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diff --git a/Principles_Of_Geotechnical_Engineering_by_B_M_Das/15-Slope_Stability.ipynb b/Principles_Of_Geotechnical_Engineering_by_B_M_Das/15-Slope_Stability.ipynb new file mode 100644 index 0000000..6968ca3 --- /dev/null +++ b/Principles_Of_Geotechnical_Engineering_by_B_M_Das/15-Slope_Stability.ipynb @@ -0,0 +1,333 @@ +{ +"cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 15: Slope Stability" + ] + }, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.11: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"C=20\n", +"G=18.5\n", +"H=21.62\n", +"c=25\n", +"r=0.25\n", +"Fs=3.1*tand(c)\n", +"printf('Fs = %f',Fs)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.1: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"Gs=17.8\n", +"Gw=9.81\n", +"C=10\n", +"c=20\n", +"b=15\n", +"H=6\n", +"G=Gs-Gw\n", +"Fs= C/(Gs*H*cosd(b)*cosd(b)*tand(b))+G*tand(c)/(Gs*tand(b))\n", +"printf('a)The factor of safety = %f \n',Fs)\n", +"Fs=2\n", +"H=2.247/(Fs-0.61)\n", +"printf(' b)H= %f m',H)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.2: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"G=105\n", +"c=15\n", +"C=600\n", +"b=45\n", +"Fs=3\n", +"Cd=C/Fs\n", +"c1= atand(tand(c)/Fs)\n", +"\n", +"H= 4*Cd*(sind(b)*cosd(c1)/(1-cosd(b-c1)))/G\n", +"printf('The depth of the cut slope = %f ft',H)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.3: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"Cu=40\n", +"G=17.5\n", +"b=60\n", +"a=35\n", +"c=72.5\n", +"m=0.195\n", +"Hc=Cu/(G*m)\n", +"r=Hc/(2*sind(a)*sind(c/2))\n", +"BC=Hc*((1/tand(a))-(1/tand(b)))\n", +"printf('a)The maximum depth Hc = %f m\n',Hc)\n", +"printf(' b)The radius, r = %f m\n',r)\n", +"printf(' c)The distance BC.= %f m',BC)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.4: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"Gs=17.29\n", +"d=9.15\n", +"d1=6.1\n", +"D=d/d1\n", +"a=40\n", +"m=0.175\n", +"b=40\n", +"H=6.1\n", +"Cu=H*Gs*m\n", +"printf('a)The undrained cohesion of the clay Cu = %f kN/m^2\n',Cu)\n", +"printf(' b)The nature of the critical circle is midpointcircle\n')\n", +"d=1.5\n", +"b=40\n", +"n=0.9\n", +"D1=n*H\n", +"printf(' c)Distance = %f m',D1)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.5: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"Fs=1\n", +"b=56\n", +"Kh=0.25\n", +"M=3.66\n", +"Cu=500\n", +"G=100\n", +"Hc=Cu*M/G\n", +"printf('a)The maximum depth = %f ft\n',Hc)\n", +"Fs=2\n", +"H=Cu*M/(G*Fs)\n", +"printf(' b)H= %f ft',H)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.6: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"b=45\n", +"c=20\n", +"C=24\n", +"G=18.9\n", +"m=0.06\n", +"Hc=C/(G*m)\n", +"Cd=G*Hc*m\n", +"Fc=C/Cd\n", +"printf('a)Critical height of slope = %f \n',Hc)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.7: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"FSs=1\n", +"c=20\n", +"G=18.9\n", +"C=24\n", +"Hcr=C/(G*tand(c)*0.17)\n", +"printf('a)Critical height Hc = %f m\n',Hcr)\n", +"H=10\n", +"k=C/(G*H*tand(c))\n", +"Fs=4*tand(c)\n", +"printf(' b)Fs = %f',Fs)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.8: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"W=22.4\n", +"C=20\n", +"a=70\n", +"s=sind(a)\n", +"c=cosd(a)\n", +"l=2.924\n", +"Wn=W*s\n", +"Wn1=W*c\n", +"//doing this to all values\n", +"F1=30.501\n", +"F2=776.75\n", +"F3=1638\n", +"Fs=(F1*C+F3*tand(C))/F2\n", +"printf('Fs = %f',Fs)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 15.9: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"C=20\n", +"G=18.5\n", +"r=0.25\n", +"H=21.62\n", +"C=25\n", +"b= atand(0.5)\n", +"//from table 15.3 \n", +"m=1.624\n", +"n=1.338\n", +"Fs=m-n*r\n", +"printf(' The value of Fs for D= 1 is %f',Fs)" + ] + } +], +"metadata": { + "kernelspec": { + "display_name": "Scilab", + "language": "scilab", + "name": "scilab" + }, + "language_info": { + "file_extension": ".sce", + "help_links": [ + { + "text": "MetaKernel Magics", + "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md" + } + ], + "mimetype": "text/x-octave", + "name": "scilab", + "version": "0.7.1" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |