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-rwxr-xr-xSolid_State_Electronics/Solid_State_electronics.ipynb (renamed from Solid_State_Electronics/Solid_State_electronics_Ch10.ipynb)0
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-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 1 : Introduction to Solid State Electronics"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.1, Page No. 17"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# ne in the doped silicon\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "ni=1.5*10**16 # in m^-3\n",
- "nh=4.5*10**22 # in m^-3\n",
- "\n",
- "#Calculations\n",
- "ne=ni**2/nh\n",
- "\n",
- "#Result\n",
- "print(\" ne in the doped silicon is,(m^-3) = %.f * 10^9\"%(ne/10**9))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " ne in the doped silicon is,(m^-3) = 5 * 10^9\n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.2, Page No. 17"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistivity\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "\n",
- "ne=8.0*10**19 # in m^-3\n",
- "nh=5.0*10**18 # in m^-3\n",
- "mu_e=2.3 # in m^2/V-s\n",
- "mu_h=.01 # in m^2/V-s\n",
- "e=1.6*10**-19 # in V\n",
- "\n",
- "#Calculations\n",
- "p=1/(e*((ne*mu_e)+(nh*mu_h)));\n",
- "\n",
- "#Result\n",
- "print(\"(b) the resistivity,p(ohm-m)= %.1f * 10^-2\"%(p*10**2))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(b) the resistivity,p(ohm-m)= 3.4 * 10^-2\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.3, Page No. 17"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Density\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "\n",
- "sigma=500.0 # in ohm^-1 m^-1\n",
- "mu_e=0.39 # m^2/V-s\n",
- "e=1.6*10**-19 # in V\n",
- "\n",
- "#Calculations\n",
- "ne=sigma/(e*mu_e);\n",
- "\n",
- "#Result\n",
- "print(\"number density of donor,ne(m^-3) = %.2f * 10^21\"%(ne*10**-21))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "number density of donor,ne(m^-3) = 8.01 * 10^21\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.4, Page No. 18"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Density\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "\n",
- "e=1.6*10**-19 # in V\n",
- "Pp=10**-2 # p-type silicon in ohm-m\n",
- "Pn=10**-2 # n-type silicon in ohm-m\n",
- "mu_p=0.048 # holes mobilities in m^2/V-s\n",
- "mu_n=0.135 # electrons mobilities in m^2/V-s\n",
- "\n",
- "#Calculations\n",
- "Na=1/(e*mu_p*Pp);\n",
- "Nd=1/(e*mu_n*Pn);\n",
- "\n",
- "#Result\n",
- "print(\"(i). the density of impurity,Na (m^-3) = %.1f * 10^22\"%(Na*10**-22))\n",
- "print(\"(ii). the density of impurity,Nd (m^-3) = %.2f * 10^21\"%(Nd*10**-21))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i). the density of impurity,Na (m^-3) = 1.3 * 10^22\n",
- "(ii). the density of impurity,Nd (m^-3) = 4.63 * 10^21\n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.5, Page No. 18"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Resistivity\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "e=1.6*10**-19 # in V\n",
- "n=2.5*10**19 # m^3\n",
- "p=n\n",
- "ni=n\n",
- "mu_p=0.17 # holes mobilities in m^2/V-s\n",
- "mu_n=0.36 # electrons mobilities in m^2/V-s\n",
- "\n",
- "#Calculations\n",
- "sgint=e*(ni*(mu_p+mu_n)) #electrical conductivity in mho/metre\n",
- "pint=1/sgint #resistivity in ohm-meter\n",
- "print(\"electrical conductivity is ,(mho/metre)= %.2f\"%sgint)\n",
- "print(\"resistivity is ,(ohm-metre)= %.2f\"%pint)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "electrical conductivity is ,(mho/metre)= 2.12\n",
- "resistivity is ,(ohm-metre)= 0.47\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.6, Page No. 18"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Conductivity\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "\n",
- "e=1.6*10**-19 # in V\n",
- "ni=1.5*10**16 # in m^3\n",
- "mu_p=0.13 # holes mobilities in m^2/V-s\n",
- "mu_n=0.05 # electrons mobilities in m^2/V-s\n",
- "siat=10.0**8 # number of silicon atoms\n",
- "ta=5.0*10**28 # silicon atoms in atoms/m^3\n",
- "mu_n2=0.13 # electrons mobilities in m^2/V-s\n",
- "siat2=10.0**8 # number of silicon atoms\n",
- "ta2=5.0*10**28 # silicon atoms in atoms/m^3\n",
- "mu_p2=0.05 # holes mobilities in m^2/V-s\n",
- "\n",
- "#Calculations\n",
- "sgint=e*(ni*(mu_p+mu_n)) # electrical conductivity in mho/m\n",
- "Nd=ta/siat # in atoms/m^3\n",
- "p= ni**2/Nd # holes concentration in holes/m^3\n",
- "n=Nd\n",
- "sntype=e*n*mu_n2 # in mho/m\n",
- "Na=ta2/siat2 # in atoms/m^3\n",
- "n= ni**2/Na # holes concentration in holes/m^3\n",
- "sptype=e*Na*mu_p2 # in mho/m\n",
- "\n",
- "#Calculations\n",
- "print(\"(i) electrical conductivity is ,(mhos/m) = %.2f * 10^-4\"%(sgint*10**4))\n",
- "print(\"(ii) holes concentration is, (holes/m^3) = %.1f *10^11\"%(p*10**-11))\n",
- "print(\"(ii) conductivity is ,(mho/m) = %.1f\"%sntype)\n",
- "print(\"(iii) electron concentration is, (holes/m^3)= %.1f * 10^11\"%(n/10**11))\n",
- "print(\"(iii) conductivity is ,(mho/m) = %.1f\"%sptype)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) electrical conductivity is ,(mhos/m) = 4.32 * 10^-4\n",
- "(ii) holes concentration is, (holes/m^3) = 4.5 *10^11\n",
- "(ii) conductivity is ,(mho/m) = 10.4\n",
- "(iii) electron concentration is, (holes/m^3)= 4.5 * 10^11\n",
- "(iii) conductivity is ,(mho/m) = 4.0\n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.7, Page No. 19"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Fermi Level\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "#Nd1=Nc*exp^-(Ec-Ef1)/kT ...Formula Used\n",
- "Nc=1.0 #assume\n",
- "kT=0.03 #eV\n",
- "EcEf1=0.5 #position of Fermi level in V\n",
- "Nd=1.0 #assume\n",
- "Nd1=3*Nd #After tripling the donor concentration\n",
- "\n",
- "#Calculation\n",
- "EcEf2=(EcEf1-(kT*(math.log(Nd1/Nd))))\n",
- "print(\"new position of Fermi-level is %.3f eV below conduction band\"%(math.ceil(EcEf2*1000)/1000))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "new position of Fermi-level is 0.468 eV below conduction band\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.8, Page No. 20"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# density\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "e=1.6*10**-19 # in V\n",
- "Pp=10**-1 # p-type silicon in ohm-m\n",
- "Pn=10**-1 # n-type silicon in ohm-m\n",
- "mu_h=0.05 # holes mobilities in m^2/V-s\n",
- "mu_e=0.13 # electrons mobilities in m^2/V-s\n",
- "\n",
- "#Calculations\n",
- "Na=1/(e*mu_h*Pp);\n",
- "Nd=1/(e*mu_e*Pn);\n",
- "\n",
- "#Result\n",
- "print(\"(i). the density of impurity,Na (m^-3) = %.2f * 10^21\"%(Na/10**21))\n",
- "print(\"(ii). the density of impurity,Nd (m^-3) = %.1f * 10^20\"%(Nd/10**20))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i). the density of impurity,Na (m^-3) = 1.25 * 10^21\n",
- "(ii). the density of impurity,Nd (m^-3) = 4.8 * 10^20\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.9, Page No. 20"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "e=1.6*10**-19 # in V\n",
- "Pp=10**-1 # p-type silicon in ohm-m\n",
- "Pn=10**-1 # n-type silicon in ohm-m\n",
- "mu_hsi=0.048 # holes mobilities in m^2/V-s\n",
- "mu_esi=0.135 # electrons mobilities in m^2/V-s\n",
- "nisi=1.5*10**16 # in m^-3\n",
- "nesi=nisi\n",
- "nhsi=nisi\n",
