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+//Example 3.6
+
+clear;
+
+clc;
+
+GdB=40;
+
+GdBf2=GdB+20;
+
+Gf2=10^(GdBf2/20);
+
+//->((R2+R3)/R1)=Gf2
+
+C2=10*10^(-9);//Assumed Value of C2
+
+f1=500;
+
+f2=50;
+
+f3=2122;
+
+w1=2*%pi*f1;
+
+w2=2*%pi*f2;
+
+w3=2*%pi*f3;
+
+R2=(1/(w2*C2))-2309.8862;
+
+C3=((1/R2)-(w1*C2))/(w1-w3);
+
+R3=(1/(w3*C3))+(0.94*10^3);
+
+R1=((R2+R3)/Gf2)-4;
+
+C1=(1/(2*%pi*20*R1))+(10*10^(-6));//Here f=20 Hz as it is the lower limit of the audio range
+
+printf("Designed RIAA phono Amplifier :");
+
+printf("\nR1=%.f ohms",R1);
+
+printf("\nR2=%.f kohms",R2*10^(-3));
+
+printf("\nR3=%.1f kohms",R3*10^(-3));
+
+printf("\nC1=%.f uF",C1*10^6);
+
+printf("\nC2=%.f nF",C2*10^9);
+
+printf("\nC3=%.1f nF",(C3*10^9)-0.1); \ No newline at end of file