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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 25: Electric Potential"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 25.1: Sample_Problem_1.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"exec('electrostatics.sci', -1)\n",
"\n",
"//Given that\n",
"E = 150 //in N/C\n",
"d = -520 //in meter\n",
"\n",
"//Sample Problem 25-1\n",
"printf('**Sample Problem 25-1**\n')\n",
"W = E*(-e)*d\n",
"deltaU = -W\n",
"printf('The change in potential energy is %eJ', deltaU)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 25.3: Sample_Problem_3.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"exec('electrostatics.sci', -1)\n",
"\n",
"//Given that\n",
"d = 1.3 //in meter\n",
"q1 = 12*10^-9 //in C\n",
"q2 = -24*10^-9 //in C\n",
"q3 = +31*10^-9 //in C\n",
"q4 = 17*10^-9 //in C\n",
"\n",
"//Sample Problem 25-3\n",
"printf('**Sample Problem 25-3**\n')\n",
"V = EPotential(q1+q2+q3+q4, d/sqrt(2))\n",
"printf('The electric potential at point P is equal to %eV', V)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 25.4: Sample_Problem_4.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"exec('electrostatics.sci', -1)\n",
"\n",
"//Given that\n",
"n = 12\n",
"qT = -n*e\n",
"R = 1 //(say)\n",
"\n",
"//Sample Problem 25-4a\n",
"printf('**Sample Problem 25-4a**\n')\n",
"V = EPotential(qT, R)\n",
"printf('The electric potential at the center is equal to %e/R Volts', V)\n",
"\n",
"//Sample Problem 25-4b\n",
"printf('**Sample Problem 25-4b**\n')\n",
"printf('It does not change in this configuration')"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 25.6: Sample_Problem_6.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"exec('electrostatics.sci', -1)\n",
"\n",
"//Given that\n",
"d = 12*10^-2 //in cm\n",
"q = 150*10^-9 //in C\n",
"q1 = +q\n",
"q2 = -4*q\n",
"q3 = +2*q\n",
"\n",
"//Sample Problem 25-6\n",
"printf('**Sample Problem 25-6**\n')\n",
"U = EPotential(q1, d)*q2 + EPotential(q2, d)*q3 + EPotential(q3, d)*q1\n",
"printf('The electric potential energy of the system is equal to %eJ', U)"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Scilab",
"language": "scilab",
"name": "scilab"
},
"language_info": {
"file_extension": ".sce",
"help_links": [
{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
}
],
"mimetype": "text/x-octave",
"name": "scilab",
"version": "0.7.1"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
