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authorSiddharth Agarwal2019-09-03 18:27:40 +0530
committerSiddharth Agarwal2019-09-03 18:27:40 +0530
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+
+// ELECTRICAL MACHINES
+// R.K.Srivastava
+// First Impression 2011
+// CENGAGE LEARNING INDIA PVT. LTD
+
+// CHAPTER : 4 : DIRECT CURRENT MACHINES
+
+// EXAMPLE : 4.16
+
+clear ; clc ; close ; // Clear the work space and console
+
+
+// GIVEN DATA
+
+Out_hp = 20; // Output of the Motor in HP
+eta = 90/100; // Full load efficiency of the Motor
+V = 220; // Motor voltage in Volts
+ns = 5; // Number of the step of Starter
+Rf = 220; // Field Resistance in Ohms
+cr = 1.8; // Lowest Current rating is 1.8 times of the Full load current
+Cu = 5/100; // Total Copper loss is 5% of the Input
+
+
+// CALCULATIONS
+
+Out = 20 * 746; .. // Output of the Motor in Watt
+Inp = (Out/eta); // Input of the Motor in KiloWatt
+I = Inp/Rf; // Full-Load Current in Amphere
+Cu_l = Inp*Cu; // Total Copper loss in Watts
+olf = (V ^ 2)/Rf; // Ohmic loss in the Fiels in the Watts
+Acu = Cu_l - olf; // Armature Copper loss in Watts
+Ra = Acu/(I * I); // Armature Resistance in Ohms
+I2 = I * cr; // Lower Current in Amphere
+n = ns - 1; // Number of the Resistance
+gama = ( (I2 * Ra)/Rf ) ^ (1/(n + 1)); // Current Ratio
+I1 = I2/gama; // Initial Current in amphere
+R1 = V/I1; // Initial Resistance in Ohms
+R2 = gama * R1; // Initial Resistance in Ohms
+r1 = R1 - R2; // Graded Resistance in Ohms
+R3 = gama * R2; // Initial Resistance in Ohms
+r2 = gama * r1; // Graded Resistance in Ohms
+r3 = gama ^ 2 * r1; // Graded Resistance in Ohms
+r4 = gama ^ 3 * r1; // Graded Resistance in Ohms
+
+
+// DISPLAY RESULTS
+
+disp("EXAMPLE : 4.16 : SOLUTION :-") ;
+printf("\n (a) Graded Resistances are %.4f Ohms, %.4f Ohms, %.4f Ohms and %.4f Ohms \n",r1,r2,r3,r4);