- "mu_hge=0.19 # holes mobilities in m^2/V-s\n",
- "mu_ege=0.39 # electrons mobilities in m^2/V-s\n",
- "A=1*10**-4 # area in m^2\n",
- "nige=2.4*10**19 # in m^-3\n",
- "V=2.0 # in V\n",
- "l=0.1 # in m\n",
- "\n",
- "#Calculations\n",
- "Isi= e*A*(V/l)*((nesi*mu_esi)+(nhsi*mu_hsi))\n",
- "#Current for silicon is calculated wrong in the textbook\n",
- "nege=nige\n",
- "nhge=nige\n",
- "Ige= e*A*(V/l)*((nege*mu_ege)+(nhge*mu_hge))\n",
- "\n",
- "#Result\n",
- "print(\"Total current for silicon is,(A) = %f\"%Isi)\n",
- "print(\"Total current for germanium is,(A)= %.2f * 10^-3\"%(math.ceil(Ige*10**5)/100))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Total current for silicon is,(A) = 0.000001\n",
- "Total current for germanium is,(A)= 4.46 * 10^-3\n"
- ]
- }
- ],
- "prompt_number": 41
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.10, Page No. 21"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# hole concentration and conductivity\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "nh=2*10**21 # acceptor atoms in atoms/m^3\n",
- "mu_h=0.17 # mobility of holes in m^2/V-s\n",
- "e=1.6*10**-19 # in C\n",
- "\n",
- "#Calculations\n",
- "Na=nh\n",
- "sigma=nh*mu_h*e;\n",
- "\n",
- "#Result\n",
- "print(\"hole concentration,Na(atoms/m^3) = %.1f * 10^21\"%(Na/10**21))\n",
- "print(\"conductivity,(ohm^-1-m^-1) = %.1f\"%sigma)\n",
- "#conductivity is calculated wrong in the book"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "hole concentration,Na(atoms/m^3) = 2.0 * 10^21\n",
- "conductivity,(ohm^-1-m^-1) = 54.4\n"
- ]
- }
- ],
- "prompt_number": 42
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.11, Page No. 22"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# donor concentration\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "p=0.15 # in ohm-m\n",
- "mu_e=0.39 # mobility of electron in m^2/V-s\n",
- "e=1.6*10**-19 # in C\n",
- "\n",
- "#Calculations\n",
- "Na=1/(e*mu_e*p);\n",
- "\n",
- "#Result\n",
- "print(\"The value of donor concentration,Na(m^-3) = %.2f * 10^20\"%(Na/10**20))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of donor concentration,Na(m^-3) = 1.07 * 10^20\n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.12, Page No. 12"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistivity\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "mu_n=0.13 # in m^2/V-s\n",
- "mu_p=0.05 # in m^2/V-s\n",
- "ni=1.5*10**16 # in m^-3\n",
- "e=1.6*10**-19 # in C\n",
- "\n",
- "#Calculations\n",
- "p=1/((e*ni)*(mu_n+mu_p));\n",
- "\n",
- "#Result\n",
- "print(\"The resistivity,p(ohm-m) = %.1f\"%p)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The resistivity,p(ohm-m) = 2314.8\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.13, Page No. 37"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "e=1.6*10**-19 # electron charge in coulombs\n",
- "k=1.38*10**-23 # Boltzmann constant in m^2-kg/s^2-K^-1\n",
- "T=300.0 # in Kelvin\n",
- "I=240.0 # in mA\n",
- "eta=2.0\n",
- "Ve=0.8 # in V\n",
- "V=0.7 # in V\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Vt=(k*T)/e # in V\n",
- "Id=I*math.e**((V-Ve)/(eta*Vt)) #in mA\n",
- "Ir=(I/((math.e**(Ve/(eta*Vt)))-1))*10**6\n",
- "\n",
- "\n",
- "#Result\n",
- "print(\"(i) Current is ,(mA) = %.f\"%(round(Id)))\n",
- "print(\"(ii) reverse saturation current is ,(nA) = %.f\"%(round(Ir)))\n",
- "#reverse saturation current is calculated wrong in the textbook"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Current is ,(mA) = 35\n",
- "(ii) reverse saturation current is ,(nA) = 46\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.14, Page No. 38"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# diode current and voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "e=1.6*10**-19 # electron charge in coulombs\n",
- "k=1.38*10**-23 # Boltzmann constant in m^2-kg/s^2-K^-1\n",
- "T=300.0 # in Kelvin\n",
- "Ir1=10**-10 # in A\n",
- "Ir2=10**-12 # in A \n",
- "V211=0.5 # in V\n",
- "\n",
- "#Calculations\n",
- "Vt=(k*T)/e\n",
- "Vt = math.ceil(Vt*1000)/1000\n",
- "V21=((Vt)*math.log10(Ir1/Ir2))*2.3026\n",
- "V21 = math.floor(V21*10000)/10000\n",
- "V2=(1.0/2)*(V21+V211)\n",
- "V1=(1.0/2)*(V211-V21)\n",
- "I1=Ir2*math.e**(V2/Vt)*10**6\n",
- "I2=I1\n",
- "\n",
- "#Result\n",
- "print(\"diode voltage V2 is ,(V) = %.5f\"%V2)\n",
- "print(\"diode voltage V1 is ,(V) = %.5f\"%V1)\n",
- "print(\"diode current is,(micro-A) = %.4f\"%I1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode voltage V2 is ,(V) = 0.30985\n",
- "diode voltage V1 is ,(V) = 0.19015\n",
- "diode current is,(micro-A) = 0.1498\n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.15, Page No. 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "e=1.6*10**-19 # electron charge in coulombs\n",
- "k=1.38*10**-23 # Boltzmann constant in m^2-kg/s^2-K^-1\n",
- "T=300.0 # in Kelvin\n",
- "Ir1=10**-12 # in A\n",
- "Ir2=10**-10 # in A\n",
- "It=2.0 # mA\n",
- "\n",
- "#Calculations\n",
- "I21=Ir2/Ir1\n",
- "Vt=(k*T)/e # in V\n",
- "Vt = math.ceil(Vt*1000)/1000\n",
- "I1=It/(1+I21)*10**3 # in micro-A\n",
- "I2=It*10**3-I1 # in micro-A\n",
- "I1=I2/I21 # in micro-A\n",
- "x=((I1*10**-6)/Ir1)\n",
- "V=Vt*math.log10(x)*2.3026\n",
- "\n",
- "#Result\n",
- "print(\"diode voltage is ,(V) = %.3f\"%V)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode voltage is ,(V) = 0.437\n"
- ]
- }
- ],
- "prompt_number": 53
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.16, Page No. 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "T=27.0 # degree Celsius\n",
- "Tk=273+T # in Kelvin\n",
- "e=1.6*10**-19 # electron charge in coulombs\n",
- "k=1.38*10**-23 # Boltzmann constant in m^2-kg/s^2-K^-1\n",
- "J=10**4 # in Amp/m^2\n",
- "Jo=200.0 #in mA/m^2\n",
- "\n",
- "#Calculations\n",
- "x=(J/(Jo*10**-3))\n",
- "Ve=((math.log(x))*k*Tk)/e\n",
- "\n",
- "#Result\n",
- "print(\"voltage to be applied is ,(V) = %.2f\"%Ve)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage to be applied is ,(V) = 0.28\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.17, Page No. 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "V=3.0 # in V\n",
- "I=55.0 # in mA\n",
- "V2=26.0 # in mV\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Rdc=V/(I*10**-3) # in ohm\n",
- "Rac=V2/I # in ohm\n",
- "\n",
- "#Result\n",
- "print(\"static resistance is ,(ohm) = %.1f\"%Rdc)\n",
- "print(\"dynamic resistance is ,(ohm) = %.2f\"%Rac)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "static resistance is ,(ohm) = 54.5\n",
- "dynamic resistance is ,(ohm) = 0.47\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.18, Page No. 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "k=1.38*10**-23 # constant\n",
- "T=27+273.0 # in K\n",
- "eta=2.0\n",
- "e=1.6*10**-19 # in C\n",
- "Vt=(k*T/e) # in V\n",
- "V=0.5 # in V\n",
- "Ir=10**-6 # in A\n",
- "\n",
- "#Calculations\n",
- "I=(Ir*10**3*(math.e**(V/(eta*Vt))-1))\n",
- "R_dc=V*10**3/I;\n",
- "R_ac=(eta*k*T)/(e*I*10**-3);\n",
- "\n",
- "#Result\n",
- "print(\"static resistance,R_dc(ohm) = %.1f\"%R_dc)\n",
- "print(\"Dynamic resistance,R_ac(ohm) = %.1f\"%R_ac)\n",
- "#answer is wrong in textbook"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "static resistance,R_dc(ohm) = 31.8\n",
