cu=40.\n",

+      "G=17.5\n",

+      "b=60.\n",

+      "a=35.\n",

+      "c=72.5\n",

+      "m=0.195\n",

+      "Hc=Cu/(G*m)\n",

+      "r=Hc/(2.*math.sin(a/57.3)*math.sin((c/2)/57.3))\n",

+      "BC=Hc*((1./math.tan(a/57.3))-(1./math.tan(b/57.3)))\n",

+      "print'%s %.1f %s'%('a)The maximum depth Hc = ',Hc,' m')\n",

+      "print'%s %.2f %s'%(' b)The radius, r = ',r,' m')\n",

+      "print'%s %.3f %s'%(' c)The distance BC.= ',BC,' m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)The maximum depth Hc =  11.7  m\n",

+        " b)The radius, r =  17.28  m\n",

+        " c)The distance BC.=  9.973  m\n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg531"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Determine the undrained cohesion of the clay (Figure 15.13).\n",

+      "#b.What was the nature of the critical circle?\n",

+      "#c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?\n",

+      "Gs=17.29\n",

+      "d=9.15\n",

+      "d1=6.1\n",

+      "D=d/d1\n",

+      "a=40.\n",

+      "m=0.175\n",

+      "b=40.\n",

+      "H=6.1\n",

+      "Cu=H*Gs*m\n",

+      "print'%s %.1f %s'%('a)The undrained cohesion of the clay Cu = ',Cu,' kN/m^2')\n",

+      "print(' b)The nature of the critical circle is midpointcircle')\n",

+      "d=1.5\n",

+      "b=40.\n",

+      "n=0.9\n",

+      "D1=n*H\n",

+      "print'%s %.1f %s'%(' c)Distance = ',D1,' m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)The undrained cohesion of the clay Cu =  18.5  kN/m^2\n",

+        " b)The nature of the critical circle is midpointcircle\n",

+        " c)Distance =  5.5  m\n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg534"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Determine the maximum depth up to which the cut could be made.\n",

+      "#b.How deep should the cut be made if a factor of safety of 2 against sliding is required\n",

+      "Fs=1.\n",

+      "b=56.\n",

+      "Kh=0.25\n",

+      "M=3.66\n",

+      "Cu=500.\n",

+      "G=100.\n",

+      "Hc=Cu*M/G\n",

+      "print'%s %.1f %s'%('a)The maximum depth =',Hc,' ft')\n",

+      "Fs=2.\n",

+      "H=Cu*M/(G*Fs)\n",

+      "print'%s %.1f %s'%(' b)H= ',H,' ft')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)The maximum depth = 18.3  ft\n",

+        " b)H=  9.2  ft\n"

+       ]

+      }

+     ],

+     "prompt_number": 5

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex6-pg541"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#a.Find the critical height of the slope.\n",

+      "#b.If the height of the slope is 10 m, determine the factor of safety with respect to strength.\n",

+      "b=45.\n",

+      "c=20.\n",

+      "C=24.\n",

+      "G=18.9\n",

+      "m=0.06\n",

+      "Hc=C/(G*m)\n",

+      "Cd=G*Hc*m\n",

+      "Fc=C/Cd\n",

+      "print'%s %.1f %s'%('a)Critical height of slope = ',Hc,'')\n",

+      "#calculate the factor of safety using spencers solution\n",

+      "import math\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "phid=numpy.array([20,15,10,5])*math.pi/180.\n",

+      "mx=numpy.array([.06,.083,.105,.136])\n",

+      "cdx=numpy.array([11.34,15.69,19.85,25.7])\n",

+      "m=.06\n",

+      "g=18.9\n",

+      "cd=24.\n",

+      "#calculations\n",

+      "Hcr=cd/g/m\n",

+      "leng=len(phid)\n",

+      "Fcd=numpy.zeros(leng)\n",

+      "Fphi=numpy.zeros(leng)\n",

+      "tanphid=numpy.zeros(leng)\n",

+      "for i in range(0,leng):\n",

+      "\ttanphid[i]=math.tan(phid[i])\n",

+      "\tFphi[i]= tan(phid[0])/tan(phid[i])\n",

+      "\tFcd[i]=cd/cdx[i]\n",

+      "\n",

+      "\n",

+      "#results\n",

+      "print'%s %.2f %s'%('The value of Hcr (in m) = ',Hcr,'')\n",

+      "print 'from graph, Fss=1.4'\n",

+      "pyplot.plot(Fcd,Fphi)\n",

+      "pyplot.xlabel('Fc assumed')\n",

+      "pyplot.ylabel('Fc calculated')\n",

+      "pyplot.title('Graph of Fc assumed vs Fc calculated')\n",

+      "pyplot.show()\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)Critical height of slope =  21.2 \n",

+        "The value of Hcr (in m) =  21.16 \n",

+        "from graph, Fss=1.4\n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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dBxddBEcfnW4Xamb5qdZeSQJuBGaWSgqZe4Ejs+33Al4vTApWGzbeGH7yE7j/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\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x2d2ff30>"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex7-pg544"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "# using Michalowski\u2019s solution.\n",

+      "import math\n",

+      "FSs=1.\n",

+      "c=20.\n",

+      "G=18.9\n",

+      "C=24.\n",

+      "Hcr=C/(G*math.tan(c/57.3)*0.17)\n",

+      "print'%s %.1f %s'%('a)Critical height Hc = ',Hcr,' m')\n",

+      "H=10.\n",

+      "k=C/(G*H*math.tan(c/57.3))\n",

+      "Fs=4.*math.tan(c/57.3)\n",

+      "print'%s %.1f %s'%(' b)Fs = ',Fs,'')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "a)Critical height Hc =  20.5  m\n",

+        " b)Fs =  1.5 \n"

+       ]

+      }

+     ],

+     "prompt_number": 7

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex8-pg560"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "# Determine the factor ofsafety,Fs . Use Table 15.3.\n",

+      "W=22.4\n",

+      "C=20.\n",

+      "a=70.\n",

+      "s=math.sin(a/57.3)\n",

+      "c=math.cos(a/57.3)\n",

+      "l=2.924\n",

+      "Wn=W*s\n",

+      "Wn1=W*c\n",

+      "##doing this to all values\n",

+      "F1=30.501\n",

+      "F2=776.75\n",

+      "F3=1638.\n",

+      "Fs=(F1*C+F3*math.tan(C/57.3))/F2\n",

+      "print'%s %.2f %s'%('Fs = ',Fs,'')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Fs =  1.55 \n"

+       ]

+      }

+     ],

+     "prompt_number": 8

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex9-pg560"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#using Michalowski\u2019s solution\n",

+      "C=20.\n",

+      "G=18.5\n",

+      "r=0.25\n",

+      "H=21.62\n",

+      "C=25.\n",

+      "b= math.atan(0.5)\n",

+      "##from table 15.3 \n",

+      "m=1.624\n",

+      "n=1.338\n",

+      "Fs=m-n*r\n",

+      "print'%s %.1f %s'%(' The value of Fs for D= 1 is',Fs,'')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        " The value of Fs for D= 1 is 1.3 \n"

+       ]

+      }

+     ],

+     "prompt_number": 9

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex10-pg561"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the factor of safety using spencers solution\n",

+      "import math\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "beta=numpy.array([26.57,26.57,26.57,26.57])\n",

