Solves a multi-variable optimization problem on a bounded interval
xopt = intfminbnd(f,intcon,x1,x2) xopt = intfminbnd(f,intcon,x1,x2,options) [xopt,fopt] = intfminbnd(.....) [xopt,fopt,exitflag]= intfminbnd(.....) [xopt,fopt,exitflag,output]=intfminbnd(.....) [xopt,fopt,exitflag,gradient,hessian]=intfminbnd(.....)
A function, representing the objective function of the problem.
A vector, containing the lower bound of the variables of size (1 X n) or (n X 1) where n is number of variables. If it is empty it means that the lower bound is .
A vector, containing the upper bound of the variables of size (1 X n) or (n X 1) or (0 X 0) where n is the number of variables. If it is empty it means that the upper bound is .
A vector of integers, representing the variables that are constrained to be integers.
A list, containing the options for user to specify. See below for details.
A vector of doubles, containing the computed solution of the optimization problem.
A double, containing the the function value at x.
An integer, containing the flag which denotes the reason for termination of algorithm. See below for details.
A vector of doubles, containing the objective's gradient of the solution.
A matrix of doubles, containing the Lagrangian's hessian of the solution.
Search the minimum of a multi-variable function on bounded interval specified by : Find the minimum of f(x) such that
intfminbnd calls Bonmin, which is an optimization library written in C++, to solve the bound optimization problem.
options= list("IntegerTolerance", [---], "MaxNodes",[---], "MaxIter", [---], "AllowableGap",[---] "CpuTime", [---],"gradobj", "off", "hessian", "off" );
options = list('integertolerance',1d-06,'maxnodes',2147483647,'cputime',1d10,'allowablegap',0,'maxiter',2147483647,'gradobj',"off",'hessian',"off")
The exitflag allows the user to know the status of the optimization which is returned by Bonmin. The values it can take and what they indicate is described below:
For more details on exitflag, see the Bonmin documentation which can be found on http://www.coin-or.org/Bonmin
A few examples displaying the various functionalities of intfminbnd have been provided below. You will find a series of problems and the appropriate code snippets to solve them.
We start with a simple objective function. Find x in R^6 such that it minimizes:
//Example 1: //Objective function to be minimised function y=f(x) y=0 for i =1:6 y=y+sin(x(i)); end endfunction //Variable bounds x1 = [-2, -2, -2, -2, -2, -2]; x2 = [2, 2, 2, 2, 2, 2]; intcon = [2 3 4] [x,fval] =intfminbnd(f ,intcon, x1, x2) // Press ENTER to continue | ![]() | ![]() |
//Example 2: //Objective function to be minimised function y=f(x) y=0 for i =1:6 y=y+sin(x(i)); end endfunction //Variable bounds x1 = [-2, -2, -2, -2, -2, -2]; x2 = [2, 2, 2, 2, 2, 2]; intcon = [2 3 4] //Options options=list("MaxIter",[1500],"CpuTime", [100]) [x,fval] =intfminbnd(f ,intcon, x1, x2, options) // Press ENTER to continue | ![]() | ![]() |
Unbounded Problems: Find x in R^2 such that it minimizes:
///Example 3: Unbounded problem: //Objective function to be minimised function y=f(x) y=-((x(1)-1)^2+(x(2)-1)^2); endfunction //Variable bounds x1 = [-%inf , -%inf]; x2 = [ %inf , %inf]; //Options options=list("MaxIter",[1500],"CpuTime", [100]); intcon = [1 2]; [x,fval,exitflag,output,lambda] =intfminbnd(f,intcon, x1, x2, options) | ![]() | ![]() |