- "Dynamic resistance,R_ac(ohm) = 3.3\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.19, Page No. 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "V=1.2 # in V\n",
- "Vk=0.7 # in V\n",
- "I_F=100.0 # in mA\n",
- "V_R=10.0 # in V\n",
- "I_R=1.0 # in micro-A\n",
- "I=5.0 # in mA\n",
- "eta=2\n",
- "\n",
- "#Calculations\n",
- "R_B=(V-Vk)/(I_F*10**-3)\n",
- "R_R=V_R/I_R\n",
- "R_ac=eta*26/I\n",
- "\n",
- "#Result\n",
- "print(\"the bulk resistance,R_B(ohm) = %.f\"%R_B)\n",
- "print(\"the reverse resistance,R_R(M-ohm) = %.f\"%R_R)\n",
- "print(\"ac resistance,R_ac(ohm) = %.1f\"%R_ac)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the bulk resistance,R_B(ohm) = 5\n",
- "the reverse resistance,R_R(M-ohm) = 10\n",
- "ac resistance,R_ac(ohm) = 10.4\n"
- ]
- }
- ],
- "prompt_number": 54
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.20, Page No. 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# capacitance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "epsilon_0=8.85*10**-12 # in farada/m\n",
- "K=12.0 # constant for silicon\n",
- "A=1*10**-8 # in m^2\n",
- "W=5*10**-7 # in m\n",
- "\n",
- "#Calculations\n",
- "epsilon=epsilon_0*K\n",
- "Ct=epsilon*A*10**14/W;\n",
- "\n",
- "#Result\n",
- "print(\"the transition capacitance,Ct(PF) = %.1f\"%Ct)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the transition capacitance,Ct(PF) = 212.4\n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.21, Page No. 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "V=0.2 # in V\n",
- "I=1.0 # in micro-A\n",
- "\n",
- "#Calculations\n",
- "R_dc=V*10**3/I\n",
- "R_ac=26/(I*10**3);\n",
- "\n",
- "#Result\n",
- "print(\"The static resistance,R_ac(k-ohm) = %.f\"%R_dc)\n",
- "print(\"the dynamic resistance,R_ac(ohm) = %.3f\"%R_ac)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The static resistance,R_ac(k-ohm) = 200\n",
- "the dynamic resistance,R_ac(ohm) = 0.026\n"
- ]
- }
- ],
- "prompt_number": 55
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
diff --git a/Solid_State_Electronics/Solid_State_electronics_Ch2.ipynb b/Solid_State_Electronics/Solid_State_electronics_Ch2.ipynb
deleted file mode 100755
index e605f938..00000000
--- a/Solid_State_Electronics/Solid_State_electronics_Ch2.ipynb
+++ /dev/null
@@ -1,144 +0,0 @@
-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 2 : Special Purpose Diodes"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.1, Page No. 68"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# maximum current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Pmax=364.0 #dissipation in milliwatt\n",
- "Vz=9.1 #in V\n",
- "\n",
- "#Calculations\n",
- "Izmax=Pmax/Vz #in mA\n",
- "\n",
- "#Result\n",
- "print(\"maximum current the diode can handle is ,(mA)= %.f\"%Izmax)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum current the diode can handle is ,(mA)= 40\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2, Page No. 68"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistance\n",
- "\n",
- "import math\n",
- "#Vaariable declaration\n",
- "mip=15.0 #in volt\n",
- "op=6.8 #output potential in volt\n",
- "pd=mip-op #potential difference across series resistor\n",
- "Il=5 #load current in mA\n",
- "nmip=20 #new maximum input voltage in volt\n",
- "pd1=nmip-op #new potential difference across series resistor\n",
- "Il1=20 #new load current in mA\n",
- "\n",
- "#Calculations\n",
- "R=((pd1-pd)/((Il1-Il)*10**-3))\n",
- "print(\"value of series resistance is,(ohm)= %.1f\"%R)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "value of series resistance is,(ohm)= 333.3\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3, Page No.69"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Current\n",
- "\n",
- "import math\n",
- "#VAriable declaration\n",
- "V=120.0 #in V\n",
- "Vz=50.0 #in V\n",
- "R=5.0 #in ohm\n",
- "Rl=10.0 #in k-ohm\n",
- "\n",
- "#Calculations\n",
- "vd5=V-Vz #voltage drop across 5 ohm resistor\n",
- "I5=vd5/R #current through 5 ohm resistor\n",
- "Il=Vz/(Rl*10**3) #current through load resistor\n",
- "Iz=I5-Il #in A\n",
- "\n",
- "#Result\n",
- "print(\"current through zener diode is ,(A)= %.3f\"%Iz)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "current through zener diode is ,(A)= 13.995\n"
- ]
- }
- ],
- "prompt_number": 8
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
diff --git a/Solid_State_Electronics/Solid_State_electronics_Ch3.ipynb b/Solid_State_Electronics/Solid_State_electronics_Ch3.ipynb
deleted file mode 100755
index e33d4edf..00000000
--- a/Solid_State_Electronics/Solid_State_electronics_Ch3.ipynb
+++ /dev/null
@@ -1,676 +0,0 @@
-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 3 : Bi Polar Junction Transistor"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.1, Page No. 82"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# varitation in alpha and value of beta \n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Beta=50.0 #amlification factor\n",
- "dbb=1.0 #percentage variation in degree celsius\n",
- "daa=dbb/50.0 #variation in degree celsius\n",
- "temp=325.0 #in K\n",
- "t=25 #degree celsius\n",
- "\n",
- "#Calculations\n",
- "Beta1=dbb*t\n",
- "nBeta=Beta+(Beta1/100)*t\n",
- "\n",
- "#Result\n",
- "print(\"(b) variation in alpha for a silicon BJT is ,(%%/degree-Celsius) = %.2f\"%daa)\n",
- "print(\"(c) new value of Beta is , = %.2f\"%nBeta)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(b) variation in alpha for a silicon BJT is ,(%/degree-Celsius) = 0.02\n",
- "(c) new value of Beta is , = 56.25\n"
- ]
- }
- ],
- "prompt_number": 46
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.2, Page No.83"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# current amplification factor\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "del_Ic=1*10**-3 # in A\n",
- "del_Ib=50*10**-6 # in A\n",
- "\n",
- "#Calcualtions\n",
- "Beta=del_Ic/del_Ib;\n",
- "print(\"The current amplification factor,Beta = %.f\"%Beta)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The current amplification factor,Beta = 20\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.3, Page No.83"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# base current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "alfa=0.88 # Alfa\n",
- "Ie=1 # in mA\n",
- "\n",
- "#Calcualtions\n",
- "Ic=alfa*Ie \n",
- "I_B=Ie-Ic\n",
- "\n",
- "#Result\n",
- "print(\"Base current,(mA) = %.2f\"%I_B)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Base current,(mA) = 0.12\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.4, Page No.83"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# short circuit current gain\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "del_Ic=0.95*10**-3 # in A\n",
- "del_Ie=1*10**-3 # in A\n",
- "\n",
- "#Calculations\n",
- "alfa=del_Ic/del_Ie;\n",
- "print(\"the short circuit current gain, = %.2f\"%alfa)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the short circuit current gain, = 0.95\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.5, Page No. 83"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# collector and base current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Ie=5*10**-3 # in A\n",
- "alfa=0.95 # Alfa \n",
- "I_co=10*10**-6 # in A\n",
- "Ic=((alfa*Ie)+I_co)*10**3\n",
- "Ib=(Ie-(Ic*10**-3))*10**6\n",