+      "Fs=numpy.array([1.1,1.2,1.3,1.4])\n",

+      "phid=25*math.pi/180. #degrees\n",

+      "#calculations\n",

+      "print 'From spencers graphs,'\n",

+      "cd=numpy.array([0.0455,0.0417,0.0385,0.0357])\n",

+      "phia=numpy.array([18.,19.,20.,21.])*math.pi/180.\n",

+      "leng=len(phia)\n",

+      "Fss=numpy.zeros(leng)\n",

+      "for i in range(0,leng):\n",

+      "\tFss[i]= tan(phid)/tan(phia[i])\n",

+      "\n",

+      "#results\n",

+      "print 'From graph, a footing of dimensions Fs=1.3'\n",

+      "pyplot.plot(Fs,Fss)\n",

+      "pyplot.xlabel('Fs assumed')\n",

+      "pyplot.ylabel('Fs calculated')\n",

+      "pyplot.title('Graph of Fs assumed vs Fs calculated')\n",

+      "pyplot.show()"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "From spencers graphs,\n",

+        "From graph, a footing of dimensions Fs=1.3\n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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tchuHWfu88AIcdVSaRPGss2DPPVNysdrmpWOrOH6zSlFfn7rvrrxyag8ZstSQ\nXaslHTI7rpnVtro6eOyxVOLYYYc0hfvbb5c7KqtUThxmBqQuuocckto/Fi9Oc2H94Q/puVkuV1WZ\nWZNmzkzVVwsXpuqrkSPLHZEVi9s4qjh+s0oXAddckxrQt9kGzjgD1l679c9ZZXMbh5mVjAT77JOq\nrzbYIM15dfLJ8OGHrX/WapcTh5m1qmdPOPFEeOQRmDEDBgyASy6BTz8td2RWDq6qMrOCPfggHHMM\nvPYanHIK7L67x39UE7dxVHH8ZtUsAu66Ky0a1a0bnHZa6sprlc+Jo4rjN6sFS5bAtdfCccdBv34p\ngXz1q+WOylrixnEzK6suXVID+ty5aQDhrrumCRSffLLckVmpOHGYWVEsswyMHQtPPQWbbZYWkxoz\nBl56qdyRWbE5cZhZUS2/fGo4/9e/YJVVYNiwNA7kP/8pd2RWLE4cZlYSffum9o7Zs2HRIhg4MPXA\nWrSo3JFZezlxmFlJrbkmXHghPPAAzJmTBhL+/vfw8cfljszayonDzDrEBhvA5Mlw221wyy2w4YZw\n5ZWpV5ZVF3fHNbOyqK9PY0A++ABOPRW+/W0PIuwoHsdRxfGbdXYRcNNNcOyxsNJKqU3ka18rd1S1\nz+M4zKxqSWncx6xZ8KMfwf77w847p9dWuZw4zKzsunaFH/wgdeH95jfT43vfg2efLXdk1hQnDjOr\nGN27wxFHwNNPp8b0zTeHQw9Nkyla5XDiMLOK06sXjB8P8+enEemDB6e5sBYuLHdkBk4cZlbBVl0V\nzj0XHnsMXn45lULOOssLSZWbE4eZVbyvfAUmTYJ//APuvz8tJHXxxV5IqlzcHdfMqk7uQlInnwx7\n7OExIIXwOI4qjt/M2i53IamuXdMYkG98o9xRVQcnjiqO38zar/FCUqeemnpjWfM8ANDMOrXGC0nt\ntlv6d/78ckdWu5w4zKwm5C4kNWIEbLttGo3+4ovljqz2OHGYWU1Zfnk4+ug0Cv1LX4JNNoGf/cwL\nSRVTyRKHpEslvS5pdjP795c0U9IsSfdLGpqz7/ls+wxJD5UqRjOrXX37pvaOOXPSDLwDB6YeWF5I\nqv1KWeKYBIxuYf+zwMiIGAqcBFyUsy+AuogYHhEjShijmdW4NdaACy5IXXjnzk2DCH/3Oy8k1R4l\nSxwRMRVY0ML+ByKiYQKB6cCXG73FvbLNrGjWXx+uuiotJHXbbWkhqSuugMWLyx1Z9amUNo6DgNty\nXgdwt6QaRKkyAAAKgUlEQVRHJI0pU0xmVoOGD0+JY9KkVBIZPjytSOie/fnrVu4AJH0dOBDYJmfz\nNhHxqqRVgSmS5mclmKVMmDDhs+d1dXXU1dWVMFozqxXbbZemL7n55jQK/de/To9aXEiqvr6e+vr6\noh2vpAMAJfUDbo6IIc3sHwrcAIyOiKebec94YFFEnN3EPg8ANLN2W7w4rX9+wgmw8capUX3o0NY/\nV62qdgCgpHVISeN7uUlD0vKSemXPewKjgCZ7ZpmZFUPXrnDAAfDkkzBqVHp4IanmlbI77mRgGjBQ\n0ouSDpQ0VtLY7C0nAH2BCxt1u10dmCrpcVKj+S0RcVep4jQza9C9Oxx+eBpEOGCAF5JqjueqMjNr\nxptvpskTL7sMxo2Do46CPn3KHVX7VW1VlZlZpVt1VTjnHJgxA155xQtJNXDiMDNrxTrrwKWXQn09\nTJvmhaRcVWVmVqDp01MX3ldegVNOqb6FpLweRxXHb2bVKwKmTEkLSUlpDEi1LCTlxFHF8ZtZ9Vuy\nBK67Li0ktfbaqTF9RIXPsOfGcTOzMurSBfbeG554AvbdF3bfPVVdzZtX7shKx4nDzKwIllkGxoxJ\nY0C23BJGjoSDDqrNhaScOMzMimi55dJ4j6eegtVXTwtJHXkkvPVWuSMrHicOM7MSWHHF1ONqzhz4\n6KM0jftJJ9XGQlJOHGZmJbTGGvD736cuvPPmpXVBzj+/uheScuIwM+sA/funhaTuuANuv726F5Jy\nd1wzszK49940BmTRojSN+047ddwgQo/jqOL4zaxzi0gLSR17bGoTOe002Hbb0p/XiaOK4zczg88X\nkho/HjbaKJVAhg0r3fk8ANDMrMo1LCQ1fz6MHg077gj77w/PPFPuyJrmxGFmViG6d4fDDktjQDbc\nELbYAg45pPIWknLiMDOrML16wfHHpxJIjx4weDD88pfwzjvljixx4jAzq1CrrAJnn50WknrttbQO\nyJlnln8hKScOM7MKt846cMklqQvvgw+mlQgnTizfQlLuVWVmVmWmT09jQF5+GU4+Oc3G26WAYoC7\n41Zx/GZmbRUBd9+dViKU0hiQb3wjv0GEThxVHL+ZWXstWQLXX58az/NdSMrjOMzMOrEuXWCvvTp2\nISknDjOzGtB4IanttksLSb3wQvHP5cRhZlZDGhaS+te/0kJSw4cXfyEpJw4zsxpUyoWk3DhuZtYJ\nPPMMnHAC3HcfvPSSe1WVOwwzs6rxyiuw1lpOHOUOw8ysqrg7rpmZdSgnDjMzK4gTh5mZFcSJw8zM\nCuLEYWZmBXHiMDOzgpQscUi6VNLrkmY3s39/STMlzZJ0v6ShOftGS5ov6SlJPy9VjGZmVrhSljgm\nAaNb2P8sMDIihgInARcBSOoK/C777EbAfpIGlTDOilVfX1/uEEqmlq8NfH3Vrtavr71KljgiYiqw\noIX9D0TEwuzldODL2fMRwNMR8XxEfAJcDexaqjgrWS3/8NbytYGvr9rV+vW1V6W0cRwE3JY9Xwt4\nMWffS9k2MzOrAN3KHYCkrwMHAttkmzyHiJlZBSvpXFWS+gE3R8SQZvYPBW4ARkfE09m2LYEJETE6\ne/0LYElEnN7E551kzMzaoD1zVZWtxCFpHVLS+F5D0sg8AmyQJZ1XgH2A/Zo6Rnsu3MzM2qZkiUPS\nZGA7YBVJLwLjgWUAIuKPwAlAX+BCSQCfRMSIiPhU0qHAnUBX4JKIKOHquWZmVoiqnlbdzMw6XqX0\nqvpMHgMHN5T0gKSPJB3ZaF/FDxxs5/U9nw2YnCHpoY6JuDC1PvCznddXC/dv1+z6Zkh6VNL2Oftq\n4f61dH0Vff9au7ac920u6VNJe+RsK+zeRURFPYBtgeHA7Gb2rwp8FTgZODJne1fgaaAfqUrscWBQ\nua+nWNeX7XsOWKnc19DO69sK6JM9Hw08WGP3r8nrq6H71zPn+RDSmKtaun9NXl813L/Wri3nPt0D\n3ALs0dZ7V3Eljmh94OCbEfEI8EmjXVUxcLAd19egojsE5HF9VT3wsx3X16Da79/7OS9XAN7KntfK\n/Wvu+hpU7P1r7doyhwHXAW/mbCv43lVc4miHzjBwMIC7JT0iaUy5gymCWh/4mXt9UCP3T9JukuYB\ntwOHZ5tr5v41c31Q5fdP0lqkhHBhtqmhgbvge1f2AYBF1Bla+beJiFclrQpMkTQ/+yuj6tT6wM8m\nrg9q5P5FxF+Bv0raFrhc0obljqmYGl8fMDDbVe337zzgmIgIpa6sDaWngv/v1VKJ42Vg7ZzXa5My\nZ82IiFezf98EbiQVMatO1mA8EfhORDQUrWvm/jVzfTVz/xpkvzS7ASuR7lVN3L8GDdcnaeXsdbXf\nv82AqyU9B+wBXCDpO7Th/141J47GdY2fDRyUtCxp4OBNHR9W0Xzh+iQtL6lX9rwnMAposfdEJcpn\n4Gc137/mrq+G7l//7K9VJG0KEBH/oXbuX5PXVwv3LyLWi4h1I2JdUjvHuIi4iTbcu4qrqlIrAwcl\nrQ48DPQGlkg6AtgoIhapCgYOtvX6gC8BN2Q/092AKyPirjJcQotauz6qfOBnW68PWJ3auH97AAdI\n+gRYBOyb7auV+9fk9VEF9y+Pa2tSW+6dBwCamVlBqrmqyszMysCJw8zMCuLEYWZmBXHiMDOzgjhx\nmJlZQZw4zMysIE4c1ilIWpxNh93wWKfcMRWTpD/lTpNtVkoVNwDQrEQ+iIjh5Q6ihIIam+/LKpdL\nHNZpSRosaXpWApkpaf0m3nOBpIclzZE0IWf7ryU9kX3ujGzbXpJmS3pcUn227YeSzs/53C2SRmbP\nF0k6Izv2FElbSrpX0jOSdsne01XSmZIeys7142y7JP1OafGdKaSZBSp2ym+rLS5xWGexnKQZ2fNn\nI2IP4GDgNxFxlaRuNP3/4ZcRsUBSV9KU2kOAV4DdImJDAEm9s/ceD4zKZlBt2Na4FJD7enng7xFx\ntKQbgBOB7YHBwGXAzaSp2d+JiBGSugP/lHQXsCkwABhEmg5jLnBJW74Ys0I5cVhn8WETVVXTgF9K\n+jJwQ6NJFxvso7T2QjdgDdIv6rnAR5IuIa2kdkv23vuByyRdQ5rosDUfR8Sd2fPZwEcRsVjSHNJq\nbJAm0xsiac/sdW9gA9Jqb1dFmjPoVUn35HE+s6JwVZV1WhExGdgF+BC4TWkNjc9IWhc4Etg+IoYB\ntwLLRcRi0pTa1wE7A3dkxxsHHEealvpRSSsBn/LF/2c9cp7nrvK4BPg4O84SvvhH3aERMTx79I+I\nKQ0htvnizdrBicM6LUnrRsRzEXE+8DfSGtO5egPvA+9KWg34FhDZtNorRsTtwE+BYdnx+kfEQxEx\nnrQ055eB54FNsjaJtSl8DYc7gf+XVaUhaYCk5YH7SKWhLpLWAL7e0kHMislVVdZZNNXjaG9J3yf9\n5f8qcMoXPhAxM2sXmU9aWvOf2a5ewN8k9SD91f+TbPsZkjbItt0dEbMAlBbOmQvMAx5tIaZo4vnF\npGqrx7J1It4gta/cKGn77LgvkKrdzDqEp1U3M7OCuKrKzMwK4sRhZmYFceIwM7OCOHGYmVlBnDjM\nzKwgThxmZlYQJw4zMyuIE4eZmRXk/wN5SXo27nRWHQAAAABJRU5ErkJggg==\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x5567810>"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex11-pg561"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#using Michalowski\u2019s solution\n",

