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+{
+"cells": [
+ {
+		   "cell_type": "markdown",
+	   "metadata": {},
+	   "source": [
+       "# Chapter 25: Electric Potential"
+	   ]
+	},
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 25.1: Sample_Problem_1.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"exec('electrostatics.sci', -1)\n",
+"\n",
+"//Given that\n",
+"E = 150  //in N/C\n",
+"d = -520  //in meter\n",
+"\n",
+"//Sample Problem 25-1\n",
+"printf('**Sample Problem 25-1**\n')\n",
+"W = E*(-e)*d\n",
+"deltaU = -W\n",
+"printf('The change in potential energy is %eJ', deltaU)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 25.3: Sample_Problem_3.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"exec('electrostatics.sci', -1)\n",
+"\n",
+"//Given that\n",
+"d = 1.3  //in meter\n",
+"q1 = 12*10^-9  //in C\n",
+"q2 = -24*10^-9  //in C\n",
+"q3 = +31*10^-9  //in C\n",
+"q4 = 17*10^-9  //in C\n",
+"\n",
+"//Sample Problem 25-3\n",
+"printf('**Sample Problem 25-3**\n')\n",
+"V = EPotential(q1+q2+q3+q4, d/sqrt(2))\n",
+"printf('The electric potential at point P is equal to %eV', V)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 25.4: Sample_Problem_4.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"exec('electrostatics.sci', -1)\n",
+"\n",
+"//Given that\n",
+"n = 12\n",
+"qT = -n*e\n",
+"R = 1  //(say)\n",
+"\n",
+"//Sample Problem 25-4a\n",
+"printf('**Sample Problem 25-4a**\n')\n",
+"V = EPotential(qT, R)\n",
+"printf('The electric potential at the center is equal to %e/R Volts', V)\n",
+"\n",
+"//Sample Problem 25-4b\n",
+"printf('**Sample Problem 25-4b**\n')\n",
+"printf('It does not change in this configuration')"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 25.6: Sample_Problem_6.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"exec('electrostatics.sci', -1)\n",
+"\n",
+"//Given that\n",
+"d = 12*10^-2  //in cm\n",
+"q = 150*10^-9   //in C\n",
+"q1 = +q\n",
+"q2 = -4*q\n",
+"q3 = +2*q\n",
+"\n",
+"//Sample Problem 25-6\n",
+"printf('**Sample Problem 25-6**\n')\n",
+"U = EPotential(q1, d)*q2 + EPotential(q2, d)*q3 + EPotential(q3, d)*q1\n",
+"printf('The electric potential energy of the system is equal to %eJ', U)"
+   ]
+   }
+],
+"metadata": {
+		  "kernelspec": {
+		   "display_name": "Scilab",
+		   "language": "scilab",
+		   "name": "scilab"
+		  },
+		  "language_info": {
+		   "file_extension": ".sce",
+		   "help_links": [
+			{
+			 "text": "MetaKernel Magics",
+			 "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
+			}
+		   ],
+		   "mimetype": "text/x-octave",
+		   "name": "scilab",
+		   "version": "0.7.1"
+		  }
+		 },
+		 "nbformat": 4,
+		 "nbformat_minor": 0
+}