- "print(\"Collector current,(mA) = %.2f\"%Ic)\n",
- "print(\"Base current,(micro-A) = %.f\"%Ib)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Collector current,(mA) = 4.76\n",
- "Base current,(micro-A) = 240\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.6, Page No. 84"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Ic Ib and Iceo\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Ie=5.0 # in mA\n",
- "alfa=0.99 # Alfa\n",
- "I_co=0.005 # in mA\n",
- "\n",
- "#CAlculations\n",
- "Ic=((alfa*Ie)+I_co)\n",
- "Ib=(Ie-Ic)\n",
- "Beta=alfa/(1-alfa)\n",
- "I_CEO=I_co/(1-alfa)\n",
- "\n",
- "#Result\n",
- "print(\"Ic,(mA) = %.3f\"%Ic)\n",
- "print(\"Ib,(micro-A) = %.f\"%(Ib*10**3))\n",
- "print(\"Beta = %.f\"%Beta)\n",
- "print(\"I_CEO(micro-A) = %.f\"%(I_CEO*10**3))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Ic,(mA) = 4.955\n",
- "Ib,(micro-A) = 45\n",
- "Beta = 99\n",
- "I_CEO(micro-A) = 500\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.7, Page No. 84"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# change in collector current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "alfa=0.9 # constant\n",
- "Del_Ib=4 # in mA\n",
- "\n",
- "#Caculations\n",
- "Beta=alfa/(1-alfa)\n",
- "Del_Ic=Beta*Del_Ib;\n",
- "\n",
- "#Result\n",
- "print(\"The change in the collector current,(mA) = %.f\"%Del_Ic)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The change in the collector current,(mA) = 36\n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.8, Page No. 84"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# emitter current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Beta=40.0 #beta\n",
- "Ib=25.0 # base current in micro-A\n",
- "\n",
- "#Calculation\n",
- "Ic=Beta*Ib;\n",
- "Ie=(Ib+Ic)*10**-3\n",
- "print(\"Ie,(mA) = %.3f\"%Ie)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Ie,(mA) = 1.025\n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.9, Page No. 85"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# beta \n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "alfa=0.98 # constant\n",
- "\n",
- "#Calculation\n",
- "Beta=alfa/(1-alfa)\n",
- "\n",
- "#Result\n",
- "print(\"Beta = %.f\"%Beta)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Beta = 49\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.10, Page No. 85"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# error\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Beta=100.0 # constant\n",
- "Ib=20*10**-6 # in A\n",
- "I_co=500*10**-9 # in A\n",
- "\n",
- "#Calculation\n",
- "Ic1=((Beta*Ib)+(1+Beta)*I_co)*10**3\n",
- "Ic2=(Beta*Ib)*10**3\n",
- "Error=(Ic1-Ic2)*100.0/Ic1\n",
- "\n",
- "#Result\n",
- "print(\"The error,(%%) = %.2f\"%Error)\n",
- "#answer is wrong in the txtbook"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The error,(%) = 2.46\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.11, Page No.85"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# change in base current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "alfa=0.98 \n",
- "del_Ie=5.0 # in mA\n",
- "\n",
- "#Calculations\n",
- "del_Ic=alfa*del_Ie # in mA\n",
- "del_Ib=del_Ie-del_Ic;\n",
- "\n",
- "#Result\n",
- "print(\"change in base current,(mA) = %.1f\"%del_Ib)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "change in base current,(mA) = 0.1\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.12, Page No. 86"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# collector current base current and alfa\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Ie=8.4 # in mA\n",
- "cr=0.8/100 # carriers recombine in base in %\n",
- "\n",
- "#Calculations\n",
- "Ib=cr*Ie\n",
- "Ic=Ie-Ib\n",
- "alfa=Ic/Ie\n",
- "\n",
- "#Result\n",
- "print(\"(a). The base current,Ib(mA) = %.3f\"%Ib)\n",
- "print(\"(b). The collector current,Ic(mA) = %.2f\"%Ic)\n",
- "print(\"(c). the value of alfa = %.3f\"%alfa)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a). The base current,Ib(mA) = 0.067\n",
- "(b). The collector current,Ic(mA) = 8.33\n",
- "(c). the value of alfa = 0.992\n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.13, Page No. 86"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# ac current gain\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Ie1=20.0 # in mA\n",
- "Ie2=15.0 # in mA\n",
- "Ib1=0.48 # in mA\n",
- "Ib2=0.32 # in mA\n",
- "\n",
- "#Calculation\n",
- "del_Ie=(Ie1-Ie2)*10**-3\n",
- "del_Ib=(Ib1-Ib2)*10**-3\n",
- "del_Ic=del_Ie-del_Ib\n",
- "alfa=del_Ic/del_Ie \n",
- "Beta=del_Ic/del_Ib\n",
- "\n",
- "#Result\n",
- "print(\"ac current gain in common base arrangement, = %.2f\"%alfa)\n",
- "print(\"ac current gain in common emitter arrangement, = %.f\"%Beta)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "ac current gain in common base arrangement, = 0.97\n",
- "ac current gain in common emitter arrangement, = 30\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.14, Page No. 87"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Beta Iceo and collector current \n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "alfa=0.992 # constant\n",
- "Ib=30*10**-6 # in A\n",
- "I_CBO=48*10**-9 # in A\n",
- "\n",
- "#Result\n",
- "Beta=alfa/(1-alfa)\n",
- "I_CEO=(1+Beta)*I_CBO*10**6\n",
- "Ic=((Beta*Ib)+(1+Beta)*I_CBO)*10**3\n",
- "\n",
- "#Result\n",
- "print(\"(a) Beta = %.f\"%Beta)\n",
- "print(\"(a) I_CEO (micro-A) = %.f\"%I_CEO)\n",
- "print(\"(b) Collector current,Ic(mA) = %.2f\"%(math.floor(Ic*100)/100))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Beta = 124\n",
- "(a) I_CEO (micro-A) = 6\n",
- "(b) Collector current,Ic(mA) = 3.72\n"
- ]
- }
- ],
- "prompt_number": 47
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.15, Page No. 87"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# collector current alfa and beta\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Ie=9.6 # emitter current in mA\n",
- "Ib=0.08 # base current in mA\n",
- "alfa=0.99\n",
- "\n",
- "Ic=Ie-Ib\n",
- "alfa=math.floor(Ic*100/Ie)/100\n",
- "Beta=alfa/(1-alfa)\n",
- "\n",
- "#Result\n",
- "print(\"(a). collector current,Ic(mA) = %.2f\"%Ic)\n",
- "print(\"(b). alfa = %.2f\"%alfa)\n",
- "print(\"(c). Beta = %.f\"%Beta)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a). collector current,Ic(mA) = 9.52\n",
- "(b). alfa = 0.99\n",
- "(c). Beta = 99\n"
- ]
- }
- ],
- "prompt_number": 51
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.16, Page No.87"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# collector current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Ib=68*10**-6 # in A\n",
- "Ie=30*10**-3 # in A\n",
- "Beta=440.0 # constant\n",
- "\n",
- "#Calculations\n",
- "alfa=Beta/(1+Beta)\n",
- "Ic=alfa*Ie*10**3\n",
- "\n",
- "#Result\n",
- "print(\"Collector current,Ic(mA) = %.2f\"%Ic)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Collector current,Ic(mA) = 29.93\n"
- ]
- }
- ],
- "prompt_number": 45
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
diff --git a/Solid_State_Electronics/Solid_State_electronics_Ch4.ipynb b/Solid_State_Electronics/Solid_State_electronics_Ch4.ipynb
deleted file mode 100755
index db0cddeb..00000000
--- a/Solid_State_Electronics/Solid_State_electronics_Ch4.ipynb
+++ /dev/null
@@ -1,950 +0,0 @@