+      "C=20.\n",

+      "G=18.5\n",

+      "H=21.62\n",

+      "c=25.\n",

+      "r=0.25\n",

+      "Fs=3.1*math.tan(c/57.3)\n",

+      "print'%s %.1f %s'%('Fs = ',Fs,'')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Fs =  1.4 \n"

+       ]

+      }

+     ],

+     "prompt_number": 10

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter16.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter16.ipynb
new file mode 100755
index 00000000..892e5d4d
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter16.ipynb
@@ -0,0 +1,355 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:f8ccaea2f8e2185eadf01a8580109480d61ddd5c9965256b8487bceaf5d3f50f"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter16-Soil-Bearing Capacity for Shallow Foundations"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg587"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#determine the gross allowable load per unit area (qall) that the foundation can carry.\n",

+      "import math\n",

+      "c=20.\n",

+      "## from table 16.1\n",

+      "Nc=17.69\n",

+      "Nq=7.44\n",

+      "Ng=3.64\n",

+      "\n",

+      "Df=3.\n",

+      "G=110.\n",

+      "q=G*Df\n",

+      "\n",

+      "C=200.\n",

+      "B=4.\n",

+      "\n",

+      "Qu= C*Nc+q*Nq+G*B*Ng/2.\n",

+      "\n",

+      "Fs=3.\n",

+      "Qall=Qu/Fs\n",

+      "print'%s %.1f %s'%('Qa = ',Qall,' lb/ft^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Qa =  2264.7  lb/ft^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 6

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg588"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#determine the size of the footing\u2014that is, the size of B.\n",

+      "G=18.15\n",

+      "qa=30000.*9.81/1000.\n",

+      "\n",

+      "Nc=57.75\n",

+      "Nq=41.44\n",

+      "Ng=45.41\n",

+      "C=0.\n",

+      "q=G*1.\n",

+      "B=1.\n",

+      "(1.3*C*Nc+q*Nq+0.4*G*B*Ng)*B**2/3. == qa\n",

+      "B= math.sqrt(294.3/(250.7+109.9))\n",

+      "print'%s %.1f %s'%(' B = ',B,' m')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        " B =  0.9  m\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg595"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "# Determine the safe gross load (factor of safety of 3) that the footing can carry\n",

+      "B=1.2\n",

+      "L=1.2\n",

+      "c=32.\n",

+      "C=0.\n",

+      "Df=1.\n",

+      "G=16.\n",

+      "Nq=23.18\n",

+      "Ng=22.02\n",

+      "Nc=1.\n",

+      "Lqs=1.+0.1*B*(math.tan(61./57.3)**2.)/L\n",

+      "Lgs=Lqs\n",

+      "Lqd=1.+0.1*Df*math.tan(61./57.3)/B\n",

+      "Lgd=Lqd\n",

+      "Lcs=1.\n",

+      "Lcd=1.\n",

+      "Gs=19.5\n",

+      "q=0.5*G+0.5*(Gs-9.81)\n",

+      "Qu= C*Lcs*Lcd*Nc+q*Lqs*Lqd*Nq+(Gs-9.81)*Lgs*Lgd*B*Ng/2.\n",

+      "Qa=Qu/3.\n",

+      "Q=Qa*B**2.\n",

+      "print'%s %.1f %s'%('the gross load = ',Q,' kN')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "the gross load =  311.6  kN\n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg601"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Determine the magnitude of the gross ultimate load applied eccentrically for bearing capacity failure in soil.\n",

+      "e=0.1\n",

+      "B=1.\n",

+      "X=B-2.*e\n",

+      "Y=1.5\n",

+      "B1=0.8\n",

+      "L1=1.5\n",

+      "c=30.\n",

+      "Df=1.\n",

+      "Nq=18.4\n",

+      "Ng=15.668\n",

+      "q=1.*18.\n",

+      "G=18.\n",

+      "Lqs=1.+e*(B1/L1)*math.tan(60./57.3)**2.\n",

+      "Lgs=Lqs\n",

+      "Lqd=1.+e*(Df/B1)*math.tan(60./57.3)\n",

+      "Lgd=Lqd\n",

+      "qu=q*Lqs*Lqd*Nq+Lgs*Lgd*G*B1*Ng/2.\n",

+      "Qu=qu*B1*L1\n",

+      "print'%s %.1f %s'%('The magnitude of the gross ultimate load =',Qu,' kN')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The magnitude of the gross ultimate load = 751.8  kN\n"

+       ]

+      }

+     ],

+     "prompt_number": 4

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg601"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#determine the gross ultimate load per unit length that the foundation can carry.\n",

+      "import math\n",

+      "B=1.5\n",

+      "Df=0.75\n",

+      "e=0.1*B\n",

+      "G=17.5\n",

+      "c=30.\n",

+      "C=0.\n",

+      "q=G*Df\n",

+      "Nq=18.4\n",

+      "Ng=15.668\n",

+      "Lqd=1.+0.1*(Df/B)*math.tan(60./57.3)\n",

+      "Lgd=Lqd\n",

+      "Quc=q*Nq*Lqd+Lgd*B*Ng/2.\n",

+      "k=0.8\n",

+      "a=1.754\n",

+      "Qua=Quc*(1.-a*(e/B)**k)\n",

+      "print'%s %.1f %s'%('The gross ultimate load per unit length = ',Qua,' kN')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The gross ultimate load per unit length =  198.7  kN\n"

+       ]

+      }

+     ],

+     "prompt_number": 5

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex6-pg606"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#Estimate the ultimate bearing capacity of a circular footing with a diameter of 1.5 m. The soil is sandy.\n",

+      "Qup=280.\n",

+      "Bp=0.7 ## in m\n",

+      "Bf=1.5\n",

+      "Quf=Qup*Bf/Bp\n",

+      "print'%s %.1f %s'%('The ultimate bearing capacity = ',Quf,' kN/m^2')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The ultimate bearing capacity =  600.0  kN/m^2\n"

+       ]

+      }

+     ],

+     "prompt_number": 7

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex7-pg606"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the value of Cv\n",

+      "import math\n",

+      "#Determine the size of a square column foundation that should carry a load of 2500 kN with a maximum settlement of 25 mm.\n",

+      "a=2500.\n",

+      "##doing for the first values only\n",

+      "Bf=4.\n",

+      "Bp=0.305\n",

+      "q=a/Bf**2.\n",

+      "Sep=4.\n",

+      "Sef=Sep*(2.*Bf/(Bf+Bp))**2\n",

+      "print'%s %.1f %s'%('Sef = ',Sef,' mm')\n",

+      "import math\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "t=numpy.array([.02,.1,.25,.5,1,2.,4.,8.,16.,30.,60.,120.,240.,480.,960.,1440.])\n",

+      "gauge=numpy.array([3975.,4082.,4102.,4128.,4166.,4224.,4298.,4420.,4572.,4737.,4923.,5080.,5207.,5283.,5334.,5364.])\n",

+      "Hdr=2.24\n",

+      "t50=19.\n",

+      "#calculations\n",

+      "Cv=.197*(Hdr/2)**2 /t50/60.\n",

+      "leng=len(t)\n",

+      "logt=numpy.zeros(leng)\n",

+      "for i in range(0,leng):\n",

+      "\tlogt[i]=math.log(t[i])\n",

+      "\n",

+      "#results\n",

+      "print'%s %.4f %s'%('The value of Cv (cm^2/sec) = ',Cv,'')\n",

+      "pyplot.plot(logt,gauge)\n",

+      "pyplot.xlabel('Time(min) - log scale')\n",

+      "pyplot.ylabel('Dial reading (cm)')\n",

+      "pyplot.title('Graph of dial reading vs time')\n",

+      "pyplot.show()\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Sef =  13.8  mm\n",

+        "The value of Cv (cm^2/sec) =  0.0002 \n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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NS/4xcB3wLvC/5QzKrKO59FK44QaYNMnrZ1vr1GibhaRVgWkR0SZ6eLvNwtqi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\nTkSuQmCC\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x54c9290>"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter18.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter18.ipynb
new file mode 100755
index 00000000..9672dd94
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter18.ipynb
@@ -0,0 +1,124 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:bd1dfbb2f3a2374bd2f13d65956d903f168b0ff4075bd14d19db0d9e2d866f17"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter18-Subsoil Exploration"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg642"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Determine the correctedstandard penetration numbers, (N1)60, at various depths\n",

+      "import math\n",

+      "##solving for z=5 only\n",

+      "To=0.275\n",

+      "Cn=To**(-0.5)\n",

+      "N60=8\n",

+      "N160=Cn*N60\n",

+      "print'%s %.1f %s'%('(N1)60 = ',N160,'')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "(N1)60 =  15.3 \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg643"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#estimate the average soil friction angle,f\u0003, from z\u00020 to z\u000225 ft\n",

+      "#import math\n",

+      "z=5.\n",

+      "To=0.275\n",

+      "Cn=2./(1.+To)\n",

+      "N60=8.\n",

+      "N160=Cn*N60\n",

+      "print'%s %.1f %s'%('(N1)60 = ',N160,'')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "(N1)60 =  12.5 \n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg643"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#estimate the average soil friction angle, f\u0003, from z\u00020 to z\u000225 ft\n",

