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diff --git a/Principles_Of_Geotechnical_Engineering_by_B_M_Das/15-Slope_Stability.ipynb b/Principles_Of_Geotechnical_Engineering_by_B_M_Das/15-Slope_Stability.ipynb
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+{
+"cells": [
+ {
+		   "cell_type": "markdown",
+	   "metadata": {},
+	   "source": [
+       "# Chapter 15: Slope Stability"
+	   ]
+	},
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.11: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"C=20\n",
+"G=18.5\n",
+"H=21.62\n",
+"c=25\n",
+"r=0.25\n",
+"Fs=3.1*tand(c)\n",
+"printf('Fs = %f',Fs)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.1: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"Gs=17.8\n",
+"Gw=9.81\n",
+"C=10\n",
+"c=20\n",
+"b=15\n",
+"H=6\n",
+"G=Gs-Gw\n",
+"Fs= C/(Gs*H*cosd(b)*cosd(b)*tand(b))+G*tand(c)/(Gs*tand(b))\n",
+"printf('a)The factor of safety = %f \n',Fs)\n",
+"Fs=2\n",
+"H=2.247/(Fs-0.61)\n",
+"printf(' b)H= %f m',H)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.2: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"G=105\n",
+"c=15\n",
+"C=600\n",
+"b=45\n",
+"Fs=3\n",
+"Cd=C/Fs\n",
+"c1= atand(tand(c)/Fs)\n",
+"\n",
+"H= 4*Cd*(sind(b)*cosd(c1)/(1-cosd(b-c1)))/G\n",
+"printf('The depth of the cut slope = %f ft',H)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.3: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"Cu=40\n",
+"G=17.5\n",
+"b=60\n",
+"a=35\n",
+"c=72.5\n",
+"m=0.195\n",
+"Hc=Cu/(G*m)\n",
+"r=Hc/(2*sind(a)*sind(c/2))\n",
+"BC=Hc*((1/tand(a))-(1/tand(b)))\n",
+"printf('a)The maximum depth Hc = %f m\n',Hc)\n",
+"printf(' b)The radius, r = %f m\n',r)\n",
+"printf(' c)The distance BC.= %f m',BC)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.4: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"Gs=17.29\n",
+"d=9.15\n",
+"d1=6.1\n",
+"D=d/d1\n",
+"a=40\n",
+"m=0.175\n",
+"b=40\n",
+"H=6.1\n",
+"Cu=H*Gs*m\n",
+"printf('a)The undrained cohesion of the clay Cu = %f kN/m^2\n',Cu)\n",
+"printf(' b)The nature of the critical circle is midpointcircle\n')\n",
+"d=1.5\n",
+"b=40\n",
+"n=0.9\n",
+"D1=n*H\n",
+"printf(' c)Distance = %f m',D1)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.5: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"Fs=1\n",
+"b=56\n",
+"Kh=0.25\n",
+"M=3.66\n",
+"Cu=500\n",
+"G=100\n",
+"Hc=Cu*M/G\n",
+"printf('a)The maximum depth = %f ft\n',Hc)\n",
+"Fs=2\n",
+"H=Cu*M/(G*Fs)\n",
+"printf(' b)H= %f ft',H)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.6: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"b=45\n",
+"c=20\n",
+"C=24\n",
+"G=18.9\n",
+"m=0.06\n",
+"Hc=C/(G*m)\n",
+"Cd=G*Hc*m\n",
+"Fc=C/Cd\n",
+"printf('a)Critical height of slope = %f \n',Hc)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.7: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"FSs=1\n",
+"c=20\n",
+"G=18.9\n",
+"C=24\n",
+"Hcr=C/(G*tand(c)*0.17)\n",
+"printf('a)Critical height Hc = %f m\n',Hcr)\n",
+"H=10\n",
+"k=C/(G*H*tand(c))\n",
+"Fs=4*tand(c)\n",
+"printf(' b)Fs = %f',Fs)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.8: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"W=22.4\n",
+"C=20\n",
+"a=70\n",
+"s=sind(a)\n",
+"c=cosd(a)\n",
+"l=2.924\n",
+"Wn=W*s\n",
+"Wn1=W*c\n",
+"//doing this to all values\n",
+"F1=30.501\n",
+"F2=776.75\n",
+"F3=1638\n",
+"Fs=(F1*C+F3*tand(C))/F2\n",
+"printf('Fs = %f',Fs)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 15.9: solved.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"C=20\n",
+"G=18.5\n",
+"r=0.25\n",
+"H=21.62\n",
+"C=25\n",
+"b= atand(0.5)\n",
+"//from table 15.3 \n",
+"m=1.624\n",
+"n=1.338\n",
+"Fs=m-n*r\n",
+"printf(' The value of Fs for D= 1 is %f',Fs)"
+   ]
+   }
+],
+"metadata": {
+		  "kernelspec": {
+		   "display_name": "Scilab",
+		   "language": "scilab",
+		   "name": "scilab"
+		  },
+		  "language_info": {
+		   "file_extension": ".sce",
+		   "help_links": [
+			{
+			 "text": "MetaKernel Magics",
+			 "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
+			}
+		   ],
+		   "mimetype": "text/x-octave",
+		   "name": "scilab",
+		   "version": "0.7.1"
+		  }
+		 },
+		 "nbformat": 4,
+		 "nbformat_minor": 0
+}