-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 4: Small signal amplifliers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.1, Page No.118"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Rc=4.7 # in ohm\n",
- "Vcc=24.0 # in V\n",
- "Ic1=0 # in A\n",
- "Ic=1.5 # in mA\n",
- "#this is given as 15 mA in textbook which is wrong\n",
- "\n",
- "#Calculations\n",
- "Vce=Vcc-(Ic*Rc*10**-3*10**3)\n",
- "Vce1=Vcc-Ic1*Rc\n",
- "\n",
- "#Result\n",
- "print(\"(i) Collector to emitter voltage,Vce(V) = %.2f\"%Vce)\n",
- "print(\"(ii) Collector to emitter voltage,Vce(V) = %.f\"%Vce1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Collector to emitter voltage,Vce(V) = 16.95\n",
- "(ii) Collector to emitter voltage,Vce(V) = 24\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.2, Page No. 118"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# vce\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Beta=100.0\n",
- "Rb=200*10**3 # in ohm\n",
- "Rc=1*10**3 # in ohm\n",
- "Vcc=10.0 # in V\n",
- "\n",
- "#Calculations\n",
- "Ib=Vcc/Rb # in A\n",
- "Ic=Beta*Ib # in A\n",
- "Vce=Vcc-(Ic*Rc)\n",
- "\n",
- "#Result\n",
- "print(\"Collector to emitter voltage,Vce(V) = %.f\"%Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Collector to emitter voltage,Vce(V) = 5\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.3, Page No. 119"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# base resistance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vcc=20.0 # in V\n",
- "Vbe=0.73 # in V\n",
- "Rc=2.0 # in kilo-ohm\n",
- "Icsat= Vcc/Rc #in mA\n",
- "Beta=200.0\n",
- "\n",
- "#RCalculatons\n",
- "Ib=(Icsat/Beta)*10**3 # in micro-A\n",
- "Rb=((Vcc-Vbe)/(Ib))*10**3 # in kilo-ohm\n",
- "\n",
- "#Result\n",
- "print(\"Rb < %.f kilo-ohm\"%(math.ceil(Rb)))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Rb < 386 kilo-ohm\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.4, Page No. 119"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# operating point\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vcc=15.0 # in V\n",
- "Rb=200.0 # in k-ohm\n",
- "Rc=2.0 # in k-ohm\n",
- "Beta=50.0\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc/(Rb*10**3+(Beta*Rc*10**3)))*10**6\n",
- "Ic=Beta*Ib*10**-3\n",
- "Vce=Vcc-(Ic*10**-3*(Rc*10**3))\n",
- "\n",
- "#Result\n",
- "print(\"collector current,Ic(mA) = %.1f\"%Ic)\n",
- "print(\"Collector to emitter voltage,Vce(V) = %.f\"%Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "collector current,Ic(mA) = 2.5\n",
- "Collector to emitter voltage,Vce(V) = 10\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.5, Page No. 120"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resistor\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vcc=15.0 # in V\n",
- "Vce=6.0 # in V\n",
- "Rc=3*10**3 # in ohm\n",
- "Beta=50.0\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Ic=(Vcc-Vce)/Rc\n",
- "Ib=Ic/Beta;\n",
- "Rb=((Vcc/Ib)-(Beta*Rc))*10**-3\n",
- "\n",
- "#Result\n",
- "print(\"The value of resistoe,Rb(k-ohm) = %.f\"%Rb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of resistoe,Rb(k-ohm) = 100\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.6, Page No. 120"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# operating point\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vcc=12.0 # in V\n",
- "Rb1=70.0 # in k-ohm\n",
- "Rb2=70.0 # in k-ohm\n",
- "Beta=50.0\n",
- "Rc=2.0 # in k-ohm\n",
- "\n",
- "#Calculations\n",
- "Ib=Vcc/((Rb1+Rb2+(Beta*Rc))*10**3)\n",
- "Ic=Beta*Ib*10**3\n",
- "Vce=Vcc-(Ic*Rc)\n",
- "\n",
- "#Result\n",
- "print(\"Collector current,Ic(mA) = %.1f\"%Ic)\n",
- "print(\"Collector to emitter voltage,Vce(V) = %.f\"%Vce)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Collector current,Ic(mA) = 2.5\n",
- "Collector to emitter voltage,Vce(V) = 7\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.7, Page No. 121"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# operating point\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vcc=9.0 # in V\n",
- "Rb=50.0 # in k-ohm\n",
- "Rc=250.0 # in ohm\n",
- "Re=500.0 # in ohm\n",
- "Beta=80.0\n",
- "\n",
- "#Calculations\n",
- "Ib=Vcc/(Rb*10**3+(Beta*Re))\n",
- "Ic=Beta*Ib*10**3\n",
- "Vce=Vcc-(Ic*10**-3*(Rc+Re));\n",
- "\n",
- "#Result\n",
- "print(\"collector current,Ic(mA) = %.f\"%Ic)\n",
- "print(\"Collector to emitter voltage,Vce(V) = %.f\"%Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "collector current,Ic(mA) = 8\n",
- "Collector to emitter voltage,Vce(V) = 3\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.8, Page No. 121"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# operating point\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "R2=4.0 # in k-ohm\n",
- "R1=40.0 # in k-ohm\n",
- "Vcc=22.0 # in V\n",
- "Rc=10.0 # in k-ohm\n",
- "Re=1.5 # in k-ohm\n",
- "Vbe=0.5 # in V\n",
- "\n",
- "#Calculations\n",
- "Voc=R2*10**3*Vcc/((R1+R2)*10**3)\n",
- "Ic=(Voc-Vbe)/(Re*10**3)\n",
- "Vce=Vcc-(Rc+Re)*Ic*10**3\n",
- "\n",
- "#Result\n",
- "print(\"Collector to emitter voltage,Vce(V) = %.1f\"%Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Collector to emitter voltage,Vce(V) = 10.5\n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.9, Page No.124"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# maximum collector current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Bv=12.0 # battery voltage in V\n",
- "Cl=6.0 # collector load in k-ohm\n",
- "\n",
- "#Calculations\n",
- "CC=Bv/Cl\n",
- "\n",
- "#Result\n",
- "print(\"Collector current,(mA) = %.f\"%CC)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Collector current,(mA) = 2\n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.10, Page No. 125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# maximum collector current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Bv=12.0 # battery voltage in V\n",
- "P=2.0 # power in Watt\n",
- "\n",
- "#Calculations\n",
- "Ic=(P/Bv)*10**3\n",
- "\n",
- "#Result\n",
- "print(\"The maximum collector current,Ic(mA) = %.1f\"%Ic)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The maximum collector current,Ic(mA) = 166.7\n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.11, Page No. 125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# gain\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "del_ic=1.0 # in mA\n",
- "del_ib=10.0 # in micro-A\n",
- "del_Vbe=0.02 # in V\n",
- "del_ib=10*10**-6 # in A\n",
- "Rc=2.0 # in k-ohm\n",
- "Rl=10.0 # in k-ohm\n",
- "\n",
- "#Calculations\n",
- "Beta=del_ic/(del_ib*10**3)\n",
- "Ri=(del_Vbe/del_ib)*10**-3\n",
- "Rac=Rc*Rl/(Rc+Rl);\n",
- "Av=round(Beta*Rac/Ri);\n",
- "Ap=Beta*Av;\n",
- "\n",
- "#Result\n",
- "print(\"Current gain,Beta = %.f\"%Beta)\n",
- "print(\"Input impedence,Ri(k-ohm) = %.f\"%Ri)\n",
- "print(\"Effective load,Rac(k-ohm) = %.2f\"%(math.floor(Rac*100)/100))\n",
- "print(\"Voltage gain,Av = %.f\"%Av)\n",
- "print(\"power gain,Ap = %.f\"%Ap)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current gain,Beta = 100\n",
- "Input impedence,Ri(k-ohm) = 2\n",
- "Effective load,Rac(k-ohm) = 1.66\n",
- "Voltage gain,Av = 83\n",
- "power gain,Ap = 8300\n"
- ]
- }
- ],
- "prompt_number": 70