+      "import math\n",

+      "pa=1. ## 14.7 lb/in**2 = 1ton/ft**2\n",

+      "To=0.275 ## ton/ ft**2\n",

+      "N60=8.\n",

+      "c= math.atan((N60/12.2+20.3*(To/pa))*57.3)**0.34\n",

+      "print'%s %.1f %s'%('The average soil friction angle = ',c,'')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The average soil friction angle =  1.2 \n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter2.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter2.ipynb
new file mode 100755
index 00000000..57ee4839
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter2.ipynb
@@ -0,0 +1,122 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:5e11f0622a3e8a49d45f7bf47ce2fb320225cef1a5e74b45071c152843296e82"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter2-Origin of Soil and Grain Size"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg44"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the values and plot the graph\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "import math\n",

+      "\n",

+      "from math import log\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "e=numpy.array([100,94.5,86.3,74.1,54.9,38.1,9.3,1.7,0])\n",

+      "p=numpy.array([4.75,2.00,0.850,0.425,0.250,0.180,0.150,0.075,0])\n",

+      "\n",

+      "#calculations\n",

+      "\n",

+      "\n",

+      "#results\n",

+      "\n",

+      "pyplot.plot(p,e)\n",

+      "pyplot.xlabel('Particle size ')\n",

+      "pyplot.ylabel('percent finer ,e')\n",

+      "pyplot.title('Graph of particle size vs percent finer')\n",

+      "pyplot.show()\n",

+      "print('look at the axis reverse in text book')"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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JwMzMUETkHUPFJEVP8b74IkyeDEuWuAHZzKxAEhGhnpYZUlcGN90ELS1OBGZm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\nJwMzM8PJwMzMcDIwMzPg/wPeMGYYyyrVSwAAAABJRU5ErkJggg==\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x5464ab0>"

+       ]

+      },

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "look at the axis reverse in text book\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg45"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate uniformity coefficient and coefficient of gradation\n",

+      "##initialisation of variables\n",

+      "##from graph\n",

+      "d= 0.15 ##mm\n",

+      "w= 0.17 ##mm\n",

+      "a= 0.27 ##mm\n",

+      "##calculations\n",

+      "C= a/d\n",

+      "c= w**2/(a*d)\n",

+      "##results\n",

+      "print'%s %.1f %s'%('uniformity coefficient = ',C,\"\")\n",

+      "print'%s %.2f %s'% ('coefficient of gradation = ',c,' ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "uniformity coefficient =  1.8 \n",

+        "coefficient of gradation =  0.71  \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter3.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter3.ipynb
new file mode 100755
index 00000000..d0ebca76
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter3.ipynb
@@ -0,0 +1,199 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:60c2fa50959c5a4dba9df5cf01a73aa3b32e4e232661901abd9e03f25b058fca"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter3-Weight\u2013Volume Relationships"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg 60"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#evaluvate moist and dry density and void ratio and porosity and degree of saturation and volume of water in soil sample\n",

+      "##initialisation of variables\n",

+      "V= 1.2 ##m**3\n",

+      "M= 2350. ##Kg\n",

+      "w= 0.086\n",

+      "G= 2.71\n",

+      "W= 1000. ##kg/m**3\n",

+      "##calculations\n",

+      "R= M/V\n",

+      "D= M/((1.+w)*V)\n",

+      "e= (G*W/D)-1.\n",

+      "n= e/(e+1.)\n",

+      "S= (w*G/e)*100.\n",

+      "v= (M-(M/(1.+w)))/W\n",

+      "##results\n",

+      "print'%s %.1f %s'% ('moist density = ',R,' kg/m^3 ')\n",

+      "print'%s %.1f %s'% ('dry density = ',D,' kg/m^3 ')\n",

+      "print'%s %.3f %s'%  ('void ratio = ',e,' ')\n",

+      "print'%s %.3f %s'%  ('porosity = ',n,'')\n",

+      "print'%s %.3f %s'%  ('Degree of saturation = ',S,' ')\n",

+      "print'%s %.3f %s'%  ('volume of water in soil sample = ',v,' m^3 ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "moist density =  1958.3  kg/m^3 \n",

+        "dry density =  1803.3  kg/m^3 \n",

+        "void ratio =  0.503  \n",

+        "porosity =  0.335 \n",

+        "Degree of saturation =  46.349  \n",

+        "volume of water in soil sample =  0.186  m^3 \n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg 63"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calcualte  mass of water to be added for full saturation\n",

+      "##initialisation of variables\n",

+      "n= 0.4\n",

+      "G= 2.68\n",

+      "w= 0.12\n",

+      "R= 1000. ##kg/m**3\n",

+      "V= 10. ##m**3\n",

+      "##calculations\n",

+      "d= G*R*(1.-n)*(1.+w)\n",

+      "s= ((1.-n)*G+n)*R\n",

+      "M= s-d\n",

+      "m= M*V\n",

+      "##results\n",

+      "print'%s %.1f %s'%('mass of water to be added for full saturation = ',m,' kg ')"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "mass of water to be added for full saturation =  2070.4  kg \n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg63"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculatesatuarated unit weight and specific gravity and void ratio \n",

+      "##initialisation of variables\n",

+      "d= 16.19 ##kN/m**3\n",

+      "w= 0.23\n",

+      "W= 9.81 ##kN/m**3\n",

+      "##calculations\n",

+      "R= d*(1.+w)\n",

+      "G= d/(W-d*w)\n",

+      "e= w*G\n",

+      "##results\n",

+      "print'%s %.2f %s'%('satuarated unit weight = ',R,' kN/m^3 ')\n",

+      "print '%s %.2f %s'%('specific gravity = ',G,' ')\n",

+      "print'%s %.2f %s'% ('void ratio = ',e,' ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "satuarated unit weight =  19.91  kN/m^3 \n",

+        "specific gravity =  2.66  \n",

+        "void ratio =  0.61  \n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg66"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate relative density of compaction in percentage\n",

+      "##initialisation of variables\n",

+      "G= 2.68\n",

+      "w= 0.12\n",

+      "d= 1794.4 ##kg/m**3\n",

+      "W= 1000. ##kg/m**3\n",

+      "emax= 0.75\n",

+      "emin= 0.4\n",

+      "##calculation\n",

+      "e= (G*W*(1.+w)/d)-1.\n",

+      "D= ((emax-e)/(emax-emin))*100.\n",

+      "##results\n",

+      "print'%s %.1f %s'% ('relative density of compaction in percentage = ',D,' ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "relative density of compaction in percentage =  22.1  \n"

+       ]

+      }

+     ],

+     "prompt_number": 4

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter4.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter4.ipynb
new file mode 100755
index 00000000..fba0d3fa
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter4.ipynb
@@ -0,0 +1,61 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:45b6913d14d2cf9c4faefd4baea5e7b623551c1775a96697aceb0fea3463da05"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter4-Plasticity and Structure of Soil"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg83"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate shrinkage limit of the soil \n",

+      "##initialisation of variables\n",

+      "V1= 24.6 ##cm^3\n",

+      "V2= 15.9 ##cm^3\n",

+      "M1= 44 ##g\n",

+      "M2= 30.1 ##g\n",

+      "W= 1 ##g/cm^3\n",

+      "##calculations\n",

+      "SL= (((M1-M2)/M2)*100)-(((V1-V2)/M2)*W*100.)\n",

+      "##results\n",

+      "print'%s %.1f %s'%('shrinkage limit of the soil = ',SL,' ')\n",

+      "\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "shrinkage limit of the soil =  17.3  \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter6.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter6.ipynb
new file mode 100755
index 00000000..965ec97d
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter6.ipynb
@@ -0,0 +1,188 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:9e373112e48f07ee80b6b4af3f674669c699f5259766125b19738d8e5f5cd0b1"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter6-Soil Compaction"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg127"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate maximum dry density and optimum moisture content\n",

+      "##initialisation of variables\n",

+      "G= 2.6\n",

+      "LL= 20.\n",

+      "P= 20.\n",

+      "##calclations\n",

+      "R= (4804574.*G-195.55*(LL)**2+156971*(P)**0.5-9527830)**0.5\n",

+      "n= (1.195e-4)*((LL)**2)-1.964*G-(6.617e-5)*(P)+7.651\n",

+      "w= math.e**n\n",

+      "##results\n",

+      "print'%s %.1f %s'% ('maximum dry density = ',R,' kg/m^3 ')\n",

+      "print'%s %.2f %s'%('optimum moisture content = ',w,' ')\n",

+      "\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "maximum dry density =  1894.2  kg/m^3 \n",

+        "optimum moisture content =  13.34  \n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg143"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate dry unit weight of compaction in the field and dry unit weight of compaction in the field\n",

+      "##initialisation of variables\n",

+      "do= 1570. ##kg/m^3\n",

+      "mo= 0.545 ##kg\n",

+      "M1= 7.59 ##kg\n",

+      "M2= 4.78 ##kg\n",

+      "M3= 3.007 ##kg\n",

+      "w= 0.102 ##\n",

+      "dmax= 19. ##KN/m^3\n",

+      "##calculations\n",

+      "Ms= M1-M2\n",

+      "Mc= Ms-mo\n",

+      "Vh= Mc/do\n",

+      "Dc= M3/Vh\n",

+      "Du= Dc*9.81/1000.\n",

+      "f= Du/(1.+w)\n",

+      "Rc= f*100./dmax\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('dry unit weight of compaction in the field = ',f,' kN/m^3 ')\n",

+      "print'%s %.1f %s'% ('relative compaction in the field = ',Rc,'')\n",

+      "#calculate the value of gamma and plot the graph\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "import math\n",

+      "from math import log\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "p=numpy.array([6,8,9,11,12,14])\n",

+      "e=numpy.array([14.80,17.45,18.52,18.9,18.5,16.9])\n",

+      "\n",

+      "#calculations\n",

+      "\n",

+      "\n",

+      "#results\n",

+      "\n",

+      "pyplot.plot(p,e)\n",

+      "pyplot.xlabel('gamma')\n",

+      "pyplot.ylabel('weight ,w')\n",

+      "pyplot.title('Graph of gamma vs w')\n",

+      "pyplot.show()\n",

+      "print('look at the axis reverse in text book')"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "dry unit weight of compaction in the field =  18.55  kN/m^3 \n",

+        "relative compaction in the field =  97.7 \n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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WJIoLgMmSxmbPdwLOlbQa8EDZIuvk3nsPTjwxJYmVV847GjPrzFo160lSD6Av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\n/X/kMsqaulAsNgAAAABJRU5ErkJggg==\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x566c2f0>"

+       ]

+      },

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "look at the axis reverse in text book\n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg155"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate sustainabilty number\n",

+      "##initialisation of variables\n",

+      "D1= 0.36 ##mm\n",

+      "D2= 0.52 ##mm\n",

+      "D5= 1.42 ##mm\n",

+      "##calculations\n",

+      "Sn= 1.7*(math.sqrt((3./(D5)**2)+(1./(D2)**2)+(1./(D1)**2)))\n",

+      "##results\n",

+      "print'%s %.1f %s'% ('sustainabilty number = ',Sn,' ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "sustainabilty number =  6.1  \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter7.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter7.ipynb
new file mode 100755
index 00000000..2f2c2988
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter7.ipynb
@@ -0,0 +1,503 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:386718b63e6b6f21bd32a3120a143f6e224e0278ef555853cf557429a2d7f4f2"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter7- Permeability"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg168"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Calculate the hydraulic conductivity in cm/sec.\n",

+      "import math\n",

+      "##initialisation of variables\n",

+      "L= 30. ##cm\n",

+      "A= 177. ##cm^2\n",

+      "h= 50. ##cm\n",

+      "Q= 350. ##cm^3\n",

+      "t= 300. ##sec\n",

+      "##claculations\n",

+      "k=Q*L/(A*h*t)\n",

+      "##results\n",

+      "print'%s %.4f %s'% ('hydraulic conductivity = ',k,' cm/sec ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "hydraulic conductivity =  0.0040  cm/sec \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg169\n"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Determine the hydraulic conductivity of the soil in in./sec.\n",

+      "import math\n",

+      "##initialisation of variables\n",

+      "L= 203. ##mm\n",

+      "A= 10.3 ##cm^2\n",

+      "a= 0.39 ##cm^2\n",

+      "h0= 508. ##mm\n",

+      "h180= 305. ##mm\n",

+      "t= 180. ##sec\n",

+      "##calculations\n",

+      "k= 2.303*a*L*math.log10(h0/h180)/(A*t)\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('hydraulic conductivity of sand = ',k,' in/sec ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "hydraulic conductivity of sand =  0.02  in/sec \n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg169"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#The hydraulic conductivity of a clayey soil is 3  107 cm/sec. The viscosity of water at 25\u00b0C is 0.0911  104 g # sec/cm2 \n",

+      "#Calculate the absolute permeability of the soil.\n",

+      "import math\n",

+      "##initialisation of varilables\n",

+      "k= 3e-7 ##cm/sec\n",

+      "n= 0.0911e-4 ##g*sec/cm^2\n",

+      "dw= 1. ##g/cc\n",

+      "##calculations\n",

+      "K= k*n/dw\n",

+      "##results\n",

+      "print'%s %.2e %s'% ('absolute premeability = ',K,' cm^2 ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "absolute premeability =  2.73e-12  cm^2 \n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg170"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#With k  5.3  105 m/sec for the permeable layer, calculate the rate of seepage through it in m3 /hr/m width if H  3 m and a  8\u00b0.\n",

+      "\n",

+      "import math\n",

+      "##initialisation of variables\n",

+      "k= 5.3e-5 ##m/sec\n",

+      "H= 3 ##m\n",

+      "a= 0.139 ##radians\n",

+      "##calculations\n",

+      "A= H*math.cos(a)\n",

+      "i= math.sin(a)\n",

+      "q= k*i*A*3600\n",

+      "##results\n",

+      "print'%s %.4f %s'% ('rate of seepage = ',q,' m^3/hr/m ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "rate of seepage =  0.0785  m^3/hr/m \n"

+       ]

+      }

+     ],

+     "prompt_number": 5

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg171"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate flow rate\n",

+      "##initialisation of variables\n",

+      "L= 50. ##m\n",

+      "k= 0.08e-2##m/sec\n",

+      "h= 4. ##m\n",

+      "H1= 3. ##m\n",

+      "H= 8. ##m\n",

+      "a= 0.139 ##radians\n",

+      "##calculations\n",

+      "i= h*math.cos(a)/L\n",

+      "A= H1*math.cos(a)\n",

+      "q= k*i*A\n",

+      "##results\n",

+      "print'%s %.5f %s'% ('flow rate = ',q,' m^3/sec/m ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "flow rate =  0.00019  m^3/sec/m \n"

+       ]

+      }

+     ],

+     "prompt_number": 8

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex6-pg174"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate hydraulic conductivity at void ratio of 0.65\n",

