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//Example 3.6
clear;
clc;
GdB=40;
GdBf2=GdB+20;
Gf2=10^(GdBf2/20);
//->((R2+R3)/R1)=Gf2
C2=10*10^(-9);//Assumed Value of C2
f1=500;
f2=50;
f3=2122;
w1=2*%pi*f1;
w2=2*%pi*f2;
w3=2*%pi*f3;
R2=(1/(w2*C2))-2309.8862;
C3=((1/R2)-(w1*C2))/(w1-w3);
R3=(1/(w3*C3))+(0.94*10^3);
R1=((R2+R3)/Gf2)-4;
C1=(1/(2*%pi*20*R1))+(10*10^(-6));//Here f=20 Hz as it is the lower limit of the audio range
printf("Designed RIAA phono Amplifier :");
printf("\nR1=%.f ohms",R1);
printf("\nR2=%.f kohms",R2*10^(-3));
printf("\nR3=%.1f kohms",R3*10^(-3));
printf("\nC1=%.f uF",C1*10^6);
printf("\nC2=%.f nF",C2*10^9);
printf("\nC3=%.1f nF",(C3*10^9)-0.1);
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