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.12, Page No. 125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# output voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Rc=10.0 # in k-ohm\n",
- "Rl=10 # in k-ohm\n",
- "Beta=100.0\n",
- "Ri=2.5\n",
- "Iv=2.0 # input voltage in mV\n",
- "\n",
- "#Calculations\n",
- "Rac=Rc*Rl/(Rc+Rl)\n",
- "Av=round(Beta*Rac/Ri)\n",
- "Ov=Av*Iv*10**-3\n",
- "\n",
- "#Result\n",
- "print(\"Output voltage,(V) = %.1f\"%Ov)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Output voltage,(V) = 0.4\n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.13, Page No.133"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# gain and resistance \n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "I=1.0\n",
- "hfe=46.0\n",
- "hoe=80*10**-6\n",
- "hre=5.4*10**-4\n",
- "hie=800.0 # in ohm\n",
- "RL=5*10**3 # in ohm\n",
- "Rg=500 # in ohm\n",
- "\n",
- "#Result\n",
- "Aie=hfe/(I+(hoe*RL))\n",
- "Aie = math.floor(Aie*10)/10\n",
- "Zie=hie-(hre*RL*Aie)\n",
- "Ave=(Aie*RL)/Zie\n",
- "Ave=math.floor(Ave*10)/10\n",
- "Zoe=((hie+Rg)/(hoe*(hie+Rg)-(hfe*hre)))/10**3\n",
- "Ape=Aie*Ave\n",
- "\n",
- "#Result\n",
- "print(\"Current gain,Aie = %.1f\"%(Aie))\n",
- "print(\"Input resistance,Zie(ohm) = %.1f\"%(Zie))\n",
- "print(\"Voltage gain,Ave = %.1f\"%Ave)\n",
- "print(\"Output resistance,Zoe(k-ohm) = %.1f\"%Zoe)\n",
- "print(\"Power gain,Ape = %.1f\"%Ape)\n",
- "#voltage gain and power gain are calculated wrong in the textbook"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current gain,Aie = 32.8\n",
- "Input resistance,Zie(ohm) = 711.4\n",
- "Voltage gain,Ave = 230.5\n",
- "Output resistance,Zoe(k-ohm) = 16.4\n",
- "Power gain,Ape = 7560.4\n"
- ]
- }
- ],
- "prompt_number": 79
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.14, Page No.141"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# gain and voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "A=100.0 # gain without feedback\n",
- "Beta=1.0/25 # feed back ratio\n",
- "vi=50.0 # mV\n",
- "Af=(A/(1+(Beta*A))) # gain with feedback\n",
- "ff=Beta*A # feedback factor\n",
- "Vo=Af*vi*10**-3 # in V\n",
- "fv=Beta*Vo # in V\n",
- "vin=vi*(1+Beta*A) # mV\n",
- "\n",
- "#Result\n",
- "print(\"gain with feedback is , = %.f\"%Af)\n",
- "print(\"feedback factor is, = %.f\"%ff)\n",
- "print(\"output voltage is ,(V) = %.f\"%Vo)\n",
- "print(\"feedback voltage is ,(V) = %.2f\"%fv)\n",
- "print(\"new increased input voltage is ,(mV) = %.f\"%vin)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "gain with feedback is , = 20\n",
- "feedback factor is, = 4\n",
- "output voltage is ,(V) = 1\n",
- "feedback voltage is ,(V) = 0.04\n",
- "new increased input voltage is ,(mV) = 250\n"
- ]
- }
- ],
- "prompt_number": 40
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.15, Page No. 142"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# voltage gain\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "A=1000.0 # gain without feedback\n",
- "fctr=0.40 # gain reduction factor\n",
- "\n",
- "A2=800.0 # redued gain\n",
- "\n",
- "#Calculations\n",
- "Af=A-fctr*A # gain with feedback\n",
- "Beta=((A/Af)-1)/A # feed back ratio\n",
- "Af2=((A2)/(1+(Beta*A2)))\n",
- "prfb= ((A-A2)/A)*100 #percentage reduction without feedback\n",
- "prwfb= ((Af-Af2)/Af)*100 #percentage reduction without feedback\n",
- "\n",
- "#Result\n",
- "print(\"(i) voltage gain is , = %.1f\"%Af2)\n",
- "print(\"(ii) percentage reduction without feedback is,(%%) = %.f\"%prfb)\n",
- "print(\" percentage reduction with feedback is,(%%) = %.2f\"%(math.ceil(prwfb*100)/100))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) voltage gain is , = 521.7\n",
- "(ii) percentage reduction without feedback is,(%) = 20\n",
- " percentage reduction with feedback is,(%) = 13.05\n"
- ]
- }
- ],
- "prompt_number": 81
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.16, Page No. 142"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# small change in gain\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "A=200.0 #gain without feedback\n",
- "Beta=0.25 #feed back ratio\n",
- "gc=10 #percent gain change\n",
- "\n",
- "#Calculations\n",
- "dA=gc/100.0\n",
- "dAf= ((1/(1+Beta*A)))*dA\n",
- "#Result\n",
- "print(\"small change in gain is, = %.4f\"%(math.floor(dAf*10**4)/10**4))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "small change in gain is, = 0.0019\n"
- ]
- }
- ],
- "prompt_number": 58
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.17, Page No.143"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# input voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "A=200.0 # gain without feedback\n",
- "Beta=0.05 # feed back ratio\n",
- "Dn=10.0 # percentage distortion\n",
- "vo=0.5 # initial output voltage\n",
- "\n",
- "#Calculations\n",
- "Af=(A/(1+(Beta*A))) # gain with feedback\n",
- "Dn1=(Dn/(1+A*Beta)) # percentage Distortion with negative feedback\n",
- "ff=Beta*A # feedback factor\n",
- "vi=A*vo # in V\n",
- "vin=vi/Af # in V\n",
- "\n",
- "#Result\n",
- "print(\"gain with negative feedback is , = %.1f\"%Af)\n",
- "print(\"percentage Distortion with negative feedback is ,(%%) = %.3f\"%Dn1)\n",
- "print(\"new input voltage is ,(V) = %.1f\"%vin)\n",
- "#gain and input voltage are calculated wrong in the textbook "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "gain with negative feedback is , = 18.2\n",
- "percentage Distortion with negative feedback is ,(%) = 0.909\n",
- "new input voltage is ,(V) = 5.5\n"
- ]
- }
- ],
- "prompt_number": 83
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.18, Page No. 143"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# percentage of feedback\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "A=50.0 # gain without feedback\n",
- "Af=10.0 # gain with feedback\n",
- "\n",
- "#Calculations\n",
- "Beta=(((A/Af)-1)/A)*100 # feed back ratio\n",
- "print(\"percentage of feedback is ,(%%) = %.f\"%Beta)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "percentage of feedback is ,(%) = 8\n"
- ]
- }
- ],
- "prompt_number": 84
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.19, Page No. 144"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# band width\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Bw=200.0 # bandwidth in kHz\n",
- "vg=40.0 # dB\n",
- "fb=5.0 # percentage negetive feedback\n",
- "A=40.0 # gain without feedback\n",
- "\n",
- "#Calculations\n",
- "Beta=fb/100 # feed back ratio\n",
- "Af=(A/(1+(Beta*A))) # gain with feedback\n",
- "Bwf= (A*Bw)/Af # Bandwidth with feedback\n",
- "\n",
- "#Result\n",
- "print(\" new band-width is ,(kHz) = %.f\"%Bwf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " new band-width is ,(kHz) = 600\n"
- ]
- }
- ],
- "prompt_number": 52
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.20, Page No. 144"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# percentage reduction\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "A=50.0 # gain without feedback\n",
- "Af=25.0 # gain with feedback\n",
- "Ad=40.0 # new gain after ageing\n",
- "\n",
- "#Calculations\n",
- "Beta=(((A/Af)-1)/A) # feed back ratio\n",
- "Af1=(Ad/(1+(Beta*Ad)))# new gain with feedback\n",
- "df=Af-Af1 # reduction in gain\n",
- "pdf= (df/Af)*100 # percentage reduction in gain\n",
- "\n",
- "#Result\n",