+      "##initialisation of variables\n",

+      "k1= 0.02 ##cm/sec\n",

+      "e1= 0.5 \n",

+      "e2= 0.65\n",

+      "##calculations\n",

+      "k2= k1*(e2**3/(1.+e2))/(e1**3/(1.+e1))\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('hydraulic conductivity at void ratio of 0.65 =',k2,'cm/sec ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "hydraulic conductivity at void ratio of 0.65 = 0.04 cm/sec \n"

+       ]

+      }

+     ],

+     "prompt_number": 18

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex7-pg176"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the value of grain size and plot the graph\n",

+      "import math\n",

+      "%matplotlib inline\n",

+      "import warnings\n",

+      "warnings.filterwarnings('ignore')\n",

+      "from math import log\n",

+      "import numpy\n",

+      "from math import tan\n",

+      "import matplotlib\n",

+      "from matplotlib import pyplot\n",

+      "#given\n",

+      "e=numpy.array([100,96,84,50,0])\n",

+      "p=numpy.array([0.06,0.0425,0.02,0.015,0.0075])\n",

+      "\n",

+      "#calculations\n",

+      "\n",

+      "\n",

+      "#results\n",

+      "\n",

+      "pyplot.plot(p,e)\n",

+      "pyplot.xlabel('Percent passing')\n",

+      "pyplot.ylabel('grain size,mm')\n",

+      "pyplot.title('Graph of percent passinge vs grain size')\n",

+      "pyplot.show()\n",

+      "print('look at the axis reverse in text book')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": 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+       "text": [

+        "<matplotlib.figure.Figure at 0x542d930>"

+       ]

+      },

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "look at the axis reverse in text book\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex8-pg177"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate hydraulic conductivity\n",

+      "##initialisation of variables\n",

+      "e= 0.6\n",

+      "D10= 0.09 ##mm\n",

+      "##calculations\n",

+      "k= 2.4622*(D10**2*(e**3/(1+e)))**0.7825\n",

+      "##results\n",

+      "print'%s %.4f %s'% ('hydraulic conductivity = ',k,' cm/sec ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "hydraulic conductivity =  0.0119  cm/sec \n"

+       ]

+      }

+     ],

+     "prompt_number": 17

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex9-pg177"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate hydraulic conductivity\n",

+      "##initialisation of variables\n",

+      "e= 0.6\n",

+      "D10= 0.09 ##mm\n",

+      "D60= 0.16 ##mm\n",

+      "##calculations\n",

+      "Cu=D60/D10\n",

+      "k= 35*(e**3/(1+e))*(Cu**0.6)*(D10**2.32)\n",

+      "##results\n",

+      "print'%s %.3f %s'% ('hydraulic conductivity =',k,'cm/sec ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "hydraulic conductivity = 0.025 cm/sec \n"

+       ]

+      }

+     ],

+     "prompt_number": 11

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex10-pg179"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate hydraulic conductivity\n",

+      "##initialisation of variables\n",

+      "k1= 0.302e-7 ##cm/sec\n",

+      "k2= 0.12e-7 ##cm/sec\n",

+      "e1= 1.1\n",

+      "e2= 0.9\n",

+      "e= 0.75\n",

+      "##calcualtions\n",

+      "n= (math.log10((k1/k2)*((1+e1)/(1+e2))))/math.log10(e1/e2)\n",

+      "C= k1/(e1**n/(1+e1))\n",

+      "k= C*(e**n/(1+e))\n",

+      "##results\n",

+      "print'%s %.e %s'% ('hydraulic conductivity =',k,'cm/sec')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "hydraulic conductivity = 5e-09 cm/sec\n"

+       ]

+      }

+     ],

+     "prompt_number": 16

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex11-pg185"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate ration of equivalent hydraulic conductivity\n",

+      "##initialisation of variables\n",

+      "H1= 2. ##m\n",

+      "H2= 3. ##m\n",

+      "H3= 4. ##m\n",

+      "k1= 1e-4 ##cm/sec\n",

+      "k2= 3.2e-2 ##cm/sec\n",

+      "k3= 4.1e-5 ##cm/sec\n",

+      "##calculations\n",

+      "H= H1+H2+H3\n",

+      "Kh= (1./H)*((k1*H1)+(k2*H2)+(k3*H3))\n",

+      "Kv= H/((H1/k1)+(H2/k2)+(H3/k3))\n",

+      "P= Kh/Kv\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('ration of equivalent hydraulic conductivity =',P,' ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "ration of equivalent hydraulic conductivity = 139.97  \n"

+       ]

+      }

+     ],

+     "prompt_number": 13

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex12-pg186"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate rate of water supply\n",

+      "##initialisation of variables\n",

+      "H= 450. ##mm\n",

+      "h= 150. ##mm\n",

+      "k1= 1e-2 ##cm/sec\n",

+      "k2= 3e-3 ##cm/sec\n",

+      "k3= 4.9e-4 ##cm/sec\n",

+      "h1= 300. ##mm\n",

+      "##calculations\n",

+      "Kv= H/(h*(1./k1+1./k2+1./k3))\n",

+      "i= h1/H\n",

+      "q= Kv*i*100.*3600.\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('rate of water supply =',q,' cm/hr ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "rate of water supply = 291.01  cm/hr \n"

+       ]

+      }

+     ],

+     "prompt_number": 15

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter8.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter8.ipynb
new file mode 100755
index 00000000..29871da0
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter8.ipynb
@@ -0,0 +1,241 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:61bb09563c68b30d1e4461dec41e802a02b539da836a09cb7d1de16a382cc82d"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter8-Seepage"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg203"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate rate of water flow\n",

+      "##initialisation of variables\n",

+      "H1= 12. ##in\n",

+      "H2= 20. ##in\n",

+      "z= 8. ##in\n",

+      "h1= 24. ##in\n",

+      "h= 20. ##in\n",

+      "k1= 0.026 ##in/sec\n",

+      "D= 3. ##in\n",

+      "##calculations\n",

+      "k2= H2*k1/((z/(1.-h/h1))-H1)\n",

+      "i= h1/(H1+H2)\n",

+      "A= math.pi/4.*D**2\n",

+      "keq= (H1+H2)/((H1/k1)+(H2/k2))\n",

+      "q= keq*A*i*3600.\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('rate of water flow = ',q,' in^3/hr ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "rate of water flow =  330.81  in^3/hr \n"

+       ]

+      }

+     ],

+     "prompt_number": 7

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg208"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate a)How high (above the ground surface) the water will rise if piezometers are placed at points aandb.\n",

+      "#b.The total rate of seepage through the permeable layer per unit length\n",

+      "#c. The approximate average hydraulic gradient at c.\n",

+      "##initialisation of variables\n",

+      "Nd= 6.\n",

+      "H1= 5.6 ##m\n",

+      "H2= 2.2 ##m\n",

+      "k= 5e-5 ##cm/sec\n",

+      "dL= 4.1 ##m\n",

+      "##calculations\n",

+      "H= (H1-H2)/Nd\n",

+      "h1= 5.61-H\n",

+      "h2= 5.61-5.*H\n",

+      "q= 2.38*(H1-H2)*k/Nd\n",

+      "i= H/dL\n",

+      "##results\n",

+      "print'%s %.3f %s'% ('at point a,water will rise to height of = ',h1,' m ')\n",