- "print(\" percentage reduction in gain is ,(%%) = %.1f\"%pdf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " percentage reduction in gain is ,(%) = 11.1\n"
- ]
- }
- ],
- "prompt_number": 55
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.21, Page No. 145"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Av and beta\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Af=100.0 # gain with feeback\n",
- "vi=50.0 # in mV\n",
- "vi1=60.0 # in mV\n",
- "\n",
- "#Calcualtion\n",
- "AAf=vi1/vi\n",
- "A=AAf*Af\n",
- "Beta=(((A/Af)-1)/A)\n",
- "\n",
- "#Result\n",
- "print(\"Av is ,= %.f\"%A)\n",
- "print(\"feedback factor is, = %.5f or 1/600\"%Beta)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Av is ,= 120\n",
- "feedback factor is, = 0.00167 or 1/600\n"
- ]
- }
- ],
- "prompt_number": 57
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
diff --git a/Solid_State_Electronics/Solid_State_electronics_Ch5.ipynb b/Solid_State_Electronics/Solid_State_electronics_Ch5.ipynb
deleted file mode 100755
index 6b01a9c6..00000000
--- a/Solid_State_Electronics/Solid_State_electronics_Ch5.ipynb
+++ /dev/null
@@ -1,331 +0,0 @@
-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 5 : Power Amplifiers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1, Page No. 167"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# efficiency\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Pac=0.1 #in W\n",
- "Vcc=20.0 #in V\n",
- "Ic=20.0 #in mA\n",
- "\n",
- "#Calculations\n",
- "Pdc=Vcc*Ic*10**-3 #in W\n",
- "eta=(Pac/Pdc)*100 #efficiency\n",
- "\n",
- "#Result\n",
- "print(\"efficiency is ,(%%)= %.f\"%eta)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "efficiency is ,(%)= 25\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.2, Page No. 167"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# collector current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Pac=2.0 #in W\n",
- "Vcc=12.0 #in V\n",
- "\n",
- "#Calculations\n",
- "Ic=(Pac*math.sqrt(2)*math.sqrt(2))/Vcc\n",
- "\n",
- "#Result\n",
- "print(\"maximum collector current is ,(A)= %.2f\" %Ic)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum collector current is ,(A)= 0.33\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.3, Page No. 167"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# collector efficiency and power rating\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Pac=3.0 #in W\n",
- "Pdc=10.0 #in W\n",
- "\n",
- "#Calculations\n",
- "eta=(Pac/Pdc)*100 #percentage efficieny \n",
- "\n",
- "#Result\n",
- "print(\"collector efficiency is , (%%) = %.f\"%eta)\n",
- "print(\"power rating of transistor is ,(W) = %.f\" %Pdc)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "collector efficiency is , (%) = 30\n",
- "power rating of transistor is ,(W) = 10\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.4, Page No. 168"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# power\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "dIc=100.0 #in mA\n",
- "Rl=6.0 #in ohm\n",
- "Rl=6.0 #in ohm\n",
- "dVc=10.0 #in V\n",
- "\n",
- "#Calculations\n",
- "mv=dIc*Rl*10**-3 #in V\n",
- "pd=mv*dIc #in mW\n",
- "oi=(dVc/dIc)*10**3 #in ohm\n",
- "n=math.sqrt(oi/Rl) #turn ratio of transformer\n",
- "tsv=dVc/n #om V\n",
- "Il=tsv/Rl #in A\n",
- "ptr= Il**2*Rl*10**3 #in mW\n",
- "\n",
- "#Result\n",
- "print(\"(i) power developed in loudspeaker is , (mW)= %.f\"%pd)\n",
- "print(\"(ii) power transferred to loudspeaker is ,(mw)= %.f\"%ptr)\n",
- "#in textbook in second case there is one point deviation in the answer."
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) power developed in loudspeaker is , (mW)= 60\n",
- "(ii) power transferred to loudspeaker is ,(mw)= 1000\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.5, Page No. 168"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# power\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "n=10.0 #turn ratio\n",
- "Rl=10.0 #ohm\n",
- "Ic=100.0 #in mA\n",
- "\n",
- "#Result\n",
- "Rld=n**2*Rl #in ohm\n",
- "Irms=Ic/(math.sqrt(2)) #in mA\n",
- "P=Irms**2*Rld #in W\n",
- "\n",
- "#Result\n",
- "print(\"maximum power output is ,(W)= %.f\"%(P*10**-6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum power output is ,(W)= 5\n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.6, Page No. 169"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# harmonic distortions and change in power\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "#ie=15*sin 400*t+1.5*sin 800*t + 1.2*sin 1200*t + 0.5*sin 1600*t given equation\n",
- "I2=1.5 #in A\n",
- "I1=15.0 #in A\n",
- "I3=1.2 #in A\n",
- "I4=0.5 #in A\n",
- "D2=(I2/I1)*100 #Second percentage harmonic distortion\n",
- "D3=(I3/I1)*100 #Third percentage harmonic distortion\n",
- "#in book I2 is mentioned wrongly in place of I1\n",
- "D4=(I4/I1)*100 #Fourth percentage harmonic distortion\n",
- "D=math.sqrt(D2**2+D3**2+D4**2)/100 #Distortion Factor\n",
- "P1=1.0 #assume\n",
- "P=(1+D**2)*P1 #in W\n",
- "peri=((P-P1)/P1)*100 #percentage increase in power due to distortion\n",
- "\n",
- "#Result\n",
- "print(\"part (i)\")\n",
- "print(\"Second percentage harmonic distortion (D2) is ,(%%) = %.f\"%D2)\n",
- "print(\"Third percentage harmonic distortion (D3) is ,(%%) = %.f\"%D3)\n",
- "print(\"Fourth percentage harmonic distortion (D4) is ,(%%) = %.2f\"%D4)\n",
- "print(\"\\npart (ii)\")\n",
- "print(\"percentage increase in power due to distortion is ,(%%) = %.2f\"%peri)\n",
- "# answer for % increase is slightly different than book"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "part (i)\n",
- "Second percentage harmonic distortion (D2) is ,(%) = 10\n",
- "Third percentage harmonic distortion (D3) is ,(%) = 8\n",
- "Fourth percentage harmonic distortion (D4) is ,(%) = 3.33\n",
- "\n",
- "part (ii)\n",
- "percentage increase in power due to distortion is ,(%) = 1.75\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.7, Page No. 169"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# power dissipated\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vcc=15.0 #in V\n",
- "Vpeak=24.0/2 #in V\n",
- "Rl=100.0 #in ohm\n",
- "\n",
- "#Calculations\n",
- "Ipeak= Vpeak/Rl #in A\n",
- "Pdc=Vcc*(2/(math.pi))*Ipeak #in W\n",
- "pad=(1.0/2)*(Vpeak**2)/Rl #in W\n",
- "pd=Pdc-pad #in W\n",
- "pde=pd/2 #in W\n",
- "\n",
- "#Result\n",
- "print(\"power dissipated by each transistor is,(mW)= %.f\"%(pde*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "power dissipated by each transistor is,(mW)= 213\n"
- ]
- }
- ],
- "prompt_number": 28
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
diff --git a/Solid_State_Electronics/Solid_State_electronics_Ch6.ipynb b/Solid_State_Electronics/Solid_State_electronics_Ch6.ipynb
deleted file mode 100755
index ebc711df..00000000
--- a/Solid_State_Electronics/Solid_State_electronics_Ch6.ipynb
+++ /dev/null
@@ -1,325 +0,0 @@
-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 6 : Field Effect Transistors"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.1, Page No. 184"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# drain resistance transconductance and amplification factor\n",
- "\n",
- "import math\n",
- "from array import array\n",
- "#Variable declaration\n",
- "Vgs=array('d', [0.0, 0.0, 0.3]) #in V\n",
- "Vds=array('d',[5.0, 10.0, 10.0]) #in V\n",
- "Id=array('d',[8.0, 8.2, 7.6]) #in mA\n",
- "\n",
- "#Calcualtions\n",
- "dVds=Vds[1]-Vds[0] #in V\n",
- "dId=Id[1]-Id[0] #in mA\n",
- "rd=(dVds/dId) #in kilo-ohm\n",
- "dVgs=Vgs[2]-Vgs[1] #in V\n",
- "dId1=Id[1]-Id[2] #in mA\n",
- "gm=dId1/dVgs #in mA/volt\n",
- "mu=gm*rd #A/V\n",
- "\n",
- "#Result\n",
- "print(\"(i) A.C. Drain resistance is ,(kilo-ohm)= %.f\"%rd)\n",
- "print(\"(ii) Transconductance is ,(mS) = %.f\"%gm)\n",
- "print(\"(iii) Amplification factor is , = %.f\"%mu)\n",
- "#Transconductance and Amplification factor are calculated wrong in the textbook"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) A.C. Drain resistance is ,(kilo-ohm)= 25\n",
- "(ii) Transconductance is ,(mS) = 2\n",
- "(iii) Amplification factor is , = 50\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.2, Page No. 184"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# mutual conductance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "I1=1.0 # in mA\n",
- "I2=1.2 # in mA\n",
- "V1=-3.0 # in V\n",
- "V2=-2.9 # in V\n",
- "\n",
- "#Calculations\n",
- "del_ID=(I2-I1)\n",
- "del_VGS=V2-V1 # in V\n",
- "gm=del_ID/del_VGS\n",
- "\n",
- "#Result\n",
- "print(\"mutual conductance,gm(mS) = %.f\"%gm)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "mutual conductance,gm(mS) = 2\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.3, Page No. 185"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# pinch off voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "a=5.6*10**-6/2 # channel width in m\n",
- "epsilon0=8.86*10**-12 # in F/m\n",
- "epsilon=12*epsilon0 # in F/m\n",
- "Nd=10**21 # in m^-3\n",
- "e=1.6*10**-19 # in V\n",
- "\n",
- "#Calculations\n",
- "Vp=e*Nd*a**2/(2*epsilon);\n",
- "\n",
- "#Result\n",
- "print(\"Pinch off voltage,Vp(V) = %.1f\"%Vp)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Pinch off voltage,Vp(V) = 5.9\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.4, Page No. 185"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# ID gm and gmo\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "I_DES=8.7 # in mA\n",
- "V1=-3.0 # in V\n",
- "V_GS=-1.0 # in V\n",
- "\n",
- "\n",
- "#Calculations\n",
- "gmo=-(2*I_DES/V1)\n",
- "ID=I_DES*(1-(V_GS/V1))**2\n",
- "gm=gmo*(1-(V_GS/V1));\n",
- "\n",
- "#Result\n",
- "print(\"(i). ID(mA) = %.3f\"%(math.floor(ID*1000)/1000))\n",
- "print(\"(ii). gmo(mS) = %.1f\"%gmo)\n",
- "print(\"(iii).gm(mA) = %.3f\"%(math.floor(gm*1000)/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i). ID(mA) = 3.866\n",
- "(ii). gmo(mS) = 5.8\n",
- "(iii).gm(mA) = 3.866\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.5, Page No. 186"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Vgs\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "ID=3.0 # in mA\n",
- "I_DSS=9.0 # in mA\n",
- "Vp=-4.5 # in V\n",
- "\n",
- "#Calculations\n",
- "Vgs=-Vp*(math.sqrt(ID/I_DSS)-1)\n",
- "\n",
- "\n",
- "#Result\n",
- "print(\"Vgs(V) = %.1f\"%Vgs)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Vgs(V) = -1.9\n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.6, Page No. 196"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# voltage amplification\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "gm=3 #Transconductance in mS\n",
- "rl=10 #load resistance in kilo-ohm\n",
- "\n",
- "#Calculations\n",
- "av=gm*rl\n",
- "#Result\n",
- "print(\"the voltage aplification is ,= %.f\"%av)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the voltage aplification is ,= 30\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.7, Page No. 196"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# output voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Rl=20.0 #in kilo-ohm\n",
- "Rs=1.0 #in kilo-ohm\n",
- "Rg=1.0 #in M-ohm\n",
- "Cs=25.0 #in micro-F\n",
- "mu=20.0 #amplification factor\n",
- "rd=100.0 #in kilo-ohm\n",
- "vi=2.0 #in V\n",
- "f=1.0 #in kilo-Hz\n",
- "\n",
- "#Calculations\n",
- "Xc=((1/(2*math.pi*f*10**3*Cs*10**-6)))\n",
- "A=((mu*Rl*10**3)/((rd+Rl)*10**3))\n",
- "Vo=A*vi\n",
- "\n",
- "#Result\n",
- "print(\"amplifier output signal voltage is ,(V)= %.2f\"%(math.floor(Vo*100)/100))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "amplifier output signal voltage is ,(V)= 6.66\n"
- ]
- }
- ],
- "prompt_number": 3
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
diff --git a/Solid_State_Electronics/Solid_State_electronics_Ch9.ipynb b/Solid_State_Electronics/Solid_State_electronics_Ch9.ipynb
deleted file mode 100755
index 1a3e4d3e..00000000
--- a/Solid_State_Electronics/Solid_State_electronics_Ch9.ipynb
+++ /dev/null
@@ -1,154 +0,0 @@
-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 9 : Silicon Controlled Rectifier"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 9.1, Page No. 238 "
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# average voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vm=200.0 #in V\n",
- "theta=30.0 #firing angle in degree\n",
- "\n",
- "#Calculations\n",
- "vdc=((Vm/math.pi)*(1+math.cos(theta*math.pi/180)))\n",
- "\n",
- "#Result\n",
- "print(\"average value of voltage is ,(V)= %.f\"%(round(vdc)))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "average value of voltage is ,(V)= 119\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 9.2, Page No. 238"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# dc load current rms load current amd power dissipiated\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Va=300.0 # in V\n",
- "Vm=300.0*math.sqrt(2) # in V\n",
- "Rl=50.0 #in ohm\n",
- "theta1=90.0 #firing angle in degree\n",
- "\n",
- "#Calculations\n",
- "idc=((Vm/(2*math.pi*Rl))*(1+math.cos(theta1*math.pi/180)))\n",
- "irms=Va/(2*Rl)\n",
- "P=irms**2*Rl\n",
- "\n",
- "#Result\n",
- "print(\"(i) The dc load current is ,(A) = %.2f\"%idc)\n",
- "print(\"(ii) The rms load current is ,(A) = %.f\"%(round(irms)))\n",
- "print(\"(iii) The power dissipated by the load is ,(W)= %.f\"%(round(P)))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) The dc load current is ,(A) = 1.35\n",
- "(ii) The rms load current is ,(A) = 3\n",
- "(iii) The power dissipated by the load is ,(W)= 450\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 9.3, Page No. 239"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# firing angle conducting angle and average current\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Ih=0.0 #in A\n",
- "Vi=100.0 #in V\n",
- "Vm=200.0 #in V\n",
- "Rl=100.0 #in ohm\n",
- "\n",
- "#Calculations\n",
- "theta1=(180/math.pi)*math.asin(Vi/Vm) #firing angle in degree\n",
- "ca=180-theta1 #conducting angle in dehree\n",
- "av=((Vm/(2*math.pi))*(1+math.cos(theta1*math.pi/180)))\n",
- "ac=av/Rl \n",
- "\n",
- "#Result \n",
- "print(\"(i) firing angle is ,(degree) = %.f\u00b0\"%(theta1))\n",
- "print(\"(ii) conducting angle is ,(degree) = %.f\u00b0\"%ca)\n",
- "print(\"(iii) average current is ,(A) = %.4f\"%ac)\n",
- "#average current is wrong in the textbook"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) firing angle is ,(degree) = 30\u00b0\n",
- "(ii) conducting angle is ,(degree) = 150\u00b0\n",
- "(iii) average current is ,(A) = 0.5940\n"
- ]
- }
- ],
- "prompt_number": 10
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file