+      "print'%s %.3f %s'% ('at point b,water will rise to height of =',h2,' m ')\n",

+      "print'%s %.e %s'% ('total rate of seepage per unit lenghth = ',q,' m^3/sec/m ')\n",

+      "print'%s %.3f %s'% ('average hydraulic gradient at c = ',i,' ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "at point a,water will rise to height of =  5.043  m \n",

+        "at point b,water will rise to height of = 2.777  m \n",

+        "total rate of seepage per unit lenghth =  7e-05  m^3/sec/m \n",

+        "average hydraulic gradient at c =  0.138  \n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg210"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate average rate of flow\n",

+      "##initialisation of variables\n",

+      "k1= 5.67 ##ft/day\n",

+      "k2= 11.34 ##ft/day\n",

+      "##from graph\n",

+      "Nd= 8\n",

+      "Nf= 2.5\n",

+      "H= 20\n",

+      "##calculations\n",

+      "q= math.sqrt(k1*k2)*H*Nf/Nd\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('average rate of flow = ',q,' ft^3/day/ft ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "average rate of flow =  50.12  ft^3/day/ft \n"

+       ]

+      }

+     ],

+     "prompt_number": 9

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg 212"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate seepage under the dam \n",

+      "##initialisation of variables\n",

+      "B= 6. ##m\n",

+      "L= 120. ##m\n",

+      "s= 3. ##m\n",

+      "T= 6. ##m\n",

+      "x= 2.4 ##m\n",

+      "H= 5. ##m\n",

+      "k= 0.008 ##cm/sec\n",

+      "##calculations\n",

+      "b=B/2.\n",

+      "a1= b/T\n",

+      "a2= s/T\n",

+      "a3= x/b\n",

+      "Q= 0.378*k*H*L*36*24\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('seepage under the dam = ',Q,' m^3/day ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "seepage under the dam =  1567.64  m^3/day \n"

+       ]

+      }

+     ],

+     "prompt_number": 4

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex5-pg217"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate seepage rate\n",

+      "##initialisation of variables\n",

+      "b= math.pi/4. ##degrees\n",

+      "a= math.pi/6.##degrees\n",

+      "B= 10. ##ft\n",

+      "H= 20. ##ft\n",

+      "h= 25. ##ft\n",

+      "k= 2e-4 ##ft/min\n",

+      "##calculations\n",

+      "r= H/math.tan(b)\n",

+      "d= 0.3*r+(h-H)/math.tan(b)+B+h/math.tan(a)\n",

+      "L= d/math.cos(a)-math.sqrt((d/math.cos(a))**2-(H/math.sin(a))**2)\n",

+      "q= k*L*math.tan(a)*math.sin(a)*24.*60\n",

+      "##results\n",

+      "print'%s %.4f %s'% ('seepage rate = ',q,' ft^3/day/ft ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "seepage rate =  0.9724  ft^3/day/ft \n"

+       ]

+      }

+     ],

+     "prompt_number": 6

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file
diff --git a/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter9.ipynb b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter9.ipynb
new file mode 100755
index 00000000..005e638c
--- /dev/null
+++ b/Principles_Of_Geotechnical_Engineering_by_B._M._Das/Chapter9.ipynb
@@ -0,0 +1,205 @@
+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:c82d7ef2a69a4d72efc2edfc8621bdf4ff77be194f7e8e01b4cf1b42672764ab"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter9-In Situ Stresses"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex1-pg230"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "#calculate total pressure and pore water pressure and effective stress at point\n",

+      "##initialisation of variables\n",

+      "Ds= 16.5 ##kN/m**3\n",

+      "S= 19.25 ##kN/m**3\n",

+      "g= 9.8 ##kN/m**3\n",

+      "h1= 6. ##m\n",

+      "h2= 13. ##m\n",

+      "##at point A\n",

+      "Sa= 0.\n",

+      "Ua= 0.\n",

+      "Sa1= 0.\n",

+      "##at point B\n",

+      "Sb= h1*Ds\n",

+      "Ub= 0.\n",

+      "Sb1= Sb-Ub\n",

+      "##at point C\n",

+      "Sc= h1*Ds+h2*S\n",

+      "Uc= h2*g\n",

+      "Sc1= Sc-Uc\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('total pressure at C= ',Sc,' kN/m^3 ')\n",

+      "print'%s %.2f %s'% ('pore water pressure at C = ',Uc,' kN/m^3 ')\n",

+      "print'%s %.2f %s'% ('effective stress at point C=',Sc1,' kN/m^3 ')\n",

+      "\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "total pressure at C=  349.25  kN/m^3 \n",

+        "pore water pressure at C =  127.40  kN/m^3 \n",

+        "effective stress at point C= 221.85  kN/m^3 \n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex2-pg233"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate maximu depth that can be made in clay\n",

+      "##initialisation of variables\n",

+      "h= 20. ##ft\n",

+      "g= 120. ##kg/ft**3\n",

+      "h1= 12. ##ft\n",

+      "w= 62.4 ##kg/ft**3\n",

+      "##calculations\n",

+      "H= h-(h1*w/g)\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('maximu depth that can be made in clay = ',H,' ft ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "maximu depth that can be made in clay =  13.76  ft \n"

+       ]

+      }

+     ],

+     "prompt_number": 8

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex3-pg236"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate effective stress at point a and b and see page force per unit voume\n",

+      "##initialisation of variables\n",

+      "G= 2.68\n",

+      "e= 0.52\n",

+      "g= 9.81 ##kN/m^3\n",

+      "h1= 0.7 ##m\n",

+      "h2= 1 ##m\n",

+      "h3= 1.5 ##m\n",

+      "h4= 2 ##m\n",

+      "##calculations\n",

+      "##for soil A\n",

+      "sa= (G+e)*g/(1.+e)\n",

+      "##point a\n",

+      "Sa= h1*g+h2*sa\n",

+      "u= (h2+h1+h3/2.)*g\n",

+      "Es= Sa-u\n",

+      "##point b\n",

+      "sb= h1*g+h4*sa\n",

+      "ub= (h4+h1+h3)*g\n",

+      "Eb= sb-ub\n",

+      "i= h3/2.\n",

+      "s= i*g\n",

+      "##results\n",

+      "print'%s %.2f %s'% ('effective stress at point a=',Es,' kN/m^2 ')\n",

+      "print'%s %.2f %s'% ('effective stress at point b= ',Eb,'kN/m^2 ')\n",

+      "print'%s %.2f %s'% ('seepage force per unit voume = ',s,' kN/m^3 ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "effective stress at point a= 3.49  kN/m^2 \n",

+        "effective stress at point b=  6.97 kN/m^2 \n",

+        "seepage force per unit voume =  7.36  kN/m^3 \n"

+       ]

+      }

+     ],

+     "prompt_number": 9

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Ex4-pg239"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate safety factor\n",

+      "##initialisation of variables\n",

+      "C0= 0.357\n",

+      "H1= 30.5 ##ft\n",

+      "H2= 5. ##ft\n",

+      "w= 62.4 ## lb/ft^3\n",

+      "D= 20.\n",

+      "g= 112. ## lb/ft^3\n",

+      "##calculations\n",

+      "G= g-w\n",

+      "FS= D*G/(C0*w*(H1-H2))\n",

+      "##results\n",

+      "print'%s %.1f %s'% ('safety factor =',FS,' ')\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "safety factor = 1.7  \n"

+       ]

+      }

+     ],

+     "prompt_number": 5

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file